Does anyone know what does it mean, when a nitrogen buffer tank capacity is written as 6000nM3?
Trying to size the Nitrogen Buffer Tank, but i don't know what it means by that capacity.
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Posted 01 February 2008 - 03:14 AM
Neelrahs2006,
In my opinion, "6000nM3" is referring to 6000 m3 of gas at NORMAL condition.
You may read this article for definition of STANDARD & NORMAL (Click HERE) *
As you can see, the definition of STANDARD & NORMAL is different from organisations, field, discipline, project, etc...You have to look for the definition in you case.
* http://en.wikipedia.org/wiki/Standard_cond...re_and_pressure
In my opinion, "6000nM3" is referring to 6000 m3 of gas at NORMAL condition.
You may read this article for definition of STANDARD & NORMAL (Click HERE) *
As you can see, the definition of STANDARD & NORMAL is different from organisations, field, discipline, project, etc...You have to look for the definition in you case.
* http://en.wikipedia.org/wiki/Standard_cond...re_and_pressure
JoeWong
Chemical & Process Technology
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Chemical & Process Technology
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Posted 25 September 2008 - 10:32 PM
QUOTE (Neelrahs2006 @ Feb 29 2008, 05:33 PM) <{POST_SNAPBACK}>
Thanks for the info. 
HI, continue to above question. I just want to clarify that, if i want to design a gas buffer tank to supply 5500 Nm3/hr for 60 barg to 30 barg. Is that i find the normalize tank volume?
P1*V1/T1 = P2*V2/T2
1.0133*V1/273.15 = 61.0133*5500/303.15
V1 = 298296 m3
P1*V1/T1 = P2*V2/T2
1.0133*V1/273.15 = 31.0133*5500/303.15
V1 = 151676 m3
to determine the size of the tank,
298296 - 151676 = 146620 m3?
Will it be very large?
Posted 26 September 2008 - 12:45 AM
sabahboyz,
It would have been better if you had started a new thread.
Your calculations don't make sense. Did you do an analysis of the units on both sides of the = sign?
What is missing from your problem description is the required buffer time. Let's assume you need 6 minutes of buffer time.
Rule of thumb approach:
You have 30 bar to play with. Now this roughly means that every m3 of buffer vessel will provide you 30 Nm3 of buffer volume. You need 5500 Nm3/hr * 6 minutes / 60 minutes/hr = 550 Nm3. So you need 550 Nm3 / 30 Nm3/m3 vessel = 18.33 m3.
Now this is only a rough estimation but I am quite sure you will be fine with 19 m3 of vessel.
The detailed calculation procedure for air and nitrogen buffer vessels has been discussed before on this forum --> use the SEARCH button.
It would have been better if you had started a new thread.
Your calculations don't make sense. Did you do an analysis of the units on both sides of the = sign?
What is missing from your problem description is the required buffer time. Let's assume you need 6 minutes of buffer time.
Rule of thumb approach:
You have 30 bar to play with. Now this roughly means that every m3 of buffer vessel will provide you 30 Nm3 of buffer volume. You need 5500 Nm3/hr * 6 minutes / 60 minutes/hr = 550 Nm3. So you need 550 Nm3 / 30 Nm3/m3 vessel = 18.33 m3.
Now this is only a rough estimation but I am quite sure you will be fine with 19 m3 of vessel.
The detailed calculation procedure for air and nitrogen buffer vessels has been discussed before on this forum --> use the SEARCH button.
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