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Converting From Kg-mol/hour To M3/hour


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#1 Guest_Guest_*

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Posted 06 February 2005 - 10:13 AM

Hello

I'm given a gas at a certain T,P and flowrate in kg-mol/hour
I must convert this to m3/hour

I think :

kgmol/hour * (RT/P) where RT/P = V/n = m3/kmol

would give me the correct units.

Is this correct ? are kmol = kgmol ?

Thanks!

#2 mbeychok

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Posted 06 February 2005 - 03:37 PM

For any ideal gas, 1 kg-mol = 22.414 m3 at 0 °C and 1 atmosphere. Thus:

(Equation 1)   m3/hr at 0 °C and 1 atmosphere = (22.414) ( kg-mol/hr )

To convert m3/hr at 0 °C and 1 atmosphere to m3/hr at any other T and P, use:

(Equation 2)   P1V1/T1 = P2V2/T2

In using Equation 2, be sure to use absolute pressures and absolute temperatures (°K or °R). In some cases where there is a large difference between conditions 1 and 2, you may need to use compressibility factors (Z) in Equation 2. Thus:

(Equation 3)   P1V1/(Z1T1) = P2V2/(Z2T2)

#3 Guest_Guest_*

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Posted 06 February 2005 - 10:04 PM

QUOTE (Guest @ Feb 6 2005, 10:13 AM)
Hello

I'm given a gas at a certain T,P and flowrate in kg-mol/hour
I must convert this to m3/hour

I think :

kgmol/hour * (RT/P) where RT/P = V/n = m3/kmol

would give me the correct units.

Is this correct ? are kmol = kgmol ?

Thanks!

Just to add a little to 'are kmol = kgmol'......

That is correct if you are working in SI units - all you are saying is that you are measuring molecular weights in kg/kmol.

You can also find lb-moles.




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