|
|
2 replies to this topic
Share this topic:
#1
Posted 07 March 2012 - 09:41 AM
Please can someone help me with this problem. Its a topic under sustainability energy processes. I have attached the question. Looking forward to your response. Thanks
#2
Posted 07 March 2012 - 03:46 PM
Hi Natasha,
Please be specific, which part of assignment you are not able to do. Attach your calculation worked copy, then we might able to help you.
Regards
Shivshankar
Please be specific, which part of assignment you are not able to do. Attach your calculation worked copy, then we might able to help you.
Regards
Shivshankar
#3
Posted 08 March 2012 - 10:01 AM
Hi Natasha,
Part 1 ( Use all parameters (Data) given)
Q1. (i) First you calculate the power generation in Watts, then you multiply with generating period then you get the dialy energy generation.
Power Generation in Watts (P) =(Density of water (Rho)*Acceleration due to gravity (g)*Volumetric generating flow rate(Vt)*(Operated head between lower and upper reservoir(H)- Head loss of Water pipe(L))*Efficeicy(E)) watts.
Here Efficiency(E)=Generating efficiency(ng) times Turbine efficiency(nt).
The daily energy generation=generating period*above calculated power (Watts Hours/day)
This will be your energy output.
ii) Calculate same way the daily energy consumption for the pump( first calculate power and then energy consumption).
Power Generation in Watts (P) =(Density of water (Rho)*Acceleration due to gravity (g)*Volumetric generating flow rate(Vp)*(Operated head between lower and upper reservoir(H)- Head loss of Water pipe(L))*Efficeicy(E)) watts.
Here Efficiency(E)=Pump efficiency(np) times Motor efficiency(nm).
The daily energy consumption by pump=Pumping period* Power generation (Watts Hours/day)
Now
Here you calculate Energy input.
iii) Turn around efficiency= Turbine -Generatoor Energy / Pump-Motor energy (Percentage)
Note: Use head loss in water 5 % (while calculating)
Q2) let me know if you can solve this?
Part 2 is easy you can do yourself?
I hope this will help you, If i mistook somewhere please let me know.
Regards
Shivshankar
Part 1 ( Use all parameters (Data) given)
Q1. (i) First you calculate the power generation in Watts, then you multiply with generating period then you get the dialy energy generation.
Power Generation in Watts (P) =(Density of water (Rho)*Acceleration due to gravity (g)*Volumetric generating flow rate(Vt)*(Operated head between lower and upper reservoir(H)- Head loss of Water pipe(L))*Efficeicy(E)) watts.
Here Efficiency(E)=Generating efficiency(ng) times Turbine efficiency(nt).
The daily energy generation=generating period*above calculated power (Watts Hours/day)
This will be your energy output.
ii) Calculate same way the daily energy consumption for the pump( first calculate power and then energy consumption).
Power Generation in Watts (P) =(Density of water (Rho)*Acceleration due to gravity (g)*Volumetric generating flow rate(Vp)*(Operated head between lower and upper reservoir(H)- Head loss of Water pipe(L))*Efficeicy(E)) watts.
Here Efficiency(E)=Pump efficiency(np) times Motor efficiency(nm).
The daily energy consumption by pump=Pumping period* Power generation (Watts Hours/day)
Now
Here you calculate Energy input.
iii) Turn around efficiency= Turbine -Generatoor Energy / Pump-Motor energy (Percentage)
Note: Use head loss in water 5 % (while calculating)
Q2) let me know if you can solve this?
Part 2 is easy you can do yourself?
I hope this will help you, If i mistook somewhere please let me know.
Regards
Shivshankar
Similar Topics
Hydro-Processing Pump Trip Backflow Prevention Design And Process SafeStarted by Guest_VeryProfessionalEngineer_* , 14 Jun 2018 |
|
|
||
Asme Hydro Test PressureStarted by Guest_libn999_* , 11 Apr 2018 |
|
|
||
Hydro SkimmerStarted by Guest_titim_* , 05 Dec 2017 |
|
|
||
Specifications Requirements For Hydro-Cracking ProcessStarted by Guest_Atif1730_* , 23 Aug 2017 |
|
|
||
Rg Compressor Flow Issue In Hydro Processing Unit.Started by Guest_Sonu Kumar Balaraman_* , 13 Jan 2017 |
|
|

FB






