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#1
Posted 17 September 2012 - 07:23 AM
Hallo fellow aspiring engineers/ engineers... I will like to know how to go about removing a quantity of water that is present in our reformer tubes; inasmuch as the tube is 52 ft and we have used a horse attached to a pump to remove 35ft=10.6 meters (the maximum amount of water that the siphon mechanism by which pumps operate can allow) the remaining 17 ft cannot be pumped out. We have taking the injection of nitrogen to pressurized the water out as one of our solutions..PLEASEEEEEE WHATEVER YOUR IDEA AS PER WHAT THE SOLUTION CAN BE HOW EVER SMALL WILL BE SUBLIMELY APPRECIATED. I HAVE ATTACHED A DRAWING TO GUIDE YOUR BRAINSTORMING. THANKS.
#2
Posted 17 September 2012 - 08:18 AM
What shape and size are the tubes?
Edited by latexman, 17 September 2012 - 08:18 AM.
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