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Extraction Of Copper From Copper Ore (Extraction Solid-Liquid)

extraction

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#1 rectification24

rectification24

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Posted 07 August 2014 - 02:08 PM

Hey,

 

can someone please help me? I have one problem that I have to solve, but unfortunately I don't know if my result is correct.

Could someone please look at my work and tell me if I did any mistake? 

I would be very grateful for any help.

 

Regards,

Filip

 

Description of my problem could be seen here and solution down under:

 

Roasted copper ore containing the copper as CuSO4 is to be extracted in a counter-current 
stage extractor. Charge consists of 10 tons of inert solids, 2 tons of 
copper sulfate (CuSO4), and 0.5 ton of water. The strong solution produced is to 
consist of 90% H2O and 10% CuSO4 by weight. The recovery of CuSO4 is to be 98% of 
that in the ore. Pure water is to be used as the fresh solvent. After each stage, 1 ton of 
inert solids retains 2 tons of water plus the copper sulfate dissolved in that water. 
Equilibrium is attained in each stage. How many stages are required? 
 

 

2 t CuSO4....................100%                                                       1.96t....................10%

      x       ......................98%                                                             x........................90%

                                         

x=1.96 t CuSO4                                                                                                                     x=17.64 t H2O

 

extract:   1.96 t CuSO4/17.64 t H2O = 1.12 t CuSO4/10 t H2O

 

raffinate:

 

0.04 t CuSO4/10 t inert solid

 

As base we define 10 t of inert solid (without H2O and CuSO4)

 

CuSO4 in: 2 t 

 

CuSO4 out:

 

0.04 +(1.12 /(1.12 +10) *(S-20+0.5)) = 0.101*S - 1.924

 

 

CuSOin = CuSO4 out

 

2 = 0.101*S - 1.924

 

S = 38.85 t H2O  (amount of solvent)

 

 

y= ((20*1.12/(1.12+10)) + (1.12/(1.12+10)*(38.85-20+0.5)) - 2 ) / 38.85

ya = 0.0505

 

yb = 0

 

ya* = 1.12/(1.12+10) = 0.101

 

yb* = 0.04/20 = 0.002

 

Number of stages:

 

N=log(y- yb*/(ya-ya*)) / log(yb-ya/(yb*- ya*))

 

N=4.8=5

 

 

 

 

 

 

              



#2 breizh

breizh

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Posted 08 August 2014 - 03:21 AM

Hi ,

My calculation , different from yours !  

Breizh

 

 

 

Ya 0.1 Yb 0 Xa =Ya* 0.16 Xb=Yb* 0.001332     N 8.248054

Edited by breizh, 08 August 2014 - 03:24 AM.


#3 rectification24

rectification24

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Posted 08 August 2014 - 12:38 PM

Could you please send me your calculations that I will be able to see what I did wrong?

 

Filip

 

 

 

Hi ,

My calculation , different from yours !  

Breizh

 

 

 

Ya 0.1 Yb 0 Xa =Ya* 0.16 Xb=Yb* 0.001332     N 8.248054

 



#4 breizh

breizh

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Posted 09 August 2014 - 08:28 AM   Best Answer

Hi ,

 

Consider my excel sheet ! Nothing granted.

 

Breizh



#5 rectification24

rectification24

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Posted 10 August 2014 - 08:39 AM

Thanks a lot.

 

Filip

 

Hi ,

 

Consider my excel sheet ! Nothing granted.

 

Breizh






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