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Evaporation Rate As Per Api 2000


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#1 Nagarajan K

Nagarajan K

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Posted 13 August 2014 - 01:10 AM

Dear All,

 

I am bit confused with Evaporation rate calculation method mentioned in API 2000.

 

As per Clause, In Annex-A, A.3.2.3, 2nd last Paragraph.

 

What Exactly does it says,

 

I carried out calculation as follows.

 

My incoming flow rate is 112 m3/hr at 45 deg C. 

 

Density of Liquid is 985 kg/me at 45 Deg C.

 

So may Mass flow is 110320 kg/hr.

 

Evaporation rate of 0.5 %, So evaporation mass flow rate is  0.005 * 110320 = 551.6 kg/hr.

 

Next say Density of Air is 1.29 kg/m3 at 45 deg C.

 

(As per 2nd last statement of 2nd last paragraph).

 

HC vapor density is 1.5 times of Air Density = 1.5 * 1.29 = 1.935 kg/m3

 

So my evaporation rate is 551.6/1.935 kg/m3

 

Evaporation rate = 285.06 m3/hr @ 45 deg C.

 

Evaporation rate in Nm3/hr is = 245 nm3/hr.

 

Am i Correct .

 

I have a Doubt.

 

Regards,

 

Nagarajan K

 

 

 

 

 



#2 breizh

breizh

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Posted 13 August 2014 - 01:16 AM

Hi ,

You need to define the meaning of Nm3 . It's not at 45 C and then you perform adjustment based on your reference ( 0C or 60F or ??)  using the general equation : P1*V1/T1 =P2*V2/T2.

 

Hope this helps

 

Breizh


Edited by breizh, 13 August 2014 - 01:19 AM.


#3 Nagarajan K

Nagarajan K

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Posted 13 August 2014 - 01:44 AM

Dear Breizh,

 

The approx flow rate calculated for 245 Nm3/hr from actual flow rate of 285.06 Nm3/hr using P1V1/T1=P2V2/T2.

 

Regards,

 

Nagarajan K



#4 ankur2061

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Posted 13 August 2014 - 01:49 AM

Nagarajan,

 

Refer the link below ans specifically post #28  by latexman.

 

http://www.cheresour...ervative/page-2

 

Regards,

Ankur.



#5 Nagarajan K

Nagarajan K

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Posted 13 August 2014 - 02:40 AM

Dear All,

 

I followed d same conversion but,is the method correct to find out Evaporation rate?

 

Regards,

 

Nagarajan K






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