Jump to content



Featured Articles

Check out the latest featured articles.

File Library

Check out the latest downloads available in the File Library.

New Article

Product Viscosity vs. Shear

Featured File

Vertical Tank Selection

New Blog Entry

Low Flow in Pipes- posted in Ankur's blog

Exhaust Gas From Burning - Calculation


This topic has been archived. This means that you cannot reply to this topic.
2 replies to this topic
Share this topic:
| More

#1 gajus21

gajus21

    Brand New Member

  • Members
  • 6 posts

Posted 03 March 2015 - 04:49 AM

Hallo

I have another question:

 I need to calculate how many of gases (m3/hr) we recive from burning:

450 000 Nm3/hr

 

H2  [mol/ mol]  3,064

CO  24,296

CH4  0,035

C2H4  0,000

C2H6  0,000

C3H6  0,000

C2H2  0,000

CO2  17,768

N2  53,874

O2  0,963

Suma mol/ mol100,0

 

 

I have done this with two ways:

1) V=0,210*(Q/1000) - This is a theoretical equation  and I received

 

Nm3/h

2 266 081

 

 

2) Vos=Vco2+Vso2+Vh2o+Vn2

Vco2=CO2+CO+CH4+2C2H2+2C2H4

Vh20=H20+H2+cCH4+2C2H4+C2H2

VN2=N2+0,79*(1/21(H2/2+CO/2+2CH4+2C2H4-O2)


and i received

     1 206 678   

 

 

And mine question is why there is so much different? In publication which I have used this equation there is not so much problem, could someone give my some advice form where (publication) I can find some good information about it or a little help which this.


Edited by gajus21, 03 March 2015 - 04:58 AM.


#2 Bobby Strain

Bobby Strain

    Gold Member

  • Members
  • 3,529 posts

Posted 03 March 2015 - 10:57 AM

Like all good chemical engineers you should do a heat and material balance.

 

Bobby



#3 gajus21

gajus21

    Brand New Member

  • Members
  • 6 posts

Posted 04 March 2015 - 01:56 AM

Thank You Bobby very helpful,






Similar Topics