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#1 geo123

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Posted 04 July 2015 - 08:42 AM

A geothermal plant pumps water at 15 degrees celsius into the ground. The water travels through the pipes underground before returning to the surface at a temperature of 90 degrees celsius. If the efficiency of the plant is 10%, how much water must be pumped into the ground every second for the plant to generate 1MW of power?

 

 



#2 geo123

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Posted 04 July 2015 - 09:06 AM

I used Q=cm(deltaT)

and

n=W/(Q1)

 

Q=energy input

W=work done of the engine

n=efficiency

c=energy gained per second

delta T= temperature difference

m=mass flow rate



#3 geo123

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Posted 04 July 2015 - 09:28 AM

(Q1)=1MW/0.1=10MW

m=(deltaQ)/c*(deltaT)=(10^4kW/(4.2kJ/kg*K))*(75K)=1.79*10^5kg/s



#4 geo123

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Posted 04 July 2015 - 09:29 AM

I want to know if I've done it right or wrong?


Edited by geo123, 04 July 2015 - 09:29 AM.


#5 breizh

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Posted 05 July 2015 - 01:40 AM

geo 123,

 

Redo the math :should be 31.89 kg/s   ;Q=m*cp*dt >>> m =Q/(cp*dt)

 

Breizh


Edited by breizh, 05 July 2015 - 05:40 AM.


#6 Art Montemayor

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Posted 05 July 2015 - 03:58 PM

Geo123:

 

Stop making multiple postings of the same topic - especially in different Forums.

 

READ THE FORUM GUIDELINES.  If you persist, I'll have to take remedial action that won't sit well with you.

 

Thank you.



#7 geo123

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Posted 11 July 2015 - 08:10 PM

I'm sorry about this and I will not make anymore multiple postings of the same topic - especially in different Forums.

Thanks for the help.






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