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Fluid Dynamics
#1
Posted 07 October 2015 - 09:55 AM
#2
Posted 07 October 2015 - 10:11 AM
The balance at the x-coordinate is
rhoe*v1*A1=rhoe*v2*A2=mass flow rate.
0=-rhoe*v1A1(V-vj)+Fx
F(x)=mdV/dt=rhoe(vj-V)A1vj
d(mV)/dt=rhoe(vj-V)A1vj
Integral of d(mV)=integral of rhoe*(vj-V)A1vjdt
(m0+rhoe(vj-v)at)V(t)=rhoe(vj-V)A1vjt
m0V(t)=(rhoe(vj-V)A1vj-V(t)rhoe(vj-V)t
It leads to a dead end after this as I differentiated V with respect to time.
Then I integrated dV from 10 to 20 and integrated (rhoe(vj-V)A1vj-V(t)rhoe(vj-V))[t]/m0 from 0 to an arbitrary t
Edited by geo123, 07 October 2015 - 10:29 AM.
#3
Posted 07 October 2015 - 10:18 AM
Do you expect our Forum members to do your homework assignments for you?
If so, what work input have you done on this assignment up to now? Please show ALL the work you have done in trying to solve this problem. If you have not done any work on this effort, then you can't be expecting "help". What you are expecting is someone to do your work for you.
Also, please stop posting duplicate threads of the same topic. I deleted your other duplicate posting.
#4
Posted 07 October 2015 - 10:22 AM
m0= the initial mass of the moving vehicle with water in it.
V=velocity of the moving vehicle plus water.
vj=velocity of the jet of water.
#5
Posted 07 October 2015 - 10:31 AM
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