I need to do sizing of RD/PSV on tube rupture case at shell & tube heat exchanger. There is no chance of flashing due to tube rupture and both side contain liquids. The details are as follows:
Shell Side Design Pressure = 19 kg/cm2.g
Shell Side Operating Pressure = 15 kg/cm2.g
Tube Side Design Pressure = 10 kg/cm2.g
Tube Side Operating Pressure = 7 kg/cm2.g
As per API-521, “relieving rate is to be the liquid flowing across a rupture equal to twice the cross-sectional area of one tube.” (Correct me if I am wrong).
So Flow Area, A = 2 * Cross sectional Area of tube
A= 2 * ( ∏ /4 * d^2)
Now
Liquid Flow = 1685 A * SQRT (∆P * Density)
d = Inside dia of tube = 14.8 mm
P1 = Rupture’s upstream pressure of fluid = 15 kg/cm2.g
P2 = Rupture’s upstream pressure of fluid = 7 kg/cm2.g I consider max. operating pressure for P 1 & P2.
Density = 913 kg/m3
Therefore, So by using above two equations, I got following values;
Liquid flow = 33.3 tons/hr or 36.5 m3/hr
Appreciate if anyone can verify the methodology being adopted & guide about the way forward.
Regards
Edited by Ankit_Kumar, 12 January 2016 - 08:58 AM.