I am sorry for posting the question incorrectly. Here is the correct question.
Liquid ammonia is fed to a storage tank at the rate of 100833kg/hr at -33 deg C at 3.5 kg/cm2 G pressure.
How much is the vapor formed in kg/hour?
Specs for strorage tank.
Volume = 17145 m3
Storage Temp. = -33 deg C
Storage press. = 0.02 kg/cm2 forl liquid but can assume loss of 15mbar for vapour formation.
No heat ingress.
All the feed is getting stored
a.Tank is closed
b. Vapours are taken out.
I tried to solve it the following way.
Hl1=Hl2+Hv2.........................................(1)
hl1 = 50.55 kJ/kg at p = 3.5 kg/cm2 G
hl2 = 50.22 kJ/kg at p = 0.02 kg/cm2 G
hv2 = 1429.92 kJ/kg at p = (0.02-0.15mbar) kg/cm2 G
Assuming vapour formation rate to be x and solving equation (1), I get my answer of vapor formation rate to be 24.12 kg/hr.
Please let me know whether I am correct or not.
Thanks
Edited by Prashkrans, 03 June 2016 - 02:14 AM.