4 replies to this topic

[Steve Goch]

I mix two fliuds or gases(e.g monoatomic gas say Helium ) intially at different tanks with different temperatures. How can I obtain the resulting mixture temperaure? If there be a simple equation...that can do me help.

Thanks in advance

Edited by Steve Goch, 15 August 2009 - 03:32 AM.

[latexman]

There may be a simple solution, but you did not give us much to go on. With the limited information given all I can do is refer you to your ChE text on mass and energy balances. With some more information the problem might get simpler. What sre the two fluids? What is the temperature of the two fluids? Are the fluids mixed "in-line" or in a closed vessel?

[chau]

There may be a simple solution, but you did not give us much to go on. With the limited information given all I can do is refer you to your ChE text on mass and energy balances. With some more information the problem might get simpler. What sre the two fluids? What is the temperature of the two fluids? Are the fluids mixed "in-line" or in a closed vessel?

Dera Latexman

Taking part on this thread i , have a same query to ask .

What will be the resultant temp of below two steam after mixing it

1) Steam at 17 Bar 340 DEG C

2) Steam at 17 Bar 310 DEG C

[latexman]

chau,

Both stream 1 and stream 2 are superheated steam. Heat capacity of each stream will be essentially equal. I would use a simple arithmatic average weighted by the proportions of each stream. You did not provide information on the proportions. If equal quantities of each are mixed (50% each), than the resultant T = 340(0.5) + 310(0.5) = 325 C. It doesn't get much simpler than this.

[Steve Goch]

chau,

Both stream 1 and stream 2 are superheated steam. Heat capacity of each stream will be essentially equal. I would use a simple arithmatic average weighted by the proportions of each stream. You did not provide information on the proportions. If equal quantities of each are mixed (50% each), than the resultant T = 340(0.5) + 310(0.5) = 325 C. It doesn't get much simpler than this.

I realised that my question was incomplete. I have to thank you all for your efforts. I have found the answer to my question from some book. It helped.