<?xml version="1.0" encoding="UTF-8" ?>
<rss version="2.0">
<channel>
	<title>Fluid Flow - Articles</title>
	<link>http://www.cheresources.com/content/articles/fluid-flow/</link>
	<pubDate>Fri, 24 Apr 2026 02:52:22 +0000</pubDate>
	<ttl>86400</ttl>
	<description></description>
	<item>
		<title>Product Viscosity Versus Shear</title>
		<link>http://www.cheresources.com/content/articles/fluid-flow/product-viscosity-versus-shear</link>
		<description><![CDATA[<p>We were concerned when a client stated that their product has a viscosity of 2000 to 3000 cP. How could we pump this material from the manufacturing tank to the filling line? Luckily, we had a plant and resources to conduct a full-scale test. The objective of the test was to pump a &ldquo;placebo product&rdquo; (one that had all of the viscosity building materials but none of the active ingredients) from one tank to another. We hoped to analyze data from the test and determine the &ldquo;apparent viscosity&rdquo; of the placebo, then compare that with laboratory measurements.</p>
<p>Two flow tests were conducted. Placebo product (a suspension with no active ingredient, target viscosity of 2500 cP) was pumped from a Manufacturing Tank to a Receiver. Here are the observed results:</p>
<table align="center" border="0" class="datatable">
	<caption>
		Table 1: Sample Data</caption>
	<tbody>
		<tr>
			<td>
				<b>Parameter</b></td>
			<td>
				<b>Test 1</b></td>
			<td>
				<b>Test 2</b></td>
		</tr>
		<tr>
			<td>
				Pump Speed</td>
			<td>
				30%</td>
			<td>
				40%</td>
		</tr>
		<tr>
			<td>
				Temperature</td>
			<td>
				35 C</td>
			<td>
				34 C</td>
		</tr>
		<tr>
			<td>
				Flow rate, based on load cells</td>
			<td>
				220 kg/min</td>
			<td>
				160 kg/min</td>
		</tr>
		<tr>
			<td>
				Pressure at pump discharge</td>
			<td>
				125 kPa</td>
			<td>
				83 kPa</td>
		</tr>
		<tr>
			<td>
				Pressure at receiver</td>
			<td>
				28 kPa</td>
			<td>
				28 kPa</td>
		</tr>
	</tbody>
</table>
<p>The observed values, along with knowledge of the physical piping, can be used to calculate the &ldquo;apparent viscosity&rdquo; of the placebo product. The piping from the pump to the Hold Tank is 50 DN (47.5 mm inside diameter). It includes straight piping, elbows, 45&deg; bends, one divert valve and one diaphragm valve. The total equivalent length of this piping and valves is 85 m. Equivalent length is used to calculate pressure drop. The pressure gauge on the pump discharge is 1 meter higher than the one beneath the Receiver; the pressure drop due to friction is therefore P1 &ndash; P2 + 1 meter head, where P1 = pressure at pump discharge, and P2 = pressure beneath Receiver.</p>
<p><p class="h1header">Estimation of Apparent Viscosity</p></p>
<p>There are three steps to calculating the pressure drop due to friction through the pipe. The first step requires fluid viscosity as an input. To calculate the viscosity, initially assume a value, proceed through the three steps, and compare the calculated pressure drop with the observed results. Iterate by changing the viscosity assumption until the calculation and observed result match.</p>
<p>For these calculations, a value for the placebo product density must also be known. This wasn&rsquo;t measured, but plant operators stated that it is from 1.2 to 1.3; we calculated it to be 1.26.</p>
<p><p class="h2header">Step 1: Reynolds Number<sup>i</sup></p></p>
<table align="center" border="0" class="equationtable">
	<tbody>
		<tr>
			<td valign="top">
				<img alt="eq-1" src="http://www.cheresources.com/invision/uploads/images/articles/shear1.png" /></td>
			<td align="right" class="equationnumber">
				Eq. (1)</td>
		</tr>
	</tbody>
</table>
<p>&rho; = density of liquid, kg/m<sup>3</sup> or lb/ft<sup>3</sup><br />
D = pipe diameter, m or ft<br />
U = average fluid velocity, m/s or ft/s = G / &rho;<br />
G = mass flux, kg/s-m<sup>2</sup> or lb/s-ft<sup>2</sup> = W / (3600 A)<br />
A = cross-sectional area of pipe, m<sup>2</sup> or ft<sup>2</sup><br />
&mu; = fluid dynamic viscosity, Pa-s or lb/ft-h (1 cP = 2.42 lb/ft-h)</p>
<p><p class="h2header">Step 2: Friction Factor</p></p>
<table align="center" border="0" class="equationtable">
	<tbody>
		<tr>
			<td valign="top">
				<img alt="eq-2" src="http://www.cheresources.com/invision/uploads/images/articles/shear2.png" /></td>
			<td align="right" class="equationnumber">
				Eq. (2)</td>
		</tr>
	</tbody>
</table>
<p>Where:</p>
<table align="center" border="0" class="equationtable">
	<tbody>
		<tr>
			<td valign="top">
				<img alt="eq-3" src="http://www.cheresources.com/invision/uploads/images/articles/shear3.png" /></td>
			<td align="right" class="equationnumber">
				Eq. (3)</td>
		</tr>
	</tbody>
</table>
<table align="center" border="0" class="equationtable">
	<tbody>
		<tr>
			<td valign="top">
				<img alt="eq-4" src="http://www.cheresources.com/invision/uploads/images/articles/shear4.png" /></td>
			<td align="right" class="equationnumber">
				Eq. (4)</td>
		</tr>
	</tbody>
</table>
<p>&epsilon; = surface roughness, m or ft</p>
<p>Surface roughness is a piping characteristic. The limiting value is &ldquo;smooth,&rdquo; and defined to be 0.0000015 m or 0.000005 ft. For this calculation, use a value of 0.000002 m.</p>
<p><p class="h2header">Step 3: Pressure Drop Due to Friction</p></p>
<table align="center" border="0" class="equationtable">
	<tbody>
		<tr>
			<td valign="top">
				<img alt="eq-5" src="http://www.cheresources.com/invision/uploads/images/articles/shear5.png" /></td>
			<td align="right" class="equationnumber">
				Eq. (5)</td>
		</tr>
	</tbody>
</table>
<p>L = pipe equivalent length, m or ftg<sub>c</sub> = conversion factor, 1 m/s<sup>2</sup> or 32.17 ft/s<sup>2</sup></p>
<table align="center" border="0" class="datatable">
	<caption>
		Table 2: Calculation Results</caption>
	<tbody>
		<tr>
			<td>
				<b>Parameter</b></td>
			<td>
				<b>Test 1</b></td>
			<td>
				<b>Test 2</b></td>
		</tr>
		<tr>
			<td>
				Specific Gravity<sup>ii</sup></td>
			<td>
				1.26</td>
			<td>
				1.26</td>
		</tr>
		<tr>
			<td>
				Observed pressure drop</td>
			<td>
				110 kPa</td>
			<td>
				68 kPa</td>
		</tr>
		<tr>
			<td>
				Viscosity</td>
			<td>
				39 cP</td>
			<td>
				47 cP</td>
		</tr>
		<tr>
			<td>
				Calculated pressure drop</td>
			<td>
				110 kPa</td>
			<td>
				68 kPa</td>
		</tr>
	</tbody>
</table>
<p></p>
<p><p class="h1header">Viscosity Measurements</p></p>
<p>Pseudoplastic compounds follow a power curve, with viscosity decreasing with shear rate. Viscosity measurements were performed with a Brookfield Viscometer, Model LVDV-II+. Using the #31 spindle and Sample Adapter 13R cup, shear rate is determined by multiplying the rotational speed by 0.34<sup>iii</sup>. This gives the following raw data for the placebo product made for the tests:</p>
<table align="center" border="0" class="datatable">
	<caption>
		Table 3: Viscosity Measurements</caption>
	<tbody>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p1"><b>RPM</b></p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p1"><b>Viscosity (cP)</b></p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p1"><b>Torque (%)</b></p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p1"><b>Shear Rate, sec<sup>-1</sup></b></p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">0.5</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">8338</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">13.9</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">0.17</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">1.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">5159</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">17.2</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">0.34</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">1.5</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">3919</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">19.6</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">0.51</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">3.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">2449</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">24.6</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">1.02</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">6.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">1540</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">30.8</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">2.04</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">12.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">977.3</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">39.1</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">4.08</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">20.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">706.3</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">47.1</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">6.8</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">30.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">551.9</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">55.2</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">10.2</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">45.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">435.2</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">65.3</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">15.3</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">60.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">370.4</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">74.1</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">20.4</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">100.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">283.7</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">94.6</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">34</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="bottom">
				<p class="p2">150.0</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">EEEE</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p2">EEEE</p>
			</td>
			<td class="td1" valign="bottom">
				<p class="p3">&nbsp;</p>
			</td>
		</tr>
	</tbody>
</table>
<p>Measurements made at 25&deg;C</p>
<p>Here are the data charted in Excel with the trend line and trend line equation superimposed:</p>
<table align="center" border="0" class="imagecaption">
	<tbody>
		<tr>
			<td>
				<img alt="figure-1" src="http://www.cheresources.com/invision/uploads/images/articles/shear6.png" /></td>
		</tr>
		<tr>
			<td>
				Figure 1: Graph of Viscosity Data with Trend Line</td>
		</tr>
	</tbody>
</table>
<p>The power law equation for apparent viscosity is:</p>
<table align="center" border="0" class="equationtable">
	<tbody>
		<tr>
			<td valign="top">
				&mu;<sub>a</sub> = K &gamma;<sup>n-1</sup></td>
			<td align="right" class="equationnumber">
				Eq. (6)</td>
		</tr>
	</tbody>
</table>
<p>K = flow consistency index, Pa-s<em class="bbc">n</em> = flow behavior index, dimensionless</p>
<p>Viscosity is in units Pa-s. Since our data is in cP (=mPa-s), the values of K and n are 2.53 and 0.356.</p>
<p>The viscometer&rsquo;s measurement range is limited, but extrapolation is acceptable with decreased accuracy.</p>
<p>Using the trend line equation, the viscosity at any shear rate is estimated. But this is for a temperature of 25&deg;C. Since data at only one temperature is given, the Lewis and Squires temperature correlation is used to estimate the viscosity at the actual flowing condition.</p>
<table align="center" border="0" class="imagecaption">
	<tbody>
		<tr>
			<td>
				<img alt="figure-2" src="http://www.cheresources.com/invision/uploads/images/articles/shear7.png" /></td>
		</tr>
		<tr>
			<td>
				Figure 2: Lewis and Squires Temperature Correlation</td>
		</tr>
	</tbody>
</table>
<p>The equation for this chart is<sup>iv</sup>:</p>
<table align="center" border="0" class="equation">
	<tbody>
		<tr>
			<td valign="top">
				<img alt="eq-7" src="http://www.cheresources.com/invision/uploads/images/articles/shear8.png" /></td>
			<td align="right" class="equation">
				Eq. (7)</td>
		</tr>
	</tbody>
</table>
<p></p>
<p><p class="h1header">Shear Rate in Pipeline</p></p>
<p>The shear rate at the wall of a circular pipe is calculated with:</p>
<table align="center" border="0" class="equation">
	<tbody>
		<tr>
			<td valign="top">
				<img alt="eq-8" src="http://www.cheresources.com/invision/uploads/images/articles/shear9.png" /></td>
			<td align="right" class="equation">
				Eq. (8)</td>
		</tr>
	</tbody>
</table>
<p>And here are the results:</p>
<table align="center" border="0" class="datatable">
	<caption>
		Table 4: Viscosity Results</caption>
	<tbody>
		<tr>
			<td class="td1" valign="top">
				<p class="p1"><b>Parameter</b></p>
			</td>
			<td class="td1" valign="top">
				<p class="p2"><b>Test 1</b></p>
			</td>
			<td class="td1" valign="top">
				<p class="p2"><b>Test 2</b></p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="top">
				<p class="p1">Flow rate</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">220 kg/min</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">160 kg/min</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="top">
				<p class="p1">Density</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">1.26</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">1.26</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="top">
				<p class="p1">Pipe diameter</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">47.5 mm</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">47.5 mm</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="top">
				<p class="p1">Velocity</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">1.65 m/s</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">1.20 ft/s</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="top">
				<p class="p1">Shear rate</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">277 sec<sup>-1</sup></p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">202 sec<sup>-1</sup></p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="top">
				<p class="p1">Viscosity at 25&deg;C</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">68 cP</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">83 cP</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="top">
				<p class="p1">Corrected viscosity, 34&deg;C</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">42 cP</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">53 cP</p>
			</td>
		</tr>
		<tr>
			<td class="td1" valign="top">
				<p class="p1">Compare with calculation</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">39 cP</p>
			</td>
			<td class="td1" valign="top">
				<p class="p1">47 cP</p>
			</td>
		</tr>
	</tbody>
</table>
<p><p class="h1header">Discussion and Conclusions</p></p>
<p>After correction for shear rate and temperature, viscosity measurements from the Brookfield viscometer result in reasonably good estimates of pipeline pressure drop. It is important to ensure that the sample has reached the target temperature of 25&deg; before recording the reading.</p>
<p>The limitations in this study include:</p>
<ul>
<li>1. Pressure gauge reading accuracy due to the range of the instrument and the relatively small value being read.</li>
<li>2. Estimated placebo product density.</li>
<li>3. Unknown dependency of viscosity on the time of the applied shear stress. Further measurements with the Brookfield viscometer could be made to determine if there is a time dependency.</li>
</ul>
<p>&nbsp;</p>
<p><p class="h1header">References</p></p>
<p><sup>i</sup>Hall, S.M., Rules of Thumb for Chemical Engineers, Butterworth-Heinemann (2012)</p>
<p><sup>ii</sup>Specific gravity determined from the pump speed (40% x 449 rpm max) and capacity (0.96 l/rev). This gives volumetric flow rate. From the measured mass flow rate, the specific gravity is calculated. Results from the two flow tests were averaged to obtain a value of 1.26.</p>
<p><sup>iii</sup>Brookfield Engineering Labs, More Solutions to Sticky Problems, downloaded from http://www.brookfieldengineering.com/</p>
<p><sup>iv</sup>Poling, B.E., Prausnitz, J.M., O&rsquo;Connell, J.P., Properties of Gases and Liquids, Fifth Edition, McGraw-Hill (2001).</p>]]></description>
		<pubDate>Tue, 12 Feb 2013 18:12:31 +0000</pubDate>
		<guid isPermaLink="false">cc40d06ff0a16a793d066dbfa2917bab</guid>
	</item>
	<item>
		<title>Valve Sizing and Selection</title>
		<link>http://www.cheresources.com/content/articles/fluid-flow/valve-sizing-and-selection</link>
		<description><![CDATA[Sizing flow valves is a science with many rules of thumb that few people agree on.  In this article I'll try to define a more standard procedure for sizing a valve as well as helping to select the appropriate type of valve.  **Please note that the correlation within this article are for turbulent flow.<br />






<br />






<p class="h2header">Step #1: Define the System</p><br />






The system is pumping water from one tank to another through a piping system with a total pressure drop of 150 psi.  The fluid is water at 70 <sup>Â°</sup>F.   Design (maximum) flowrate of 150 gpm, operating flowrate of 110 gpm, and a minimum flowrate of 25 gpm.  The pipe diameter is 3 inches.  At 70 <sup>Â°</sup>F, water has a specific gravity of 1.0.<br />






<span style="color: #ff0000"><em>Key Variables:  Total pressure drop, design flow, operating flow, minimum flow, pipe diameter, specific gravity</em></span><br />






<br />






<p class="h2header">Step #2: Define a maximum allowable pressure drop for the valve</p><br />






When defining the allowable pressure drop across the valve, you should first investigate the pump.  {parse block="google_articles"}What is its maximum available head?  Remember that the system pressure drop is limited by the pump.  Essentially the Net Positive Suction Head Available (NPSHA) minus the Net Positive Suction Head Required (NPSHR) is the maximum available pressure drop for the valve to use and this must not be exceeded or another pump will be needed.  It's important to remember the trade off, larger pressure drops increase the pumping cost (operating) and smaller pressure drops increase the valve cost because a larger valve is required (capital cost).  The usual rule of thumb is that a valve should be designed to use 10-15% of the total pressure drop or 10 psi, whichever is greater.  For our system, 10% of the total pressure drop is 15 psi which is what we'll use as our allowable pressure drop when the valve is wide open (the pump is our system is easily capable of the additional pressure drop).<br />






<br />






<p class="h2header">Step #3: Calculate the valve characteristic</p><br />






<a class='resized_img' rel='lightbox[5bd513a277a408eabf2339bb28a06b75]' id='ipb-attach-url-4394-0-88502100-1776999142' href="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-92017000-1323182198.gif" title="valve1.gif - Size: 2.15KB, Downloads: 1062"><img src="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-92017000-1323182198_thumb.gif" id='ipb-attach-img-4394-0-88502100-1776999142' style='width:250;height:106' class='attach' width="250" height="106" alt="Attached Image: valve1.gif" /></a>
<br />






For our system:<br />






<a class='resized_img' rel='lightbox[5bd513a277a408eabf2339bb28a06b75]' id='ipb-attach-url-4395-0-88506500-1776999142' href="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-55048700-1323182210.gif" title="valve2.gif - Size: 1.14KB, Downloads: 874"><img src="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-55048700-1323182210.gif" id='ipb-attach-img-4395-0-88506500-1776999142' style='width:152;height:41' class='attach' width="152" height="41" alt="Attached Image: valve2.gif" /></a>
<br />






At this point, some people would be tempted to go to the valve charts or characteristic curves and select a valve.  Don't make this mistake, instead, proceed to Step #4!<br />






<br />






<p class="h2header">Step #4: Preliminary valve selection</p><br />






Don't make the mistake of trying to match a valve with your calculated Cv value.   The Cv value should be used as a guide in the valve selection, not a hard and fast rule.  Some other considerations are:<br />






<span style="color: #ff0000">a.  Never use a valve that is less than half the pipe size<br />






b.  Avoid using the lower 10% and upper 20% of the valve stroke.  The valve is much easier to control in the 10-80% stroke range.</span>{parse block="google_articles"}<br />






Before a valve can be selected, you have to decide what type of valve will be used (<strong>See the list of valve types later in this article</strong>).  For our case, we'll assume we're using an equal percentage, globe valve (equal percentage will be explained later).  The valve chart for this type of valve is shown below.   This is a typical chart that will be supplied by the manufacturer (as a matter of fact, it was!)<br />






<a class='resized_img' rel='lightbox[5bd513a277a408eabf2339bb28a06b75]' id='ipb-attach-url-4402-0-88529900-1776999142' href="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-27877800-1323182286.gif" title="valvechart.gif - Size: 43.65KB, Downloads: 6684"><img src="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-27877800-1323182286_thumb.gif" id='ipb-attach-img-4402-0-88529900-1776999142' style='width:250;height:122' class='attach' width="250" height="122" alt="Attached Image: valvechart.gif" /></a>
<br />






For our case, it appears the 2 inch valve will work well for our Cv value at about 80-85% of the stroke range.  Notice that we're not trying to squeeze our Cv into the 1 1/2 valve which would need to be at 100% stroke to handle our maximum flow.   If this valve were used, two consequences would be experienced:  the pressure drop would be a little higher than 15 psi at our design (max) flow and the valve would be difficult to control at maximum flow.  Also, there would be no room for error with this valve, but the valve we've chosen will allow for flow surges beyond the 150 gpm range with severe headaches!<br />






So we've selected a valve...but are we ready to order?  Not yet, there are still some characteristics to consider.<br />






<p class="h2header">Step #5: Check the Cv and stroke percentage at the minimum flow</p><br />






If the stroke percentage falls below 10% at our minimum flow, a smaller valve may have to be used in some cases.  Judgements plays role in many cases. For example, is your system more likely to operate closer to the maximum flowrates more often than the minimum flowrates?  Or is it more likely to operate near the minimum flowrate for extended periods of time.  It's difficult to find the perfect valve, but you should find one that operates well most of the time.  Let's check the valve we've selected for our system:<br />






<a class='resized_img' rel='lightbox[5bd513a277a408eabf2339bb28a06b75]' id='ipb-attach-url-4396-0-88510200-1776999142' href="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-89425100-1323182220.gif" title="valve3.gif - Size: 1.06KB, Downloads: 5329"><img src="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-89425100-1323182220.gif" id='ipb-attach-img-4396-0-88510200-1776999142' style='width:112;height:41' class='attach' width="112" height="41" alt="Attached Image: valve3.gif" /></a>
<br />






Referring back to our valve chart, we see that a Cv of 6.5 would correspond to a stroke percentage of around 35-40% which is certainly acceptable.  Notice that we used the maximum pressure drop of 15 psi once again in our calculation.  Although the pressure drop across the valve will be lower at smaller flowrates, using the maximum value gives us a "worst case" scenario.  If our Cv at the minimum flow would have been around 1.5, there would not really be a problem because the valve has a Cv of 1.66 at 10% stroke and since we use the maximum pressure drop, our estimate is conservative.   Essentially, at lower pressure drops, Cv would only increase which in this case would be advantageous.<br />






<p class="h2header">Step #6: Check the gain across applicable flowrates</p><br />






Gain is defined as:<br />






<a class='resized_img' rel='lightbox[5bd513a277a408eabf2339bb28a06b75]' id='ipb-attach-url-4397-0-88514300-1776999142' href="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-28581200-1323182232.gif" title="valve4.gif - Size: 1.17KB, Downloads: 918"><img src="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-28581200-1323182232.gif" id='ipb-attach-img-4397-0-88514300-1776999142' style='width:148;height:36' class='attach' width="148" height="36" alt="Attached Image: valve4.gif" /></a>
<br />






Now, at our three flowrates:<br />






Q<sub>min</sub> = 25 gpm<br />






Q<sub>op</sub> = 110 gpm<br />






Q<sub>des</sub> = 150 gpm<br />






we have corresponding Cv values of 6.5, 28, and 39.  The corresponding stroke percentages are 35%, 73%, and 85% respectively.  Now we construct the following table:<br />






<center><table border="1" width="64"><tbody><tr><td width="17%" align="center">Flow (gpm)</td><td width="16%" align="center">Stroke (%)</td><td width="28%" align="center">Change in flow (gpm)</td><td width="39%" align="center">Change in Stroke (%)</td></tr><tr><td width="17%" align="center">25</td><td width="16%" align="center">35</td><td width="28%" align="center" rowspan="2">110-25 = 85</td><td width="39%" align="center" rowspan="2">73-35 = 38</td></tr><tr><td width="17%" align="center">110</td><td width="16%" align="center">73</td></tr><tr><td width="17%" align="center">150</td><td width="16%" align="center">85</td><td width="28%" align="center" rowspan="2">150-110 = 40</td><td width="39%" align="center" rowspan="2">85-73 = 12</td></tr><tr><td width="33%" align="center" colspan="2"> </td></tr></tbody></table></center><br />






<span style="color: #ff0000">Gain #1 = 85/38 = 2.2<br />






Gain #2 = 40/12 = 3.3</span><br />






<br />






The difference between these values should be less than 50% of the higher value.<br />






0.5 (3.3) = 1.65 and 3.3 - 2.2 = 1.10.  Since 1.10 is less than 1.65, there should be no problem in controlling the valve.  Also note that the gain should never be less than 0.50.  So for our case, I believe our selected valve will do nicely!<br />






<p class="h2header">Other Notes</p><br />






Another valve characteristic that can be examined is called the choked flow.  The relation uses the FL value found on the valve chart.  I recommend checking the choked flow for vastly different maximum and minimum flowrates.  For example if the difference between the maximum and minimum flows is above 90% of the maximum flow, you may want to check the choked flow.   Usually, the rule of thumb for determining the maximum pressure drop across the valve also helps to avoid choking flow.<br />






<p class="h1header">Selecting a Valve Type</p><br />






When speaking of valves, it's easy to get lost in the terminology.  Valve types are used to describe the mechanical characteristics and geometry (Ex/ gate, ball, globe valves).  We'll use valve control to refer to how the valve travel or stroke (openness) relates to the flow:<br />






1.  Equal Percentage:  equal increments of valve travel produce an equal percentage in flow change<br />






2.  Linear:  valve travel is directly proportional to the valve stoke<br />






3.  Quick opening:  large increase in flow with a small change in valve stroke{parse block="google_articles"}<br />






<br />






So how do you decide which valve control to use?  Here are some rules of thumb for each one:<br />






1.  Equal Percentage (most commonly used valve control)<br />






a.  Used in processes where large changes in pressure drop are expected<br />






b.  Used in processes where a small percentage of the total pressure drop is permitted by the valve<br />






c.  Used in temperature and pressure control loops<br />






<br />






2.  Linear<br />






a.  Used in liquid level or flow loops<br />






b.  Used in systems where the pressure drop across the valve is expected to remain fairly constant (ie. steady state systems)<br />






<br />






3.  Quick Opening<br />






a.  Used for frequent on-off service<br />






b.  Used for processes where "instantly" large flow is needed (ie. safety systems or cooling water systems)<br />






<br />






Now that we've covered the various types of valve control, we'll take a look at the most common valve types.<br />






<br />






<p class="h2header">Gate Valves</p><div style="width:660px; float:left;"><div style="width:200px; float:left"><br />






<a class='resized_img' rel='lightbox[5bd513a277a408eabf2339bb28a06b75]' id='ipb-attach-url-4398-0-88517400-1776999142' href="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-09401200-1323182244.gif" title="valve5.gif - Size: 1.96KB, Downloads: 420"><img src="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-09401200-1323182244_thumb.gif" id='ipb-attach-img-4398-0-88517400-1776999142' style='width:128;height:250' class='attach' width="128" height="250" alt="Attached Image: valve5.gif" /></a>
</div><div style="width:460px; float:left;">Best Suited Control:  Quick Opening<br />






<br />






Recommended Uses:<br />






1.  Fully open/closed, non-throttling<br />






2.  Infrequent operation<br />






3.  Minimal fluid trapping in line<br />






<br />






Applications:  Oil, gas, air, slurries, heavy liquids, steam, noncondensing gases, and corrosive liquids<br />






<div style="width:230px; float:left"><br />






Advantages:<br />






1.  High capacity                              <br />






2.  Tight shutoff                              <br />






3.  Low cost                                  <br />






4.  Little resistance to flow</div><div style="width:230px; float:left"><br />






Disadvantages:<br />






1. Poor control<br />






2. Cavitate at low pressure drops<br />






3. Cannot be used for throttling</div></div></div><br />






<br />






<br />






<p class="h2header">Globe Valves</p><div style="width:660px; float:left;"><div style="width:200px; float:left"><br />






<a class='resized_img' rel='lightbox[5bd513a277a408eabf2339bb28a06b75]' id='ipb-attach-url-4399-0-88520600-1776999142' href="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-53889600-1323182255.gif" title="valve6.gif - Size: 1.91KB, Downloads: 440"><img src="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-53889600-1323182255_thumb.gif" id='ipb-attach-img-4399-0-88520600-1776999142' style='width:132;height:250' class='attach' width="132" height="250" alt="Attached Image: valve6.gif" /></a>
</div><div style="width:460px; float:left;">Best Suited Control:  Linear and Equal percentage<br />






<br />






Recommended Uses:<br />






1.  Throttling service/flow regulation<br />






2.  Frequent operation<br />






<br />






Applications:  Liquids, vapors, gases, corrosive substances, slurries<br />






<div style="width:230px; float:left"><br />






Advantages:                        <br />






1. Efficient throttling              <br />






2. Accurate flow control        <br />






3. Available in multiple ports</div><div style="width:230px; float:left"><br />






Disadvantages:<br />






1. High pressure drop<br />






2. More expensive than other valves</div></div></div><br />






<br />






<br />






<p class="h2header">Ball Valves</p><div style="width:660px; float:left;"><div style="width:270px; float:left"><br />






<a class='resized_img' rel='lightbox[5bd513a277a408eabf2339bb28a06b75]' id='ipb-attach-url-4400-0-88523800-1776999142' href="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-16189200-1323182265.gif" title="valve7.gif - Size: 2.15KB, Downloads: 418"><img src="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-16189200-1323182265_thumb.gif" id='ipb-attach-img-4400-0-88523800-1776999142' style='width:250;height:187' class='attach' width="250" height="187" alt="Attached Image: valve7.gif" /></a>
</div><div style="width:390px; float:left;">Best Suited Control: Quick opening, linear<br />






<br />






Recommended Uses:<br />






1.  Fully open/closed, limited-throttling<br />






2.  Higher temperature fluids<br />






<br />






Applications: Most liquids, high temperatures, slurries<br />






<div style="width:195px; float:left"><br />






Advantages:                        <br />






1. Low cost                          <br />






2. High capacity                    <br />






3. Low leakage and maint.<br />






4. Tight sealing with low torque</div><div style="width:195px; float:left"><br />






Disadvantages:<br />






1. Poor throttling characteristics<br />






2. Prone to cavitation</div></div></div><br />






<br />






<br />






<p class="h2header">Butterfly Valves</p><div style="width:660px; float:left;"><div style="width:200px; float:left"><br />






<a class='resized_img' rel='lightbox[5bd513a277a408eabf2339bb28a06b75]' id='ipb-attach-url-4401-0-88526800-1776999142' href="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-87759900-1323182274.gif" title="valve8.gif - Size: 1.87KB, Downloads: 366"><img src="http://www.cheresources.com/invision/uploads/monthly_12_2011/ccs-1-0-87759900-1323182274_thumb.gif" id='ipb-attach-img-4401-0-88526800-1776999142' style='width:161;height:250' class='attach' width="161" height="250" alt="Attached Image: valve8.gif" /></a>
</div><div style="width:460px; float:left;">Best Suited Control:  Linear, Equal percentage<br />






<br />






Recommended Uses:  <br />






1.  Fully open/closed or throttling services<br />






2.  Frequent operation<br />






3.  Minimal fluid trapping in line<br />






<br />






Applications:  Liquids, gases, slurries, liquids with suspended solids<br />






<div style="width:230px; float:left"><br />






Advantages:                       <br />






1. Low cost and maint.        <br />






2. High capacity                  <br />






3. Good flow control<br />






4. Low pressure drop</div><div style="width:230px; float:left"><br />






Disadvantages:<br />






1. High torque required for control<br />






2. Prone to cavitation at lower flows</div></div></div><br />






<br />






<br />






<p class="h2header">Other Valves</p><br />






Another type of valve commonly used in conjunction with other valves is called a check valve.  Check valves are designed to restrict the flow to one direction.  If the flow reverses direction, the check valve closes.   Relief valves are used to regulate the operating pressure of incompressible flow.  Safety valves are used to release excess pressure in gases or compressible fluids.<br />






<br />






<p class="h2header">References</p><br />






Rosaler, Robert C., <u>Standard Handbook of Plant Engineering</u>, McGraw-Hill, New York, 1995, pages 10-110 through 10-122<br />






Purcell, Michael K., "Easily Select and Size Control Valves", Chemical Engineering Progress, March 1999, pages 45-50]]></description>
		<pubDate>Tue, 06 Dec 2011 14:32:38 +0000</pubDate>
		<guid isPermaLink="false">a5481cd6d7517aa3fc6476dc7d9019ab</guid>
	</item>
	<item>
		<title>Centrifugal Pumps: Basic Concepts of Operation,...</title>
		<link>http://www.cheresources.com/content/articles/fluid-flow/centrifugal-pumps-basic-concepts-of-operation-maintenance-and-troubleshooting</link>
		<description><![CDATA[<p>The operating manual of any centrifugal pump often starts with a general statement, "Your centrifugal pump will give you completely trouble free and satisfactory service only on the condition that it is installed and operated with due care and is properly maintained."</p> <p>Despite all the care in operation and maintenance, engineers often face the statement "the pump has failed i.e. it can no longer be kept in service". Inability to deliver the desired flow and head is just one of the most common conditions for taking a pump out of service. {parse block="google_articles"}There are other many conditions in which a pump, despite suffering no loss in flow or head, is considered to have failed and has to be pulled out of service as soon as possible. These include seal related problems (leakages, loss of flushing, cooling, quenching systems, etc), pump and motor bearings related problems (loss of lubrication, cooling, contamination of oil, abnormal noise, etc), leakages from pump casing, very high noise and vibration levels, or driver (motor or turbine) related problems.</p><p>The list of pump failure conditions mentioned above is neither exhaustive nor are the conditions mutually exclusive. Often the root causes of failure are the same but the symptoms are different. A little care when first symptoms of a problem appear can save the pumps from permanent failures. Thus the most important task in such situations is to find out whether the pump has failed mechanically or if there is some process deficiency, or both. Many times when the pumps are sent to the workshop, the maintenance people do not find anything wrong on disassembling it. Thus the decision to pull a pump out of service for maintenance / repair should be made after a detailed analysis of the symptoms and root causes of the pump failure. Also, in case of any mechanical failure or physical damage of pump internals, the operating engineer should be able to relate the failure to the process unit's operating problems.</p><p>Any operating engineer, who typically has a chemical engineering background and who desires to protect his pumps from frequent failures must develop not only a good understanding of the process but also thorough knowledge of the mechanics of the pump. Effective troubleshooting requires an ability to observe changes in performance over time, and in the event of a failure, the capacity to thoroughly investigate the cause of the failure and take measures to prevent the problem from re-occurring.</p><p>The fact of the matter is that there are three types of problems mostly encountered with centrifugal pumps:</p><ul><li>design errors </li><li>poor operation </li><li>poor maintenance practices</li></ul><p>The present article is being presented in three parts, covering all aspects of operation, maintenance, and troubleshooting of centrifugal pumps. The article has been written keeping in mind the level and interests of students and the beginners in operation. Any comments or queries are most welcome.</p><p><span class="h1header">Working Mechanism of a Centrifugal Pump</span></p><p align="left">A centrifugal pump is one of the simplest pieces of equipment in any process plant. Its purpose is to convert energy of a prime mover (a electric motor or turbine) first into velocity or kinetic energy and then into pressure energy of a fluid that is being pumped.</p><p align="left">The energy changes occur by virtue of two main parts of the pump, the impeller and the volute or diffuser. The impeller is the rotating part that converts driver energy into the kinetic energy. The volute or diffuser is the stationary part that converts the kinetic energy into pressure energy.</p><span class="info">All of the forms of energy involved in a liquid flow system are expressed in terms of feet of liquid i.e. head.</span><p class="h2header" align="left">Generation of Centrifugal Force</p><table class="imagecaption" border="0" align="left"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centrifugalpumps8.gif" alt="centrifugal-pumps" width="243" height="230" /></td></tr><tr><td>Figure 1: Liquid Flow Path Inside<br />
a Centrifugal Pump</td></tr></tbody></table><p align="left">The process liquid enters the suction nozzle and then into eye (center) of a revolving device known as an impeller. When the impeller rotates, it spins the liquid{parse block="google_articles"} sitting in the cavities between the vanes outward and provides centrifugal acceleration. As liquid leaves the eye of the impeller a low-pressure area is created causing more liquid to flow toward the inlet. Because the impeller blades are curved, the fluid is pushed in a tangential and radial direction by the centrifugal force. This force acting inside the pump is the same one that keeps water inside a bucket that is rotating at the end of a string. Figure A.01 below depicts a side cross-section of a centrifugal pump indicating the movement of the liquid.</p><p class="h2header" align="left">Conversion of Kinetic Energy to Pressure Energy</p><p align="left">The key idea is that the energy created by the centrifugal force is <em>kinetic energy</em>. The amount of energy given to the liquid is proportional to the <em>velocity</em> at the edge or vane tip of the impeller. The faster the impeller revolves or the bigger the impeller is, then the higher will be the velocity of the liquid at the vane tip and the greater the energy imparted to the liquid.</p><p>This kinetic energy of a liquid coming out of an impeller is harnessed by creating a <em>resistance</em> to the flow. The first resistance is created by the pump volute (casing) that catches the liquid and slows it down. In the discharge nozzle, the liquid further decelerates and its velocity is converted to pressure according to Bernoulli's principle.</p><p>Therefore, the head (pressure in terms of height of liquid) developed is approximately equal to the velocity energy at the periphery of the impeller expressed by the following well-known formula:</p><table class="equationtable" border="0" width="50%"><tbody><tr><td style="width: 50%;" align="left"><p><img src="../../../../invision/uploads/images/articles/centpumps_eq1a.gif" alt="centpumps_eq1a" width="87" height="55" /></p><p>where:<br />
H = Total Head developed in feet<br />
v = Velocity at periphery of impleller in ft/s<br />
g = Acceleration due to gravity = 32.2 ft/s<sup>2</sup></p></td><td class="equationnumber" align="right">Eq. 1</td></tr></tbody></table><p>A handy formula for peripheral velocity is:</p><table class="equationtable" border="0" width="50%"><tbody><tr><td style="width: 50%;"><p><img src="../../../../invision/uploads/images/articles/centpumps_eq2a.gif" alt="centpumps_eq2a" width="103" height="58" /></p><p>where:<br />
v = Velocity at periphery of impleller in ft/s<br />
N = Impeller RPM (revolutions per minute)<br />
D = Impeller diameter in inches</p></td><td class="equationnumber" align="right">Eq. 2</td></tr></tbody></table><p>This head can also be calculated from the readings on the pressure gauges attached to the suction and discharge lines.</p><p><em><strong><span class="info">One fact that must always be remembered: A pump does not create pressure, it only provides flow.<br />
Pressure is a just an indication of the amount of resistance to flow.</span></strong></em></p><p align="left">Pump curves relate flow rate and pressure (head) developed by the pump at different impeller sizes and rotational speeds. The centrifugal pump operation should conform to the pump curves supplied by the manufacturer. In order to read and understand the pump curves, it is very important to develop a clear understanding of the terms used in the curves. This topic will be covered later.</p><p align="left"><span class="h1header">General Components of Centrifugal Pumps</span></p><p>A centrifugal pump has two main components:</p><p>A rotating component comprised of an impeller and a shaft</p><p>A stationary component comprised of a casing, casing cover, and bearings.</p><p>The general components, both stationary and rotary, are depicted in Figure 2. The main components are discussed in brief below. Figure3 shows these parts on a photograph of a pump in the field.</p><table class="imagecaption" border="0" align="center"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="General Components of Centrifugal Pump" href="../../../../invision/uploads/images/articles/centrifugalpumps11.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps11.gif" alt="centrifugal-pumps" width="250" height="189" /></a></td><td><a class='resized_img' rel='lightbox[2]' title="General Components of Centrifugal Pump" href="../../../../invision/uploads/images/articles/centrifugalpumps12.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps12.gif" alt="centrifugal-pumps" width="250" height="186" /></a></td></tr><tr><td align="left">Figure 2: General Components of Centrifugal Pump</td><td align="left">Figure 3: General Components of Centrifugal Pump</td></tr></tbody></table><p class="h2header">Stationary Components</p><p class="column_separator"><span style="text-decoration: underline;">Casings</span></p><table class="imagecaption" border="0" align="left"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Cut-Away of a Pump Showing Volute Casing" href="../../../../invision/uploads/images/articles/centrifugalpumps13.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps13.gif" alt="centrifugal-pumps" width="300" height="226" /></a></td></tr><tr><td>Figure 4: Cut-Away of a Pump Showing Volute Casing</td></tr></tbody></table><p>Casings are generally of two types: volute and circular. The impellers are fitted inside the casings.</p><p><em>Volute Casings</em></p><p>Volute casings build a higher head; <em>circular casings</em> are used for low head and high capacity. A <em>volute</em> is a curved funnel increasing in area to the discharge port as shown in Figure 4. As the area of the cross-section increases, the volute reduces the speed of the liquid and increases the pressure of the liquid. One of the <em>main purposes of a volute casing</em> is to help balance the hydraulic pressure on the shaft of the pump. However, this occurs best at the manufacturer's recommended capacity. Running volute-style pumps at a lower capacity than the manufacturer recommends can put lateral stress on the shaft of the pump, increasing wear-and-tear on the seals and bearings, and on the shaft itself. Double-volute casings are used when the radial thrusts become significant at reduced capacities.</p><p><em>Circular Casings</em></p><p>Circular casing have stationary diffusion vanes surrounding the impeller periphery that convert velocity energy to pressure energy. Conventionally, the diffusers are applied to multi-stage pumps.</p><table class="imagecaption" border="0" align="right"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centrifugalpumps14.gif" alt="centrifugal-pumps" width="134" height="169" /></td></tr><tr><td>Figure 5: Solid Casing</td></tr></tbody></table><p>The casings can be designed either as solid casings or split casings. <strong>Solid casing</strong> implies a design in which the entire casing including the discharge nozzle is all contained in one casting or fabricated piece. A <strong>split casing</strong> implies two or more parts are fastened together. When the casing parts are divided by horizontal plane, the casing is described as horizontally split or axially split casing. When the split is in a vertical plane perpendicular to the rotation axis, the casing is described as vertically split or radially split casing. Casing Wear rings act as the seal between the casing and the impeller.</p><p><span style="text-decoration: underline;">Suction and Discharge Nozzles</span></p><p>The suction and discharge nozzles are part of the casings itself. They commonly have the following configurationstwo of which are shown in Figure 6:</p><p><em></em></p><table class="imagecaption" border="0" align="left"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Suction and Discharge Nozzle Locations" href="../../../../invision/uploads/images/articles/centrifugalpumps15.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps15.gif" alt="centrifugal-pumps" width="300" height="212" /></a></td></tr><tr><td>Figure 6: Suction and Discharge Nozzle Locations</td></tr></tbody></table><p><em>End Suction/Top Discharge</em></p><p>The suction nozzle is located at the end of, and concentric to, the shaft while the discharge nozzle is located at the top of the case perpendicular to the shaft. This pump is always of an overhung type and typically has lower NPSHr because the liquid feeds directly into the impeller eye</p><p><em>Top Suction/Top Discharge</em></p><p>The suction and discharge nozzles are located at the top of the case perpendicular to the shaft. This pump can either be an overhung type or between-bearing type but is always a radially split case pump.</p><p><em>Side Suction/Side Discharge</em></p><p>The suction and discharge nozzles are located at the sides of the case perpendicular to the shaft. This pump can have either an axially or radially split case type.</p><p><span style="text-decoration: underline;">Seal Chamber and Stuffing Box</span></p><table class="imagecaption" border="0" align="left"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centrifugalpumps16.gif" alt="centrifugal-pumps" width="342" height="236" /></td></tr><tr><td>Figure 7: Parts of a Simple Seal Chamber</td></tr></tbody></table><p>Seal chamber and Stuffing box both refer to a chamber, either integral with or separate from the pump case housing that forms the region between the shaft and casing where sealing media are installed. When the sealing is achieved by means of a mechanical seal, the chamber is commonly referred to as a Seal Chamber. When the sealing is achieved by means of packing, the chamber is referred to as a Stuffing Box. Both the seal chamber and the stuffing box have the primary function of protecting the pump against leakage at the point where the shaft passes out through the pump pressure casing. When the pressure at the bottom of the chamber is below atmospheric, it prevents air leakage into the pump. When the pressure is above atmospheric, the chambers prevent liquid leakage out of the pump. The seal chambers and stuffing boxes are also provided with cooling or heating arrangement for proper temperature control. Figure7depicts an externally mounted seal chamber and its parts.</p><p><em>Glands</em></p><p>The gland is a very important part of the seal chamber or the stuffing box. It gives the packings or the mechanical seal the desired fit on the shaft sleeve. It can be easily adjusted in axial direction. The gland comprises of the seal flush, quench, cooling, drain, and vent connection ports as per the standard codes like API 68</p><p><em>Throat Bushing</em></p><p>The bottom or inside end of the chamber is provided with a stationary device called throat bushing that forms a restrictive close clearance around the sleeve (or shaft) between the seal and the impeller.</p><p><em>Throttle Bushing{parse block="google_articles"}</em></p><p>The throttle bushing refers to<strong> </strong>a device that forms a restrictive close clearance around the sleeve (or shaft) at the outboard end of a mechanical seal gland.</p><p><em>Internal Circulating Device</em></p><p>The internal circulating device refers to device located in the seal chamber to circulate seal chamber fluid through a cooler or barrier/buffer fluid reservoir. Usually it is referred to as a pumping ring.</p><p><em>Mechanical Seal</em></p><p>Mechanical seals will be discussed further in part two of this article series.</p><p><span style="text-decoration: underline;">Bearing Housing</span></p><p>The bearing housing encloses the bearings mounted on the shaft. The bearings keep the shaft or rotor in correct alignment with the stationary parts under the action of radial and transverse loads. The bearing house also includes an oil reservoir for lubrication, constant level oiler, jacket for cooling by circulating cooling water.</p><p class="h2header">Rotating Components</p><p><span style="text-decoration: underline;">Impeller</span></p><p>The impeller is the main rotating part that provides the centrifugal acceleration to the fluid. They are often classified in many ways:</p><ol><li>Based on major direction of flow in reference to the axis of rotation:<br />
Radial flow<br />
Axial flow<br />
Mixed flow<br />
</li><li>Based on suction type:<br />
Single-suction: Liquid inlet on one side.<br />
Double-suction: Liquid inlet to the impeller symmetrically from both sides.</li><li><p>Based on mechanical construction (Figure 8)<br />
Closed: Shrouds or sidewall enclosing the vanes.<br />
Open: No shrouds or wall to enclose the vanes.<br />
Semi-open or vortex type.</p><table class="imagecaption" border="0" align="right"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centrifugalpumps17.gif" alt="centrifugal-pumps" width="298" height="228" /></td></tr><tr><td>Figure 8: Impeller Types</td></tr></tbody></table><p> </p></li></ol><p>Closed impellers require wear rings and these wear rings present another maintenance problem. Open and semi-open impellers are less likely to clog, but need manual adjustment to the volute or back-plate to get the proper impeller setting and prevent internal re-circulation. Vortex pump impellers are great for solids and "stringy" materials but they are up to 50% less efficient than conventional designs. The number of impellers determines the number of stages of the pump. A single stage pump has one impeller only and is best for low head service. A two-stage pump has two impellers in series for medium head service. A multi-stage pump has three or more impellers in series for high head service.</p><p>Wear ring provides an easily and economically renewable leakage joint between the impeller and the casing. clearance becomes too large the pump efficiency will be lowered causing heat and vibration problems. Most manufacturers require that you disassemble the pump to check the wear ring clearance and replace the rings when this clearance doubles.</p><p><span style="text-decoration: underline;">Shaft</span></p><p>The basic purpose of a centrifugal pump shaft is to transmit the torques encountered when starting and during operation while supporting the impeller and other rotating parts. It must do this job with a deflection less than the minimum clearance between the rotating and stationary parts.</p><p><em></em></p><table class="imagecaption" border="0" align="left"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centrifugalpumps18.gif" alt="centrifugal-pumps" width="256" height="168" /></td></tr><tr><td>Figure 9: Shaft Sleeve</td></tr></tbody></table><p><em>Shaft Sleeves</em></p><p>Pump shafts are usually protected from erosion, corrosion, and wear at the seal chambers, leakage joints, internal bearings, and in the waterways by renewable sleeves. Unless otherwise specified, a shaft sleeve of wear, corrosion, and erosion-resistant material shall be provided to protect the shaft. The sleeve shall be sealed at one end. The shaft sleeve assembly shall extend beyond the outer face of the seal gland plate. (Leakage between the shaft and the sleeve should not be confused with leakage through the mechanical seal).</p><p><em>Coupling</em></p><p>Couplings can compensate for axial growth of the shaft and transmit torque to the impeller. Shaft couplings can be broadly classified into two groups: rigid and flexible. Rigid couplings are used in applications where there is absolutely no possibility or room for any misalignment. Flexible shaft couplings are more prone to selection, installation and maintenance errors. Flexible shaft couplings can be divided into two basic groups: elastomeric and non-elastomeric</p><ol><li>Elastomeric couplings use either rubber or polymer elements to achieve flexibility. These elements can either be in shear or in compression. Tire and rubber sleeve designs are elastomer in shear couplings; jaw and pin and bushing designs are elastomer in compression couplings.</li><li>Non-elastomeric couplings use metallic elements to obtain flexibility. These can be one of two types: lubricated or non-lubricated. Lubricated designs accommodate misalignment by the sliding action of their components, hence the need for lubrication. The non-lubricated designs accommodate misalignment through flexing. Gear, grid and chain couplings are examples of non-elastomeric, lubricated couplings. Disc and diaphragm couplings are non-elastomeric and non-lubricated.</li></ol><p class="h2header">Auxilliary Components</p><p>Auxiliary components generally include the following piping systems for the following services:</p><ol><li>Seal flushing , cooling , quenching systems</li><li>Seal drains and vents</li><li>Bearing lubrication , cooling systems</li><li>Seal chamber or stuffing box cooling, heating systems</li><li>Pump pedestal cooling systems </li></ol><p>Auxiliary piping systems include tubing, piping, isolating valves, control valves, relief valves, temperature gauges and thermocouples, pressure gauges, sight flow indicators, orifices, seal flush coolers, dual seal barrier/buffer fluid reservoirs, and all related vents and drains.</p><p>All auxiliary components shall comply with the requirements as per standard codes like API 610 (refinery services), API 682 (shaft sealing systems) etc.</p><p class="h1header">Definition of Important Terms</p><p align="left">The key performance parameters of centrifugal pumps are capacity, head, BHP (Brake horse power), BEP (Best efficiency point) and specific speed. The pump curves provide the operating window within which these parameters can be varied for satisfactory pump operation. The following parameters or terms are discussed in detail in this section.</p><p align="left">Capacity</p><p>Head</p><ul><li>Significance of using Head instead of Pressure </li><li>Pressure to Head Conversion formula </li><li>Static Suction Head, <strong>h<sub>S</sub></strong> </li><li>Static Discharge Head, <strong>h<sub>d</sub></strong> {parse block="google_articles"}</li><li>Friction Head, <strong>hf</strong> </li><li>Vapor pressure Head, <strong>hvp</strong> </li><li>Pressure Head, <strong>hp</strong> </li><li>Velocity Head, <strong>hv</strong> </li><li>Total Suction Head<strong> H<sub>S</sub></strong> </li><li>Total Discharge Head <strong>H<sub>d</sub></strong> </li><li>Total Differential Head <strong>H<sub>T</sub></strong> </li></ul><p>NPSH</p><ul><li>Net Positive Suction Head Required <strong>NPSHr</strong> </li><li>Net Positive Suction Head Available <strong>NPSHa</strong> </li></ul><p align="left">Power (Brake Horse Power, B.H.P) and Efficiency (Best Efficiency Point, B.E.P)</p><p align="left">Specific Speed (Ns)</p><p align="left">Affinity Laws</p><p class="h2header" align="left">Capacity</p><p align="left">Capacity means the flow rate with which liquid is moved or pushed by the pump to the desired point in the process. It is commonly measured in either gallons per minute (gpm) or cubic meters per hour (m<sup>3</sup>/hr). The capacity usually changes with the changes in operation of the process. For example, a boiler feed pump is an application that needs a constant pressure with varying capacities to meet a changing steam demand.</p><p align="left">The capacity depends on a number of factors like:</p><ul><li>Process liquid characteristics i.e. density, viscosity</li><li>Size of the pump and its inlet and outlet sections</li><li>Impeller size </li><li>Impeller rotational speed RPM</li><li>Size and shape of cavities between the vanes</li><li>Pump suction and discharge temperature and pressure conditions</li></ul><p>For a pump with a particular impeller running at a certain speed in a liquid, the only items on the list above that can change the amount flowing through the pump are the pressures at the pump inlet and outlet. The effect on the flow through a pump by changing the outlet pressures is graphed on a pump curve.</p><p>As liquids are essentially incompressible, the capacity is directly related with the velocity of flow in the suction pipe. This relationship is as follows:</p><p> </p><table class="equationtable" border="0" align="center"><tbody><tr><td><p><img src="../../../../invision/uploads/images/articles/centpumps_eq3a.gif" alt="centpumps_eq3a" width="140" height="30" /></p><p>where:<br />
Q = Capacity in GPM (gallons per minute)<br />
V = Velocity of the flow in ft/s<br />
A = Cross sectional area of pipe if ft<sup>2</sup></p></td><td class="equationnumber" align="right">Eq. (3)</td></tr></tbody></table><p class="h2header">Head</p><p><span style="text-decoration: underline;">Significance of Using the Term "Head" Instead of the Term "Pressure"</span></p><p>The pressure at any point in a liquid can be thought of as being caused by a vertical column of the liquid due to its weight. The height of this column is called the static head and is expressed in terms of feet of liquid.</p><p>The same <em>head</em> term is used to measure the kinetic energy created by the pump. In other words, head is a measurement of the height of a liquid column that the pump could create from the kinetic energy imparted to the liquid. Imagine a pipe shooting a jet of water straight up into the air, the height the water goes up would be the head.</p><p>The head is not equivalent to pressure. Head is a term that has units of a length or feet and pressure has units of force per unit area or pound per square inch. <strong>The main reason for using head instead of pressure</strong> to measure a centrifugal pump's energy is that the pressure from a pump will change if the specific gravity (weight) of the liquid changes, but the head will not change. Since any given centrifugal pump can move a lot of different fluids, with different specific gravities, it is simpler to discuss the pump's head and forget about the pressure.</p><p>So a centrifugal pump's performance on any Newtonian fluid, whether it's heavy (sulfuric acid) or light (gasoline) is described by using the term 'head'. The pump performance curves are mostly described in terms of head.</p><span class="info">A given pump with a given impeller diameter and speed will raise a liquid to a certain height regardless of the weight of the liquid.</span><p><span style="text-decoration: underline;">Pressure to Head Conversion Formula</span></p><p>The static head corresponding to any specific pressure is dependent upon the weight of the liquid according to the following formula:</p><p> </p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centpumps_eq4a.gif" alt="centpumps_eq4a" width="291" height="57" /></td><td class="equationnumber" align="right">Eq. (4)</td></tr></tbody></table><p> </p><p>Newtonian liquids have specific gravities typically ranging from 0.5 (light, like light hydrocarbons) to 1.8 (heavy, like concentrated sulfuric acid). Water is a benchmark, having a specific gravity of 1.0.</p><p>This formula helps in converting pump gauge pressures to head for reading the pump curves.</p><p>The various head terms are discussed below.</p><p><strong><span style="text-decoration: underline;">Note</span></strong>: The Subscripts <strong>'s'</strong> refers to suction conditions and <strong>'d'</strong> refers to discharge conditions.</p><ul type="disc"><li>Static Suction Head, <strong>h<sub>S</sub></strong> </li><li>Static Discharge Head, <strong>h<sub>d</sub></strong> </li><li>Friction Head, <strong>h<sub>f</sub></strong> </li><li>Vapor pressure Head, <strong>h<sub>vp</sub></strong> </li><li>Pressure Head, <strong>h<sub>p</sub></strong> </li><li>Velocity Head, <strong>h<sub>v</sub></strong> </li><li>Total Suction Head<strong> H<sub>S</sub></strong> </li><li>Total Discharge Head <strong>H<sub>d</sub></strong> </li><li>Total Differential Head <strong>H<sub>T</sub></strong> </li><li>Net Positive Suction Head Required <strong>NPSHr</strong> </li><li>Net Positive Suction Head Available <strong>NPSHa</strong> </li></ul><p><em>Static Suction Head (h<sub>s</sub>)</em></p><p>Head resulting from elevation of the liquid relative to the pump center line. If the liquid level is above pump centerline, <strong>h<sub>S</sub></strong> is positive. If the liquid level is below pump centerline, <strong>h<sub>S</sub></strong> is negative. Negative <strong>h<sub>S</sub></strong> condition is commonly denoted as a "suction lift" condition.</p><p><em>Static Discharge Head, (h<sub>d</sub>)</em></p><p>It is the vertical distance in feet between the pump centerline and the point of free discharge or the surface of the liquid in the discharge tank.</p><p><em></em></p><p><em>Friction Head (h<sub>f</sub>)</em></p><p>The head required to overcome the resistance to flow in the pipe and fittings. It is dependent upon the size, condition and type of pipe, number and type of pipefittings, flow rate, and nature of the liquid.</p><p><em>Vapor Pressure Head (h<sub>vp</sub>)</em></p><p>Vapor pressure is the pressure at which a liquid and its vapor co-exist in equilibrium at a given temperature. The vapor pressure of liquid can be obtained from vapor pressure tables. When the vapor pressure is converted to head, it is referred to as vapor pressure head, <strong>h<sub>vp</sub></strong>. The value of <strong>h<sub>vp</sub></strong> of a liquid increases with the rising temperature and in effect, opposes the pressure on the liquid surface, the positive force that tends to cause liquid flow into the pump suction i.e. it reduces the suction pressure head.</p><p><em>Pressure Head (h<sub>p</sub>)</em></p><p>Pressure Head must be considered when a pumping system either begins or terminates in a tank which is under some pressure other than atmospheric. The pressure in such a tank must first be converted to feet of liquid. Denoted as <strong>h<sub>p</sub></strong>, pressure head refers to absolute pressure on the surface of the liquid reservoir supplying the pump suction, converted to feet of head. If the system is open, <strong>h<sub>p</sub></strong> equals atmospheric pressure head.</p><p><em>Velocity Head (h<sub>v</sub>)</em></p><p>Refers to the energy of a liquid as a result of its motion at some velocity '<strong>v'</strong>. It is the equivalent head in feet through which the water would have to fall to acquire the same velocity, or in other words, the head necessary to accelerate the water. The velocity head is usually insignificant and can be ignored in most high head systems. However, it can be a large factor and must be considered in low head systems.</p><p><em>Total Suction Head (H<sub>s</sub>)</em></p><p>The suction reservoir pressure head<strong> (hp<sub>S</sub></strong>) plus the static suction head (<strong>h<sub>S</sub></strong>) plus the velocity head at the pump suction flange (h<sub>VS</sub>) minus the friction head in the suction line (<strong>hf<sub>S</sub></strong>).</p><table class="equationtable" border="0" align="center"><tbody><tr><td>H<sub>S</sub>= hp<sub>S</sub> + h<sub>S</sub> + hv<sub>S</sub> - hf<sub>S</sub></td><td class="equationnumber" align="right">Eq. (5)</td></tr></tbody></table><p>The total suction head is the reading of the gauge on the suction flange, converted to feet of liquid.</p><p><em>Total Discharge Head (H<sub>d</sub>)</em></p><p>The discharge reservoir pressure head (<strong>hp<sub>d</sub></strong>) plus static discharge head (<strong>h<sub>d</sub></strong>) plus the velocity head at the pump discharge flange (<strong>hv<sub>d</sub></strong>) plus the total friction head in the discharge line (<strong>hf<sub>d</sub></strong>).</p><table class="equationtable" border="0" align="center"><tbody><tr><td>H<sub>d</sub>= hp<sub>d</sub> + h<sub>d</sub> + hv<sub>d</sub> + hf<sub>d</sub></td><td class="equationnumber" align="right">Eq. (6)</td></tr></tbody></table><p>The total discharge head is the reading of a gauge at the discharge flange, converted to feet of liquid.</p><p><em>Total Differential Head (H<sub>T</sub>)</em></p><p>It is the total discharge head minus the total suction head or</p><table class="equationtable" border="0" align="center"><tbody><tr><td>H<sub>T</sub> = H<sub>d</sub> + H<sub>S</sub> (with a suction lift)</td><td class="equationnumber" align="right">Eq. (7)</td></tr><tr><td>H<sub>T</sub> = H<sub>d</sub> - H<sub>S</sub> (with a suction head)</td><td class="equationnumber" align="right">Eq. (8)</td></tr></tbody></table> <p class="h2header">NPSH</p><p>When discussing centrifugal pumps, the two most important head terms are NPSHr and NPSHa.</p><p><span style="text-decoration: underline;">Net Positive Suction Head Required, NPSHr</span></p><p>NPSH is one of the most widely used and least understood terms associated with pumps. Understanding the significance of NPSH is very much essential during installation as well as operation of the pumps.</p><p><em>Pumps Can Only Pump Liquids, Not Vapor{parse block="google_articles"}</em></p><p>The satisfactory operation of a pump requires that vaporization of the liquid being pumped does not occur at any condition of operation. This is so desired because when a liquid vaporizes its volume increases very much. For example, 1 ft<sup>3</sup> of water at room temperature becomes 1700 ft<sup>3</sup> of vapor at the same temperature. This makes it clear that if we are to pump a fluid effectively, it must be kept always in the liquid form.</p><p><em>Rise in temperature and fall in pressure induces vaporization</em><br />
<br />
The vaporization begins when the vapor pressure of the liquid at the operating temperature equals the external system pressure, which, in an open system is always equal to atmospheric pressure. Any decrease in external pressure or rise in operating temperature can induce vaporization and the pump stops pumping. Thus, the pump always needs to have a sufficient amount of suction head present to prevent this vaporization at the lowest pressure point in the pump.</p><p><em>NPSH as a measure to prevent liquid vaporization</em><br />
<br />
The manufacturer usually tests the pump with water at different capacities, created by throttling the suction side. When the first signs of vaporization induced cavitation occur, the suction pressure is noted (the term cavitation is discussed in detail later). This pressure is converted into the head. This head number is published on the pump curve and is referred as the "net positive suction head required (NPSHr) or sometimes in short as the NPSH. Thus the Net Positive Suction Head (NPSH) is the total head at the suction flange of the pump less the vapor pressure converted to fluid column height of the liquid.</p><p><em>NPSHr is a function of pump design</em><br />
<br />
NPSH required is a function of the pump design and is determined based on actual pump test by the vendor. As the liquid passes from the pump suction to the eye of the impeller, the velocity increases and the pressure decreases. There are also pressure losses due to shock and turbulence as the liquid strikes the impeller. The centrifugal force of the impeller vanes further increases the velocity and decreases the pressure of the liquid. The NPSH required is the positive head in feet absolute required at the pump suction to overcome these pressure drops in the pump and maintain the majority of the liquid above its vapor pressure.<br />
<br />
The NPSH is always positive since it is expressed in terms of absolute fluid column height. The term "Net" refers to the actual pressure head at the pump suction flange and not the static suction head.<br />
<em><br />
NPSHr increases as capacity increases</em><br />
<br />
The NPSH required varies with speed and capacity within any particular pump. The NPSH required increase as the capacity is increasing because the velocity of the liquid is increasing, and as anytime the velocity of a liquid goes up, the pressure or head comes down. Pump manufacturer's curves normally provide this information. The NPSH is independent of the fluid density as are all head terms.</p><span class="info"><strong>Note:</strong>It is to be noted that the net positive suction head required (NPSHr) number shown on the pump curves is for fresh water at 20Â°C and not for the fluid or combinations of fluids being pumped.</span><p><span style="text-decoration: underline;">Net Positive Suction Head Available, NPSHa</span></p><p><em>NPSHa is a function of system design </em></p><p>Net Positive Suction Head Available is a function of the system in which the pump operates. It is the excess pressure of the liquid in feet absolute over its vapor pressure as it arrives at the pump suction, to be sure that the pump selected does not cavitate. It is calculated based on system or process conditions.<br />
<br />
<em>NPSHa calculation</em></p><p>The formula for calculating the NPSHa is stated below:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><p>NPSHa<sub>s</sub> = hp<sub>s</sub> + h<sub>s</sub> - hvp<sub>s</sub> + hf<sub>s</sub></p><p>where:</p><p>hp<sub>s</sub> = Head pressure or the barometric pressure of the vessel converted to head<br />
h<sub>s</sub> = Static suction head or the vertical distance between the eye of the first stage impeller centerline and the suction liquid level<br />
hvp<sub>s</sub> = Vapor pressure head or the vapor pressure of the liquid at its maximum pumping temperature converted to head<br />
hf<sub>s</sub> = Friction head or friction and entrance pressure losses on the suction side converted to head</p></td><td class="equationnumber" style="width: 20%;" align="right">Eq. (9)</td></tr></tbody></table><span class="info"><li>It is important to correct for the specific gravity of the liquid and to convert all terms to units of "feet <strong>absolute</strong>" in using the formula. </li><li>Any discussion of NPSH or cavitation is only concerned about the suction side of the pump. There is almost always plenty of pressure on the discharge side of the pump to prevent the fluid from vaporizing.</li></span><p><em>NPSHa in a Nutshell</em></p><p>In a nutshell, NPSH available is defined as:</p><table class="equationtable" border="0" align="center"><tbody><tr><td align="left"><p>NPSHa = Pressure head + Static head - Vapor pressure head of your product - Friction head loss in the piping, valves and fittings.</p><p>where all terms are in absolute feed of head.</p></td><td class="equationnumber" style="width: 20%;" align="right">Eq. (10)</td></tr></tbody></table><p>In an existing system, the NPSHa can also be approximated by a gauge on the pump suction using the formula:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><p>NPSHa = hp<sub>S </sub>- hvp<sub>S </sub>Â± hg<sub>S</sub> + hv<sub>S</sub></p><p>where:</p><p>hp<sub>S</sub> = Barometric pressure in feet absolute<br />
hvp<sub>S </sub>= Vapor pressure of the liquid at maximum pumping temperature, in feet absolute<br />
hg<sub>S</sub> = Gauge reading at the pump suction expressed in feet (plus if above atmospheric, minus if below atmospheric) corrected to the pump centerline<br />
hv<sub>S</sub> = Velocity head in the suction pipe at the gauge connection, expressed in feet</p></td><td class="equationnumber" style="width: 20%;" align="right">Eq. (11)</td></tr></tbody></table><p><em>Significance of NPSHr and NPSHa</em></p><p>The NPSH available must always be greater than the NPSH required for the pump to operate properly. It is normal practice to have at least 2 to 3 feet of extra NPSH available at the suction flange to avoid any problems at the duty point.</p><p class="h2header">Power and Efficiency</p><p><span style="text-decoration: underline;">Brake Horse Power (BHP)</span></p><p>The work performed by a pump is a function of the total head and the weight of the liquid pumped in a given time period. Pump input or brake horsepower (BHP) is the actual horsepower delivered to the pump shaft. Pump output or hydraulic or water horsepower (WHP) is the liquid horsepower delivered by the pump. These two terms are defined by the following formulas.</p><table class="equationtable" border="0" align="center"><tbody><tr><td><p><img src="../../../../invision/uploads/images/articles/centpumps_eq12a.gif" alt="centpumps_eq12a" width="291" height="54" /></p><p>where:</p><p>Q = Capacity in gallons per minute (GPM)<br />
H<sub>T</sub> = Total differential head in feet<br />
Efficiency = Pump efficiency in percent</p></td><td class="equationnumber" align="right">Eq. (12)</td></tr><tr><td><p><img src="../../../../invision/uploads/images/articles/centpumps_eq13a.gif" alt="centpumps_eq13a" width="293" height="52" /></p><p>where:</p><p>Q = Capacity in gallons per minute (GPM)<br />
H<sub>T</sub> = Total differential head in feet</p></td><td class="equationnumber" align="right">Eq. (13)</td></tr></tbody></table><p>The constant 3960 is obtained by dividing the number or foot-pounds for one horsepower (33,000) by the weight of one gallon of water (8.33 pounds). BHP<strong> </strong>can also be read from the pump curves at any flow rate. Pump curves are based on a specific gravity of 1.0. Other liquids' specific gravity must be considered. The brake horsepower or input to a pump is greater than the hydraulic horsepower or output due to the mechanical and hydraulic losses incurred in the pump. Therefore the pump efficiency is the ratio of these two values.</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centpumps_eq14a.gif" alt="centpumps_eq14a" width="240" height="51" /></td><td class="equationnumber" align="right">Eq. (14)</td></tr></tbody></table><p><span style="text-decoration: underline;">Best Efficiency Point (BEP)</span></p><p>The H, NPSHr, efficiency, and BHP all vary with flow rate, Q. Best Efficiency Point (BEP) is the capacity at maximum impeller diameter at which the efficiency is highest. All points to the right or left of BEP have a lower efficiency.</p><p><em>BEP as a measure of optimum energy conversion</em></p><p>When sizing and selecting centrifugal pumps for a given application the pump efficiency at design should be taken into consideration. The efficiency of centrifugal pumps is stated as a percentage and represents a unit of measure describing the change of centrifugal force (expressed as the velocity of the fluid) into pressure energy. The B.E.P. (best efficiency point) is the area on the curve where the change of velocity energy into pressure energy at a given gallon per minute is optimum; in essence, the point where the pump is most efficient.</p><p><em>BEP as a measure of mechanically stable operation</em></p><p>The impeller is subject to non-symmetrical forces when operating to the right or left of the BEP. These forces manifest themselves in many mechanically unstable conditions like vibration, excessive hydraulic thrust, temperature rise, and erosion and separation cavitation. Thus the operation of a centrifugal pump should not be outside the furthest left or right efficiency curves published by the manufacturer. Performance in these areas induces premature bearing and mechanical seal failures due to shaft deflection, and an increase in temperature of the process fluid in the pump casing causing seizure of close tolerance parts and cavitation.</p><p><em>BEP as an important parameter in calculations </em></p><p>BEP is an important parameter in that many parametric calculations such as specific speed, suction specific speed, hydrodynamic size, viscosity correction, head rise to shut-off, etc. are based on capacity at BEP. Many users prefer that pumps operate within 80% to 110% of BEP for optimum performance.</p><p><span style="text-decoration: underline;">Specific Speed</span></p><p>Specific speed (N<sub>s</sub>) is a non-dimensional design index that identifies the geometric similarity of pumps. It is used to classify pump impellers as to their type and proportions. Pumps of the same Ns but of different size are considered to be geometrically similar, one pump being a size-factor of the other.</p><p><em>Specific Speed Calculation</em></p><p>The following formula is used to determine specific speed:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><p><img src="../../../../invision/uploads/images/articles/centpumps_eq15a.gif" alt="centpumps_eq15a" width="135" height="57" /></p><p>where:</p><p>Q = Capacity at best efficiency point (BEP) at maximum impeller diameter in gallons per minute (GPM)<br />
H = Head per stage at BEP at maximum impeller diameter in feet<br />
N = Pump speed in RPM</p></td><td class="equationnumber" align="right">Eq. (15)</td></tr></tbody></table><p>The understanding of this definition is of design engineering significance only, however, and specific speed should be thought of only as an index used to predict certain pump characteristics.</p><p>As per the above formula, it is defined as the speed in revolutions per minute at which a geometrically similar impeller would operate if it were of such a size as to deliver one gallon per minute flow against one-foot head.</p><p><em>Specific Speed as a Measure of the Shape or Class of the Impellers</em></p><p>The specific speed determines the general shape or class of the impellers. As the specific speed increases, the ratio of the impeller outlet diameter, D2, to the inlet or eye diameter, D1, decreases. This ratio becomes 1.0 for a true axial flow impeller. <em>Radial flow impellers</em> develop head principally through centrifugal force. Radial impellers are generally low flow high head designs. Pumps of higher specific speeds develop head partly by centrifugal force and partly by axial force. A higher specific speed indicates a pump design with head generation more by axial forces and less by centrifugal forces. An axial flow or propeller pump with a specific speed of 10,000 or greater generates its head exclusively through axial forces. Axial flow impellers are high flow low head designs.</p><p>Specific speed identifies the approximate acceptable ratio of the impeller eye diameter (D1) to the impeller maximum diameter (D2) in designing a good impeller.</p><p>Ns: 500 to 5000;D1/D2 > 1.5 -radial flow pump<br />
Ns: 5000 to 10000;D1/D2 < 1.5 -mixed flow pump<br />
Ns: 10000 to 15000; D1/D2 = 1 - axial flow pump</p><p>Specific speed is also used in designing a new pump by size-factoring a smaller pump of the same specific speed. The performance and construction of the smaller pump are used to predict the performance and model the construction of the new pump.</p><p><em>Suction Specific Speed (Nss)</em></p><p>Suction specific speed (Nss) is a dimensionless number or index that defines the suction characteristics of a pump. It is calculated from the same formula as Ns by substituting H by NPSHr.</p><p>In multi-stage pump the NPSHr is based on the first stage impeller NPSHR. Nss is commonly used as a basis for estimating the safe operating range of capacity for a pump. The higher the Nss is, the narrower is its safe operating range from its BEP. The numbers range between 3,000 and 20,000. Most users prefer that their pumps have Nss in the range of 8000 to 11000 for optimum and trouble-free operation.</p><p class="h2header">The Affinity Laws</p><p>The Affinity Laws are mathematical exp<b></b>ressions that define changes in pump capacity, head, and BHP when a change is made to pump speed, impeller diameter, or both. According to the <em>Affinity Laws</em>:</p><p>Capacity (Q) changes in direct proportion to impeller diameter <strong>D</strong> ratio, or to speed <strong>N</strong> ratio:</p><table class="equationtable" border="0" align="center"><tbody><tr><td> Q<sub>2</sub> = Q<sub>1</sub> x [D<sub>2</sub>/D<sub>1</sub>]</td><td class="equationnumber" align="right">Eq. (16)</td></tr><tr><td> Q<sub>2</sub> = Q<sub>1</sub> x [N<sub>2</sub>/N<sub>1</sub>]</td><td class="equationnumber" align="right">Eq. (17)</td></tr></tbody></table><p>Head (H) changes in direct proportion to the square of impeller diameter <strong>D</strong> ratio, or the square of speed <strong>N</strong> ratio:</p><table class="equationtable" border="0" align="center"><tbody><tr><td> H<sub>2</sub> = H<sub>1</sub> x [D<sub>2</sub>/D<sub>1</sub>]<sup>2</sup></td><td class="equationnumber" align="right">Eq. (18)</td></tr><tr><td> H<sub>2</sub> = H<sub>1</sub> x [N<sub>2</sub>/N<sub>1</sub>]<sup>2</sup></td><td class="equationnumber" align="right">Eq. (19)</td></tr></tbody></table><p>BHP changes in direct proportion to the cube of impeller diameter ratio, or the cube of speed ratio:</p><table class="equationtable" border="0" align="center"><tbody><tr><td> BHP<sub>2</sub> = BHP<sub>1</sub> x [D<sub>2</sub>/D<sub>1</sub>]<sup>3</sup></td><td class="equationnumber" align="right">Eq. (20)</td></tr><tr><td> BHP<sub>2</sub> = BHP<sub>1</sub> x [N<sub>2</sub>/N<sub>1</sub>]<sup>3</sup></td><td class="equationnumber" align="right">Eq. (21)</td></tr></tbody></table><p>Where the subscript: 1 refers to initial condition, 2 refer to new condition.</p><p>If changes are made to both impeller diameter and pump speed the equations can be combined to:</p><table class="equationtable" border="0" align="center"><tbody><tr><td> Q<sub>2</sub> = Q<sub>1</sub> x [(D<sub>2 </sub>x N<sub>2</sub>)/(D<sub>1 </sub>x N<sub>1</sub>)]</td><td class="equationnumber" align="right">Eq. (22)</td></tr><tr><td><p>H<sub>2</sub> = H<sub>1</sub> x [(D<sub>2 </sub>x N<sub>2</sub>)/(D<sub>1 </sub>x N<sub>1</sub>)]<sup>2</sup></p></td><td class="equationnumber" align="right">Eq. (23)</td></tr><tr><td> BHP<sub>2</sub> = BHP<sub>1</sub> x [(D<sub>2 </sub>x N<sub>2</sub>)/(D<sub>1 </sub>x N<sub>1</sub>)]<sup>3</sup></td><td class="equationnumber" align="right">Eq. (24)</td></tr></tbody></table><p> These equations are used to hand-calculate the impeller trim diameter from a given pump performance curve at a bigger diameter.</p><p><span class="info"><strong>The Affinity Laws are valid only under conditions of constant efficiency</strong></span></p> <p class="h1header">Understanding Centrifugal Pump Performance Curves</p><p align="left">The capacity and pressure needs of any system can be defined with the help of a graph called a <strong><em>system curve</em></strong>.  Similarly the capacity <em>vs. </em>pressure variation graph for a particular pump defines its characteristic <strong><em>pump performance curve</em></strong>.</p><p align="left">The pump suppliers try to match the system curve supplied by the user with a pump curve that satisfies these needs as closely as possible.  A pumping system operates where the pump curve and the system resistance curve intersect.   The intersection of the two curves defines the operating point of both pump and process.  However, it is impossible for one operating point to meet all desired operating conditions.   For example, when the discharge valve is throttled, the system resistance curve shift left and so does the operating point.</p><table class="imagecaption" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centrifugalpumps27.gif" alt="centrifugal-pump-curves" width="505" height="406" /></td></tr><tr><td>Figure 10: Typical System and Pump Performance Curves </td></tr></tbody></table><p class="h2header" align="left">Developing a System Curve</p><p align="left">The <em>system resistance or system head curve</em> is the change in flow with respect to head of the system.  It must be developed by the user based upon the conditions of service.  These include physical layout, {parse block="google_articles"}process conditions, and fluid characteristics.  It represents the relationship between flow and hydraulic losses in a system in a graphic form and, since friction losses vary as a square of the flow rate, the system curve is parabolic in shape.  Hydraulic losses in piping systems are composed of pipe friction losses, valves, elbows and other fittings, entrance and exit losses, and losses from changes in pipe size by enlargement or reduction in diameter.</p><p class="h2header" align="left">Developing a Pump Performance Curve</p><p align="left">A pump's performance is shown in its characteristics performance <em>curve</em> where its capacity i.e. flow rate is plotted against its developed head.  The pump performance curve also shows its efficiency (BEP), required input power (in BHP), NPSHr, speed (in RPM), and other information such as pump size and type, impeller size, etc.   This curve is plotted for a constant speed (rpm) and a given impeller diameter (or series of diameters).  It is generated by tests performed by the pump manufacturer.  Pump curves are based on a specific gravity of 1.0.  Other specific gravities must be considered by the user.</p><p class="h2header" align="left">Normal Operation Range</p><p align="left">A typical performance curve (Figure 10) is a plot of Total Head vs. Flow rate for a specific impeller diameter.  The plot starts at zero flow.  The head at this point corresponds to the shut-off head point of the pump.  The curve then decreases to a point where the flow is maximum and the head minimum.  This point is sometimes called the run-out point.  The pump curve is relatively flat and the head decreases gradually as the flow increases.  This pattern is common for radial flow pumps.  Beyond the run-out point, the pump cannot operate.  The pump's range of operation is from the shut-off head point to the run-out point.  Trying to run a pump off the right end of the curve will result in pump cavitation and eventually destroy the pump.<br />
<br />
By plotting the system head curve and pump curve together, you can determine:<br />
<br />
1.Where the pump will operate on its curve?<br />
2.What changes will occur if the system head curve or the pump performance curve changes?<br />
<br />
<p class="h1header">Requirements for Consistent Operation</p><br />
<br />
Centrifugal pumps are the ultimate in simplicity.  In general there are two basic requirements that have to be met at all the times for a trouble free operation and longer service life of centrifugal pumps.  The first requirement is that no cavitation of the pump occurs throughout the broad operating range and the second requirement is that a certain minimum continuous flow is always maintained during operation.  A clear understanding of the concept of cavitation, its symptoms, its causes, and its consequences is very much essential in effective analyses and troubleshooting of the cavitation problem.{parse block="google_articles"}<br />
<br />
Just like there are many forms of cavitation, each demanding a unique solution, there are a number of unfavorable conditions which may occur separately or simultaneously when the pump is operated at reduced flows.  Some include:<br />
<br />
&bull;Cases of heavy leakages from the casing, seal, and stuffing box<br />
&bull;Deflection and shearing of shafts<br />
&bull;Seizure of pump internals<br />
&bull;Close tolerances erosion<br />
&bull;Separation cavitation<br />
&bull;Product quality degradation<br />
&bull;Excessive hydraulic thrust<br />
&bull;Premature bearing failures<br />
Each condition may dictate a different minimum flow low requirement.  The final decision on recommended minimum flow is taken after careful "techno-economical" analysis by both the pump user and the manufacturer.  The consequences of prolonged conditions of cavitation and low flow operation can be disastrous for both the pump and the process.  Such failures in hydrocarbon services have often caused damaging fires resulting in loss of machine, production, and worst of all, human life.   Thus, such situations must be avoided at all cost whether involving modifications in the pump and its piping or altering the operating conditions.  Proper selection and sizing of pump and its associated piping can not only eliminate the chances of cavitation and low flow operation but also significantly decrease their harmful effects.<br />
<p class="h1header">References</p><br />
<br />
1." Trouble shooting Process Operations", 3rd Edition 1991, Norman P.Lieberman, PennWell Books<br />
2."Centrifugal pumps operation at off-design conditions", Chemical Processing April, May, June 1987, Igor J. Karassik<br />
3."Understanding NPSH for Pumps", Technical Publishing Co. 1975, Travis F. Glover{include_content_item 12}<br />
4."Centrifugal Pumps for General Refinery Services", Refining Department, API Standard 610, 6th Edition, January 1981<br />
5."Controlling Centrifugal Pumps", Hydrocarbon Processing, July 1995, Walter Driedger<br />
6."Don't Run Centrifugal Pumps Off The Right Side of the Curve", Mike Sondalini<br />
7."Pump Handbook" , Third Edition , Igor j. Karassik , Joseph P.Messina , Paul cooper Charles C.Heald]]></description>
		<pubDate>Mon, 08 Nov 2010 18:50:19 +0000</pubDate>
		<guid isPermaLink="false">9766527f2b5d3e95d4a733fcfb77bd7e</guid>
	</item>
	<item>
		<title>Centrifugal Pumps: Understanding Cavitation</title>
		<link>http://www.cheresources.com/content/articles/fluid-flow/centrifugal-pumps-understanding-cavitation</link>
		<description><![CDATA[<p>Operating a pump under the condition of cavitation for even a short period of time can have damaging consequences for both the equipment and the process. Operating a pump at low flow conditions for an extended duration may also have damaging consequences for the equipment.</p><p> In <a href="../../../content/articles/fluid-flow/centrifugal-pumps-basic-concepts-of-operation-maintenance-and-troubleshooting" target="_blank">Part I</a> of this article, two basic requirements for trouble free operation and longer service life of centrifugal pumps are mentioned in brief:</p><ul><li>Prevent cavitation<br />
Cavitation of the pump should not occur throughout its operating capacity range. </li><li>Minimize low flow operation{parse block="google_articles"}<br />
Continuous operation of centrifugal pumps at low flows i.e. reduced capacities, leads to a number of unfavorable conditions. These include reduced motor efficiency, excessive radial thrusts, excessive temperature rise in the pumping fluid, internal re-circulation, etc. A certain minimum continuous flow (MCF) should be maintained during the pump operation. </li></ul><p>The condition of cavitation is essentially an indication of an abnormality in the pump suction system, whereas the condition of low flow indicates an abnormality in the entire pumping system or process. The two conditions are also inter-linked such that a low flow situation can also induce cavitation.</p><p>Cavitation is a common occurrence but is the least understood of all pumping problems. Cavitation means different things to different people. Some say when a pump makes a rattling or knocking sound along with vibrations, it is cavitating. Some call it slippage as the pump discharge pressure slips and flow becomes erratic. When cavitating, the pump not only fails to serve its basic purpose of pumping the liquid but also may experience internal damage, leakage from the seal and casing, bearing failure, etc.</p><p><span class="info">In summary, cavitation is an abnormal condition that can result in loss of production, equipment damage and worst of all, injury to personnel. </span></p><p>The plant engineer's job is to quickly detect the signs of cavitation, correctly identify the type and cause of the cavitation and eliminate it. A good understanding of the concept is the key to troubleshooting any cavitation related pumping problem.</p><p class="h1header">The Meaning of Cavitation</p><p>The term â€˜cavitation' comes from the Latin word cavus, which means a hollow space or a cavity. Webster's Dictionary defines the word â€˜cavitation' as the rapid formation and collapse of cavities in a flowing liquid in regions of very low pressure.</p><p>In any discussion on centrifugal pumps various terms like vapor pockets, gas pockets, holes, bubbles, etc. are used in place of the term cavities. These are one and the same thing and need not be confused. The term bubble shall be used hereafter in the discussion.</p><span class="info">In the context of centrifugal pumps, the term cavitation implies a dynamic process of formation of bubbles inside the liquid, their growth and subsequent collapse as the liquid flows through the pump.</span><p>Generally, the bubbles that form inside the liquid are of two types: Vapor bubbles or Gas bubbles.</p><ol><li>Vapor bubbles are formed due to the vaporisation of a process liquid that is being pumped. The cavitation condition induced by formation and collapse of vapor bubbles is commonly referred to as Vaporous Cavitation. </li><li>Gas bubbles are formed due to the presence of dissolved gases in the liquid that is being pumped (generally air but may be any gas in the system). The cavitation condition induced by the formation and collapse of gas bubbles is commonly referred to as Gaseous Cavitation. </li></ol><p>Both types of bubbles are formed at a point inside the pump where the local static pressure is less than the vapor pressure of the liquid (vaporous cavitation) or saturation pressure of the gas (gaseous cavitation).</p><p><em>Vaporous cavitation</em> is the most common form of cavitation found in process plants. Generally it occurs due to insufficiency of the available NPSH or internal recirculation phenomenon. It generally manifests itself in the form of reduced pump performance, excessive noise and vibrations and wear of pump parts. The extent of the cavitation damage can range from a relatively minor amount of pitting after years of service to catastrophic failure in a relatively short period of time.</p><p><em>Gaseous cavitation</em> occurs when any gas (most commonly air) enters a centrifugal pump along with liquid. A centrifugal pump can handle air in the range of Â½ % by volume. If the amount of air is increased to 6%, the pump starts cavitating. The cavitation condition <br />
is also referred to as Air binding. It seldom causes damage to the impeller or casing. The main effect of gaseous cavitation is loss of capacity.</p><p>The different types of cavitation, their specific symptoms and specific corrective actions shall be explored in the next part of the article. However, in order to clearly identify the type of cavitation, let us first understand the mechanism of cavitation, i.e. how cavitation occurs. Unless otherwise specified, the term cavitation shall refer to vaporous cavitation.</p><p><span class="h1header">Important Definitions</span></p><p>To enable a clear understanding of mechanism of cavitation, definitions of following important terms are explored:</p><ul><li>Static pressure</li><li>Dynamic pressure{parse block="google_articles"}</li><li>Total pressure</li><li>Static pressure head</li><li>Velocity head</li><li>Vapor pressure</li></ul><p class="h2header">Static Pressure (P<sub>s</sub>)</p><p>The static pressure in a fluid stream is the normal force per unit area on a solid boundary moving with the fluid. It describes the difference between the pressure inside and outside a system, disregarding any motion in the system. For instance, when referring to an air duct, static pressure is the difference between the pressure inside the duct and outside the duct, disregarding any airflow inside the duct. In energy terms, the static pressure is a measure of the potential energy of the fluid.</p><p class="h2header">Dynamic Pressure (P<sub>d</sub>)</p><p>A moving fluid stream exerts a pressure higher than the static pressure due to the kinetic energy (Â½ mv<sup>2</sup>) of the fluid. This additional pressure is defined as the dynamic pressure. The dynamic pressure can be measured by converting the kinetic energy of the fluid stream into the potential energy. In other words, it is pressure that would exist in a fluid stream that has been decelerated from its velocity â€˜v' to â€˜zero' velocity.</p><p class="h2header">Total Pressure (P<sub>t</sub>)</p><p>The sum of static pressure and dynamic pressure is defined as the total pressure. It is a measure of total energy of the moving fluid stream. i.e. both potential and kinetic energy.</p><p class="h2header">Relationship Between P<sub>s</sub>, P<sub>d</sub>, and P<sub>t</sub></p><p>In an incompressible flow, the relation between static, dynamic and total pressures can be found out using a simple device called Pitot tube (named after Henri Pitot in 1732) shown in Figure 1.</p><p>The Pitot tube has two tubes:</p><table class="imagecaption" border="0" align="right"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Sketch of a Pilot Tube" href="../../../../invision/uploads/images/articles/centrifugalpumps5b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps5b.gif" alt="pilot-tube" width="250" height="188" /></a></td></tr><tr><td>Figure 1: Sketch of a Pilot Tube</td></tr></tbody></table><ol><li><em>Static tube</em> (b'): The opening of the static tube is parallel to the direction of flow. It measures the static pressure, since there is no velocity component perpendicular to its opening.</li><li><em>Impact tube</em> (a): The opening of the impact tube is perpendicular to the flow direction. The point at the entrance of the impact tube is called as the stagnation point .At this point the kinetic energy of the fluid is converted to the potential energy. Thus, the impact tube measures the total pressure (also referred to as stagnation pressure) i.e. both static pressure and dynamic pressure (also referred to as impact pressure). </li></ol><p>The two tubes are connected to the legs of a manometer or equivalent device for measuring pressure.</p><p align="left">The relation between <strong>p<sub>s</sub>, p<sub>d</sub> </strong>and<strong> p<sub>t </sub></strong>can be derived by applying a simple energy balance.</p><table class="equationtable" border="0" align="center"><tbody><tr><td>Potential Energy + Kinetic Energy = Total Energy (Constant)</td><td class="equationnumber" align="right">Eq. (1)</td></tr></tbody></table><p align="left">As mentioned earlier, in the case of a fluid or gas the potential energy is represented by the static pressure and the kinetic energy by dynamic pressure. The kinetic energy is a function of the motion of the fluid, and of course it's mass. It is generally more convenient to use the density of the fluid (&rho;) as the mass representation.</p><table class="equationtable" border="0" align="center"><tbody><tr><td>K.E = p<sub>d</sub> = Â½ m v<sup>2 </sup>= Â½&rho; v<sup>2</sup></td><td class="equationnumber" align="right">Eq. (2)</td></tr></tbody></table><p align="left">The corresponding pressure balance equation is<sup>:</sup></p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centpumps_eq1b.gif" alt="centpumps_eq1b" width="146" height="61" /></td><td class="equationnumber" align="right">Eq. (3)</td></tr></tbody></table><p align="left">In place of the pressure terms as used above, it is more appropriate to speak of the energy during pumping as the energy per unit weight of the liquid pumped and the units of energy expressed this way are foot-pounds per pound (Newton-meters per Newton) or just feet (meters) i.e. the units of head. Thus the energy of the liquid at a given point in flow stream can be expressed in terms of head of liquid in feet.</p><p>The pressure term can be converted to head term by division with the factor â€˜&rho; g'. For unit inter-conversions the factor â€˜&rho; g/g<sub>c</sub>'<strong>. </strong>should be used in place of â€˜&rho;g'.</p><p class="h2header">Static Pressure Head</p><p>The head corresponding to the static pressure is called as the static pressure head.</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centpumps_eq4b.gif" alt="centpumps_eq4b" width="250" height="57" /></td><td class="equationnumber" align="right">Eq. (4)</td></tr></tbody></table><p class="h2header">Velocity Head</p><p>The head corresponding to dynamic pressure is called the velocity head.</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centpumps_eq5b.gif" alt="centpumps_eq5b" width="333" height="70" /></td><td class="equationnumber" align="right">Eq. (5)</td></tr></tbody></table><p>From the reading h<sub>m</sub>of the manometer velocity of flow can be calculated and thus velocity head can be calculated. The pressure difference, dP (P<sub>t </sub>- P<sub>s)</sub> indicated by the manometer is the dynamic pressure.</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/centpumps_eq6b.gif" alt="centpumps_eq6b" width="242" height="54" /></td><td class="equationnumber" align="right">Eq. (6)</td></tr><tr><td><img src="../../../../invision/uploads/images/articles/centpumps_eq7b.gif" alt="centpumps_eq7b" width="319" height="60" /></td><td class="equationnumber" align="right">Eq. (7)</td></tr></tbody></table><p class="h2header">Vapor Pressure (P<sub>v</sub>)</p><p>Vapor pressure is the pressure required to keep a liquid in a liquid state. If the pressure applied to the surface of the liquid is not enough to keep the molecules pretty close together, the molecules will be free to separate and roam around as a gas or vapor. The vapor pressure is dependent upon the temperature of the liquid. Higher the temperature, higher will be the vapor pressure.</p><p class="h1header">Mechanism of Cavitation</p><p>The phenomenon of cavitation is a stepwise process as shown in Figure 2.</p><table class="imagecaption" border="0" align="left"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Steps in Cavitation" href="../../../../invision/uploads/images/articles/centrifugalpumps6b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps6b.gif" alt="stps-in-cavitation" width="250" height="185" /></a></td></tr><tr><td>Figure 2: Steps in Cavitation</td></tr></tbody></table><p>The bubbles form inside the liquid when it vaporises i.e. phase change from liquid to vapor. But how does vaporization of the liquid occur during a pumping operation?</p><p>Vaporization of any liquid inside a closed container can occur if either pressure on the liquid surface decreases such that it becomes equal to or less than the liquid vapor pressure at the operating temperature, or the temperature of the liquid rises, raising the vapor pressure such that it becomes equal to or greater than the operating pressure at the liquid surface. For example, if water at room temperature (about 77 Â°F) is kept in a closed container and the system pressure is reduced to its vapor pressure (about 0.52 psia), the water quickly changes to a vapor. Also, if the operating pressure is to remain constant at about 0.52 psia and the temperature is allowed to rise above 77 <sup>Â°</sup>F, then the water quickly changes to a vapor.</p><p>Just like in a closed container, vaporization of the liquid can occur in centrifugal pumps when the local static pressure reduces below that of the vapor pressure of the liquid at the pumping temperature.</p><span class="info">The vaporisation accomplished by addition of heat or the reduction of static pressure without dynamic action of the liquid is excluded from the definition of cavitation. For the purposes of this article, only pressure variations that cause cavitation shall be explored. Temperature changes must be considered only when dealing with systems that introduce or remove heat from the fluid being pumped.</span>  <p class="h2header">Step One: Formation of Bubbles</p><p>To understand vaporization, two important points to remember are:</p><ol><li>We consider only the static pressure and not the total pressure when determining if the system pressure is less than or greater than the liquid vapor pressure. The total pressure is the sum of the static pressure and dynamic pressure (due to velocity). {parse block="google_articles"}</li><li>The terms pressure and head have different meanings and they should not be confused. As a convention in this article, the term "pressure" shall be used to understand the concept of cavitation whereas the term "head" shall be used in equations.</li></ol><p>Thus, the key concept is - vapor bubbles form due to vaporization of the liquid being pumped when the local static pressure at any point inside the pump becomes equal to or less than the vapor pressure of the liquid at the pumping temperature.</p><p>The reduction in local static pressure at any point inside the pump can occur under two conditions:</p><ol><li>The actual pressure drop in the external suction system is greater than that considered during design. As a result, the pressure available at pump suction is not sufficiently high enough to overcome the design pressure drop inside the pump.</li><li>The actual pressure drop inside the pump is greater than that considered during the pump design.</li></ol><p><span style="text-decoration: underline;">Pressure Reduction in the External Suction of the Pump</span></p><table class="imagecaption" border="0" align="left"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="External Suction System" href="../../../../invision/uploads/images/articles/centrifugalpumps7b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps7b.gif" alt="centrifugal-pumps" width="250" height="188" /></a></td></tr><tr><td>Figure 3: External Suction System</td></tr></tbody></table><p>A simple sketch of a pump external suction system in shown in Figure 3. The nomenclature used for this figure is as follows:</p><p>&rho; - Liquid density in lb<sub>m</sub> / ft<sup>3</sup></p><p>G - Acceleration due to gravity in ft / s<sup>2</sup></p><p>Psn - p refers to local static pressure (absolute). Subscript s refers to suction and subscript n refers to the point of measurement. The pressure at any point can be converted to the head term by division with the factor - <em>&rho;</em> g</p><p>p<sub>s1</sub> - Static pressure (absolute) of the suction vessel in psia</p><p>hp<sub>s1</sub> - Static pressure head i.e. absolute static pressure on the liquid surface in the suction vessel, converted to feet of head (p<sub>s1</sub>/ <em>&rho;</em> g/g<sub>c</sub>). If the system is open, hp<sub>s1</sub> equals the atmospheric pressure head.</p><p>v<sub>s1</sub> - Liquid velocity on the surface in the suction vessel in ft/s</p><p>hv<sub>s1 </sub>- Velocity head i.e. the energy of a liquid as a result of its motion at some velocity â€˜v<sub>s1</sub>'. (v<sup>2</sup><sub>s1</sub> / 2g). It is the equivalent head in feet through which the liquid would have to fall to acquire the same velocity, or the head necessary to accelerate the liquid to velocity v<sub>s1</sub>. In a large suction vessel, the velocity head is practically zero and is typically ignored in calculations.</p><p>h<sub>s</sub> - Static suction head. . . . i.e. head resulting from elevation of the liquid relative to the pump centerline. If the liquid level is above pump centerline, h<sub>S</sub> is positive. If the liquid level is below pump centerline, h<sub>S</sub> is negative. A negative h<sub>S</sub> condition is commonly referred to as "suction lift".</p><p>hf<sub>s</sub> - Friction head i.e. the head required to overcome the resistance to flow in the pipe, valves and fittings between points A and B, inclusive of the entrance losses at the point of connection of suction piping to the suction vessel (point A in Figure 1). The friction head is dependent upon the size, condition and type of pipe, number and type of fittings, valves, flow rate and the nature of the liquid. The friction head varies as the square of the average velocity of the flowing fluid.</p><p>p<sub>s2</sub> - Absolute static pressure at the suction flange in psia</p><p>hp<sub>s2</sub> - Static pressure head at the suction flange i.e. absolute pressure of the liquid at the suction flange, converted to feet of head - p<sub>s2</sub> / &rho; g/g<sub>c</sub></p><p>v<sub>s2</sub> - Velocity of the moving liquid at the suction flange in ft/s. The pump suction piping is sized such that the velocity at the suction remains low.</p><p>hv<sub>s2 </sub>- Velocity head at suction flange i.e. the energy of a liquid as a result of its motion at average velocity â€˜v<sub>s2</sub>' equal to v<sup>2</sup><sub>s2</sub> / 2g.</p><p>p<sub>v</sub> - Absolute vapor pressure of the liquid at operating temperature in psia.</p><p>hp<sub>v </sub>- Vapor Pressure head i.e. absolute vapor pressure converted to feet of head (p<sub>v</sub> / &rho; g/g<sub>c</sub>).</p><p>H<sub>s </sub>- Total Suction Head available at the suction flange in ft.</p><p>Note: As pressure is measured in absolute, total head is also in absolute.</p><p>The pump takes suction from a vessel having a certain liquid level. The vessel can be pressurised (as shown in the Figure 3) or can be at atmospheric pressure or under vacuum.</p><p class="f-default"><span style="text-decoration: underline;">Calculation of the Total Suction Head, H<sub>s</sub></span></p><p>The external suction system of the pump provides a certain amount of head at the suction flange. This is referred to as Total Suction Head (TSH), H<sub>s</sub>.</p><p>TSH can be calculated by application of the energy balance. The incompressible liquid can have energy in the form of velocity, pressure or elevation. Energy in various forms is either added to or subtracted from the liquid as it passes through the suction piping. The head term in feet (or meters) is used as an exp<b></b>ression of the energy of the liquid at any given point in the flow stream.</p><p>As shown in Figure 3, the total suction head, H<sub>s</sub>, available at the suction flange is given by the equation,</p><table class="equationtable" border="0" align="center"><tbody><tr><td>H<sub>s </sub>= hp<sub>s1 </sub>+ hv<sub>s1 </sub>+ h<sub>s</sub> - hf<sub>s </sub>+ hv<sub>s2</sub></td><td class="equationnumber" align="right">Eq. (8)</td></tr></tbody></table><p>For an existing system, Hs<sub> </sub>can also be calculated from the pressure gauge reading at pump suction flange,</p><table class="equationtable" border="0" align="center"><tbody><tr><td>H<sub>s </sub>= hp<sub>s2 </sub>+ hv<sub>s2</sub></td><td class="equationnumber" align="right">Eq. (9)</td></tr></tbody></table><p>Equations8 and9 above include the velocity head terms hv<sub>s1 </sub>and<sub> </sub>hv<sub>s2</sub>,<sub> </sub>respectively.</p><p><span style="text-decoration: underline;">Velocity Head</span></p><p>There is a lot of confusion as to whether the velocity head terms should be added or subtracted in the head calculations. To avoid any confusion remember the following:</p><p><span class="info">Just like a static tube of Pitot, a pressure gauge can measure only the static pressure at the point of connection. It does not measure the dynamic pressure as the opening of the gauge impulse pipe is parallel to the direction of flow and there is no velocity component perpendicular to its opening.</span></p><table class="imagecaption" border="0" align="left"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Measuring Static Pressure" href="../../../../invision/uploads/images/articles/centrifugalpumps8b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps8b.gif" alt="centrifugal-pumps" width="250" height="188" /></a></td></tr><tr><td>Figure 4: Measuing Static Pressure</td></tr></tbody></table><p>In Figure 4 below, flow through a pipe of varying cross section area is shown. As the cross section at point B reduces, the velocity of flow increases. The rise in kinetic energy happens at the expense of potential energy. Assuming that there are no friction losses, the total energy (sum of potential energy and kinetic energy) of fluid at point A, B and C remains constant. The pressure gauges at point A, B and C measure only the potential energy i.e. the static pressures at respective points. The drop in static pressure from 10 psi (point A) to 5 psi (point B') occurs owing to rise the dynamic pressure by 5 psi i.e. increase in velocity at point B. However the gauge at point B records only the static pressure. The velocity decreases from point B to C and the static pressure is recovered again to 10 psi.</p><p>At a particular point of flow, the total pressure is the sum of the static pressure and the dynamic pressure. Thus, theoretically, the velocity head terms must always be added and not subtracted, in calculating Total Suction Head (TSH), H<sub>s</sub>. However, practically speaking, the value of these terms is not significant in comparison to the other terms in the equation.</p><ul><li>hv<sub>s1</sub>: In industrial scale suction vessels, the value of hv<sub>s1 </sub>is practically zero and it can be safely ignored. </li><li>hv<sub>s2:</sub> It is good piping design practice to reduce the friction losses and prevent unnecessary flow turbulence by sizing the suction pipes for fluid velocities in the <em>three to five feet per second range only.</em> The velocity head corresponding to a velocity of 5 ft/s at the suction flange is only about 0.4 ft. Thus, for all practical purposes, in high head systems the velocity head at the suction flange is not significant and can be safely ignored. Only in low head systems does the factor need to be considered. </li></ul><p>Therefore, neglecting the velocity head terms, Equations8 and9 simplify to:</p><table class="equationtable" border="0" align="center"><tbody><tr><td>H<sub>s </sub>= hp<sub>s1 </sub>+ h<sub>s</sub> - hf<sub>s </sub></td><td class="equationnumber" align="right">Eq. (10)</td></tr></tbody></table><p>Â </p><table class="equationtable" border="0" align="center"><tbody><tr><td>H<sub>s </sub>= hp<sub>s2 </sub></td><td class="equationnumber" align="right">Eq. (11)</td></tr></tbody></table><p>Two important inferences can be drawn from the above equations:</p><ul><li>The pressure reduction in the external suction system is primarily due to frictional loss in the suction piping (Equation 10).</li><li>For all practical purposes, the total head at the suction flange is the static pressure head at the suction flange (Equation 11).</li></ul><p>Therefore the pump's external suction system should be designed such that the static pressure available at the suction flange is always positive and higher than the vapor pressure of the liquid at the pumping temperature.</p><p>For no vaporization at pump suction flange,</p><table class="equationtable" border="0" align="center"><tbody><tr><td>(p<sub>s2 </sub>> p<sub>v)</sub> or<sub> </sub>(p<sub>s2 </sub>- p<sub>v </sub>) or (hp<sub>s2 </sub>- hp<sub>v</sub> ) > 0</td><td class="equationnumber" align="right">Eq. (12)</td></tr></tbody></table><p>As the liquid enters the pump, there is a further reduction in the static pressure. If the value of p<sub>s2 </sub>is not sufficiently higher than p<sub>v</sub>, at some point inside the pump the static pressure can reduce to the value of p<sub>v</sub>. In pumping terminology, the head difference term corresponding to Equation 5 (hp<sub>s2 </sub>- hp<sub>v</sub>) is called the Net Positive Suction Head or NPSH. The NPSH term shall be explored in detail in the next part of the article. For now, the readers should focus only on how the static pressure within the pump may be reduced to a value lower than that of the liquid vapor pressure.</p><p><span style="text-decoration: underline;">Pressure Reduction in the Internal Suction System of the Pump</span></p><p>The pressure of the fluid at the suction flange is further reduced inside the internal suction system of the pump.</p><table class="imagecaption" border="0" align="center"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Internal Pump Locations" href="../../../../invision/uploads/images/articles/centrifugalpumps9b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps9b.gif" alt="centrifugal-pumps" width="250" height="188" /></a></td><td><a class='resized_img' rel='lightbox[2]' title="Internal Pump Nomenclature" href="../../../../invision/uploads/images/articles/centrifugalpumps10b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps10b.gif" alt="centrifugal-pumps" width="250" height="188" /></a></td></tr><tr><td>Figure 5: Internal Pump Locations</td><td>Figure 6: Internal Pump Nomenclature</td></tr></tbody></table><p>The internal suction system is comprised of the pump's suction nozzle and impeller. Figures 5 and 6 depict the internal parts in detail. A closer look at the graphic is a must in understanding the mechanism of pressure drop inside the pump.</p><p align="left">In Figure 7, it can be seen that the passage from the suction flange (point 2) to the impeller suction zone (point 3) and to the impeller eye (point 4) acts like a venturi i.e. there is gradual reduction in the cross-section area.</p><table class="imagecaption" border="0" align="left"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Pump Internal Suction System" href="../../../../invision/uploads/images/articles/centrifugalpumps11b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps11b.gif" alt="centrifugal-pumps" width="250" height="109" /></a></td></tr><tr><td>Figure 7: Pump Internal Suction System</td></tr></tbody></table><p align="left">In the impeller, the point of minimum radius (r<sub>eye</sub>) with reference to pump centerline is referred to as the "eye" of the impeller (Figure 8).</p><p>According to Bernoulli's principle, when a constant amount of liquid moves through a path of decreasing cross-section area (as in a venturi), the velocity increases and the static pressure decreases. In other words, total system energy i.e. sum of the potential and kinetic energy, remains constant in a flowing system (neglecting friction). The gain in velocity occurs at the expense of pressure. At the point of minimum cross-section, the velocity is at a maximum and the static pressure is at a minimum.</p><p>The pressure at the suction flange, p<sub>s2</sub> (Point 2) decreases as the liquid flows from the suction flange, through the suction nozzle and into the impeller eye. This decrease in pressure occurs not only due to the venturi effect but also due to the friction in the inlet passage. However, the pressure drop due to friction between the suction nozzle and the impeller eye is comparatively small for most pumps. However the pressure reduction due to the venturi effect is very significant as the velocity at the impeller increases to 15 to 20 ft/s. There is a further drop in pressure due to shock and turbulence as the liquid strikes and loads the edges of impeller vanes. The net effect of all the pressure drops is the creation of a very low-pressure area around the impeller eye and at the beginning of the trailing edge of the impeller vanes.</p><table class="imagecaption" border="0" align="center"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Impeller Eye" href="../../../../invision/uploads/images/articles/centrifugalpumps12b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps12b.gif" alt="centrifugal-pumps" width="250" height="188" /></a></td><td><a class='resized_img' rel='lightbox[2]' title="Pressure Profile in a Pump" href="../../../../invision/uploads/images/articles/centrifugalpumps13b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps13b.gif" alt="centrifugal-pumps" width="250" height="188" /></a></td></tr><tr><td>Figure 8: Impeller Eye</td><td>Figure 9: Pressure Profile in a Pump</td></tr></tbody></table><p>The pressure reduction profile within the pump is depicted in Figure 9.</p><p align="left">As shown in Figure 9, the impeller eye is the point where the static pressure is at a minimum, p<sub>4. </sub>During pump operation, if the local static pressure of the liquid at the lowest pressure becomes equal to or less than the vapor pressure (p<sub>v</sub>)<sub> </sub>of the liquid at the operating temperature, vaporization of the liquid (the formation of bubbles) begins i.e. when p<sub>4 </sub><= p<sub>v.</sub></p><p align="left">It is at the beginning of the trailing edge of the vanes near the impeller eye where the pressure actually falls to below the liquid vapor pressure. The region of bubble formation is shown in Figure 10.</p><table class="imagecaption" border="0" align="center"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Impeller Cavitation Regions" href="../../../../invision/uploads/images/articles/centrifugalpumps14b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps14b.gif" alt="centrifugal-pumps" width="250" height="188" /></a></td></tr><tr><td>Figure 10: Impeller Cavitation Regions</td></tr></tbody></table><p align="left">In summary, vaporization of the liquid (bubble formation) occurs due to the reduction of the static pressure to a value below that of the liquid vapor pressure. The reduction of static pressure in the external suction system occurs mainly due to friction in suction piping. The reduction of static pressure in the internal suction system occurs mainly due to the rise in the velocity at the impeller eye.</p><p class="h2header" align="left">Step Two: Growth of Bubbles</p><p class="f-default" align="left">Unless there is no change in the operating conditions, new bubbles continue to form and old bubbles grow in size. The bubbles then get carried in the liquid as it flows from the impeller eye to the impeller exit tip along the vane trailing edge. Due to impeller rotating action, the bubbles attain very high velocity and eventually reach the regions of high pressure within the impeller where they start collapsing. The life cycle of a bubble has been estimated to be in the order of 0.003 seconds.</p><p class="h2header" align="left">Step Three: Collapse of Bubbles</p><table class="imagecaption" border="0" align="left"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Collapse of Vapor Bubbles" href="../../../../invision/uploads/images/articles/centrifugalpumps15b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps15b.gif" alt="vapor-bubbles" width="250" height="188" /></a></td></tr><tr><td>Figure 11: Collapse of Vapor Bubbles</td></tr></tbody></table><p>As the vapor bubbles move along the impeller vanes, the pressure around the bubbles begins to increase until a point is reached where the pressure on the outside of the bubble is greater than the pressure inside the bubble. The bubble collapses. The process is not an explosion but rather an implosion (inward bursting). Hundreds of bubbles collapse at approximately the same point on each impeller vane. Bubbles collapse non-symmetrically such that the surrounding liquid rushes to fill the void forming a liquid microjet. The micro jet subsequently ruptures the bubble with such force that a hammering action occurs.Bubble collapse pressures greater than 1 GPa (145x10<sup>6</sup> psi) have been reported. The highly localized hammering effect can pit the pump impeller. The pitting effect is illustrated schematically in Figure 11.</p><p>After the bubble collapses, a shock wave emanates outward from the point of collapse. This shock wave is what we actually hear and what we call "cavitation". The implosion of bubbles and emanation of shock waves (red color) is shown in a small video clip shown below.</p><p>In nutshell, the mechanism of cavitation is all about formation, growth and collapse of bubbles inside the liquid being pumped. But how can the knowledge of mechanism of cavitation can really help in troubleshooting a cavitation problem. The concept of mechanism can help in identifying the type of bubbles and the cause of their formation and collapse. The troubleshooting method shall be explored in detail in the next part of the article.</p><p>Next let us explore the general symptoms of cavitation and its affects on pump performance.</p><p><strong></strong></p><table class="imagecaption" border="0" align="center"><tbody><tr><td><iframe title="YouTube video player" class="youtube-player" type="text/html" width="480" height="390" src="http://www.youtube.com/embed/Qw97DkOYYrg?rel=0" frameborder="0" allowFullScreen></iframe></td></tr><tr><td>Video: Cavitation in a Centrifugal Pump</td></tr></tbody></table> <span class="h1header">General Symptoms of Cavitation and Its Affects on Pump Performance and Pump Parts</span><p>Perceptible indications of the cavitation during pump operation are more or less loud noises, vibrations and an unsteadily working pump. Fluctuations in flow and discharge pressure take place with a sudden and drastic reduction in head rise and pump capacity. Depending upon the size and quantum of the bubbles formed and the severity of their collapse, the pump faces problems ranging from a partial loss in{parse block="google_articles"} capacity and head to total failure in pumping along with irreparable damages to the internal parts. It requires a lot of experience and thorough investigation of effects of cavitation on pump parts to clearly identify the type and root causes of cavitation.</p><p>A detailed description of the general symptoms is given as follows.</p><p class="h2header">Reduction in Capacity of the Pump</p><p>The formation of bubbles causes a volume increase decreasing the space available for the liquid and thus diminish pumping capacity. For example, when water changes state from liquid to gas its volume increases by approximately 1,700 times<strong>. </strong>If the bubbles get big enough at the eye of the impeller, the pump "chokes" i.e. loses all suction resulting in a total reduction in flow. The unequal and uneven formation and collapse of bubbles causes fluctuations in the flow and the pumping of liquid occurs in spurts. This symptom is common to all types of cavitations.</p><p class="h2header">Decrease in the Head Developed</p><p>Bubbles unlike liquid are compressible. The head developed diminishes drastically because energy has to be expended to increase the velocity of the liquid used to fill up the cavities, as the bubbles collapse. As mentioned earlier, The Hydraulic Standards Institute defines cavitation as condition of 3 % drop in head developed across the pump. Like reduction in capacity, this symptom is also common to all types of cavitations.</p><table class="imagecaption" border="0" align="center"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Pump Performance Curves" href="../../../../invision/uploads/images/articles/centrifugalpumps16b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps16b.gif" alt="pump-curves" width="250" height="188" /></a></td></tr><tr><td>Figure 12: Pump Performance Curves</td></tr></tbody></table><p>Thus, the hydraulic effect of a cavitating pump is that the pump performance drops off of its expected performance curve, referred to as break away, producing a lower than expected head and flow. The Figure 12 depicts the typical performance curves. The solid line curves represent a condition of adequate NPSHa whereas the dotted lines depict the condition of inadequate NPSHa i.e. the condition of cavitation.</p><p class="h2header">Abnormal Sound and Vibration</p><p>It is movement of bubbles with very high velocities from low-pressure area to a high-pressure area and subsequent collapse that creates shockwaves producing abnormal sounds and vibrations. It has been estimated that during collapse of bubbles the pressures of the order of 10<sup>4</sup> atm develops.</p><p>The sound of cavitation can be described as similar to small hard particles or gravel rapidly striking or bouncing off the interior parts of a pump or valve. Various terms like rattling, knocking, crackling are used to describe the abnormal sounds. The sound of pumps operating while cavitating can range from a low-pitched steady knocking sound (like on a door) to a high-pitched and random crackling (similar to a metallic impact). People can easily mistake cavitation for a bad bearing in a pump motor. To distinguish between the noise due to a bad bearing or cavitation, operate the pump with no flow. The disappearance of noise will be an indication of cavitation.</p><p>Similarly, vibration is due to the uneven loading of the impeller as the mixture of vapor and liquid passes through it, and to the local shock wave that occurs as each bubble collapses. Very few vibration reference manuals agree on the primary vibration characteristic associated with pump cavitation. Formation and collapsing of bubbles will alternate periodically with the frequency resulting out of the product of speed and number of blades. Some suggest that the vibrations associated with cavitation produce a broadband peak at high frequencies above 2,000 Hertz. Some suggest that cavitation follows the vane pass frequency (number of vanes times the running speed frequency) and yet another indicate that it affects peak vibration amplitude at one times running speed. All of these indications are correct in that pump cavitation can produce various vibration frequencies depending on the cavitation type, pump design, installation and use. The excessive vibration caused by cavitation often subsequently causes a failure of the pump's seal and/or bearings. This is the most likely failure mode of a cavitating pump,</p><p class="h2header">Damage to Pump Parts</p><p><span style="text-decoration: underline;">Cavitation Erosion or Pitting</span></p><table class="imagecaption" border="0" align="left"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Photographic Evidence of Cavitation" href="../../../../invision/uploads/images/articles/centrifugalpumps17b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps17b.gif" alt="cavitation" width="250" height="188" /></a></td></tr><tr><td>Figure 13: Photographic Evidence<br />
of Cavitation</td></tr></tbody></table><p>During cavitation, the collapse of the bubbles occurs at sonic speed ejecting destructive micro jets of extremely high velocity (up to 1000 m/s) liquid strong enough to cause extreme erosion of the pump parts, particularly impellers. The bubble is trying to collapse from all sides, but if the bubble is lying against a piece of metal such as the impeller or volute it cannot collapse from that side. So the fluid comes in from the opposite side at this high velocity and bangs against the metal creating the impression that the metal was hit with a "ball pin hammer". The resulting long-term material damage begins to become visible by so called</p><p>Pits (see Figure 11), which are plastic deformations of very small dimensions (order of magnitude of micrometers). The damage caused due to action of bubble collapse is commonly referred as Cavitation erosion or pitting. The Figure 13 depicts the cavitation pitting effect on impeller and diffuser surface.</p><p align="left">Cavitation erosion from bubble collapse occurs primarily by fatigue fracture due to repeated bubble implosions on the cavitating surface, if the implosions have sufficient impact force. The erosion or pitting effect is quite similar to sand blasting. High head pumps are more likely to suffer from cavitation erosion, making cavitation a "high-energy" pump phenomenon.</p><p align="left">The most sensitive areas where cavitation erosion has been observed arethe low-pressure sides of the impeller vanes near the inlet edge. The cavitation erosion damages at the impeller are more or less spread out. The pitting has also been observed on impeller vanes, diffuser vanes, and impeller tips etc. In some instances, cavitation has been severe enough to wear holes in the impeller and damage the vanes to such a degree that the impeller becomes completely ineffective. A damaged impeller is shown in Figure 14.</p><table class="imagecaption" border="0" align="center"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Cavitation Damage on Impellers" href="../../../../invision/uploads/images/articles/centrifugalpumps18b.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_centrifugalpumps18b.gif" alt="cavitation-damage" width="250" height="188" /></a></td></tr><tr><td>Figure 14: Cavitation Damage on Impellers</td></tr></tbody></table><p align="left">The damaged impeller shows that the shock waves occurred near the outside edge of the impeller, where damage is evident. This part of the impeller is where the pressure builds to its highest point. This pressure implodes the gas bubbles, changing the water's state from gas into liquid. When cavitation is less severe, the damage can occur further down towards the eye of the impeller<strong>. </strong>A careful investigation and diagnosis of point of the impeller erosion on impeller, volute, diffuser etc. can help predict the type and cause of cavitation.</p><p>The extent of cavitation erosion or pitting depends on a number of factors like presence of foreign materials in the liquid, liquid temperature, age of equipment and velocity of the collapsing bubble.</p><p><span style="text-decoration: underline;">Mechanical Deformation</span></p><p>Apart from erosion of pump parts, in bigger pumps, longer duration of cavitation condition can result in unbalancing (due to un-equal distribution in bubble formation and collapse) of radial and axial thrusts on the impeller. This unbalancing often leads to following mechanical problems:</p><p><strong></strong></p><ul><li>bending and deflection of shafts,</li><li>bearing damage and rubs from radial vibration,</li><li>thrust bearing damage from axial movement, </li><li>breaking of impeller check-nuts, </li><li>seal faces damage etc.</li></ul><p>These mechanical deformations can completely wreck the pump and require replacement of parts. The cost of such replacements can be huge.</p><p><span style="text-decoration: underline;">Cavitation Corrosion</span></p><p>Frequently cavitation is combined with corrosion. The implosion of bubbles destroys existing protective layers making the metal surface permanently activated for the chemical attack. Thus, in this way even in case of slight cavitation it may lead to considerable damage to the materials. The rate of erosion may be accentuated if the liquid itself has corrosive tendencies such as water with large amounts of dissolved oxygen to acids.</p><p class="h2header">Cavitation- The Pump Heart Attack</p><p>Thus fundamentally, cavitation refers to an abnormal condition inside the pump that arises during pump operation due to formation and subsequent collapse of vapor filled cavities or bubbles inside the liquid being pumped. The condition of cavitation can obstruct the pump, impair performance and flow capacity, and damage the impeller and other sensitive components. <em>In short, Cavitation can be termed as "the heart attack of the pump".</em></p><p class="h1header">References</p><ol type="1"><li>" New Monitoring Systems Warns of Cavitation and Low Flow Instabilities", Pumps and Systems Magazine, April 1996, Robert A. Atkins, Chung E.Lee, Henry F.Taylor </li><li>"Understanding Pump Cavitation", Chemical Processing, Feb 1997, W.E. Nelson </li><li>"Centrifugal pumps operation at off-design conditions", Chemical Processing April, May, June 1987, Igor J. Karassik {parse block="google_articles"}</li><li>"Understanding NPSH for Pumps", Technical Publishing Co. 1975, Travis F. Glover </li><li>"Centrifugal Pumps for General Refinery Services", Refining Department, API Standard 610, 6th Edition, January 1981 </li><li>"<a href="http://www.driedger.ca/" target="_blank">Controlling Centrifugal Pumps</a>", Hydrocarbon Processing, July 1995, Walter Driedger </li><li>"Don't Run Centrifugal Pumps Off The Right Side of the Curve", Mike Sondalini </li><li>"Pump Handbook", Third Edition, Igor j. Karassik, Joseph P.Messina, Paul cooper Charles C.Heald </li><li>"Centrifugal Pumps and System Hydraulics", <em>Chemical Engineering</em>, October 4, 1982, pp. 84-106. , Karassik, I.J., </li><li>Unit Operations of Chemical Engineering (5th Edition), McGraw-Hill, 1993, pp. 188-204. , McCabe, W.L., J.C. Smith, and P. Harriott, </li><li>"CAVISMONITOR: Cavitation Monitoring In Hydraulic Machines With Aid Of A Computer Aided Visualization Method", Bernd Bachert, Henrik Lohrberg, Bernd Stoffel Laboratory for Turbomachinery and Fluid Power Darmstadt University of Technology Magdalenenstrasse 4, 64289 Darmstadt, Germany </li><li>"The Hydraulic Pump Inlet Condition: Impact on Hydraulic Pump Cavitation Potential", G.E. Totten and R.J. Bishop, Jr.Union Carbide Corporation Tarrytown, NY </li><li>"Study of Cavitation Collapse Pressure and Erosion, Part I: A Method for Measurement of Collapse Pressure", Wear, 1989, Vol. 133, p.219-232, T. Okada, Y. Iwai and K. Awazu, </li><li>"Key Centrifugal Pump Parameters and How They Impact Your Applications" Part 1 Pumps and Systems: They Go Together, Doug Kriebel, PE, Kriebel Engineered Equipment </li><li>"How to compute Net Positive Suction Head for centrifugal pumps". J. J. Paugh, P.E.Vice President, Engineering, Warren Pumps Inc. </li><li>"New Monitoring System Warns of Cavitation and Low-Flow Instabilities", APRIL 1996 PUMPS AND SYSTEMS MAGAZINE, Robert A. Atkins, Chung E. lee and Henry F. Taylor </li><li>"Detecting Cavitation in Centrifugal Pumps", Experimental Results of the Pump Laboratory, Jeremy Jensen Project Engineer, Bentley Rotor Dynamics Research Corporation </li></ol>]]></description>
		<pubDate>Mon, 08 Nov 2010 18:50:19 +0000</pubDate>
		<guid isPermaLink="false">3636638817772e42b59d74cff571fbb3</guid>
	</item>
	<item>
		<title>Understanding Compressible Flow</title>
		<link>http://www.cheresources.com/content/articles/fluid-flow/understanding-compressible-flow</link>
		<description><![CDATA[<p>Understanding the flow of compressible fluids in pipes is necessary for a robust design of process plants. The main difference between incompressible fluid, like water, and compressible fluid, vapor, is the greater change in pressure and density. This makes the calculations for compressible fluids slightly more difficult. Understanding how the fluid properties change is critical when dealing with these fluids. The ability of compressible fluids, unlike incompressible fluids, to "choke" further complicates matters.</p> <p>{parse block="google_articles"}Practical applications of this topic include sizing relief valve outlet laterals and low-pressure compressor suction lines. These pose a special challenge as the velocities and pressure changes are high.</p><p><span class="h1header">Adiabatic Flow of a Compressible Fluid Through a Conduit</span></p><p>Flow through pipes in a typical plant where line lengths are short, or the pipe is well insulated can be considered adiabatic. A typical situation is a pipe into which gas enters at a given pressure and temperature and flows at a rate determined by the length and diameter of the pipe and downstream pressure. As the line gets longer friction losses increase and the following occurs:</p><ol><li>Pressure decreases</li><li>Density decreases</li><li>Velocity increases</li><li>Enthalpy decreases</li><li>Entropy increases</li></ol><p>The question is "will the velocity continue to increasing until it crosses the sonic barrier?" The answer is NO. The maximum velocity always occurs at the end of the pipe and continues to increase as the pressure drops until reaching Mach 1. The velocity cannot cross the sonic barrier in adiabatic flow through a conduit of constant cross section. If an effort is made to decrease downstream pressure further, the velocity, pressure, temperature and density remain constant at the end of the pipe corresponding to Mach 1 conditions. The excess pressure drop is dissipated by shock waves at the pipe exit due to sudden expansion. If the line length is increased to drop the pressure further the mass flux decreases, so that Mach 1 is maintained at the end of the pipe.</p><p>Analyzing the adiabatic flow using energy and mass balance yields the following analyses along with this nomenclature:</p><table class="datatable" style="border: #000000 1px solid;" border="1" width="100%" align="center"><caption>Table 1: Nomenclature</caption><tbody><tr><td width="25%" bgcolor="#c2c285">Variable</td><td width="25%" bgcolor="#c2c285">Definition</td><td width="25%" bgcolor="#c2c285">Variable</td><td width="25%" bgcolor="#c2c285">Definition</td></tr><tr><td width="25%">h</td><td width="25%">enthalpy/unit mass</td><td width="25%">hst</td><td width="25%">stagnation enthalpy</td></tr><tr><td width="25%">v</td><td width="25%">velocity</td><td width="25%">Ma</td><td width="25%">Mach number</td></tr><tr><td width="25%">g</td><td width="25%">gravitational constant</td><td width="25%">M</td><td width="25%">molecular weight</td></tr><tr><td width="25%">z</td><td width="25%">elevation</td><td width="25%">T</td><td width="25%">temperature</td></tr><tr><td width="25%">Q</td><td width="25%">heat flow</td><td width="25%">P</td><td width="25%">pressure</td></tr><tr><td width="25%">Ws</td><td width="25%">shaft work</td><td width="25%">R</td><td width="25%">gas constant</td></tr><tr><td width="25%">Cp</td><td width="25%">specific heat (constant pressure)</td><td width="25%">Z</td><td width="25%">compressibility</td></tr><tr><td width="25%">r</td><td width="25%">density</td><td width="25%">g</td><td width="25%">Cp/Cv</td></tr><tr><td width="25%">G</td><td width="25%">mass flux</td><td width="25%">Â </td><td width="25%">Â </td></tr></tbody></table> <br /><p class="h2header">Analysis One</p><p>This analysis derives the relationship between the stagnation temperature, flowing temperature, and the Mach number for a flowing ideal gas. Stagnation temperature is the temperature a flowing gas rises to when it is brought isentropically to rest, thereby converting its kinetic energy into enthalpy.</p><p>Conservation of energy requires that the energy balances:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow1.gif" alt="compressible_flow1" width="228" height="67" /></td><td class="equationnumber" align="right">Eq. (1)</td></tr></tbody></table><p>For adiabatic flow, no shaft work and for gases: Q=0, Ws=0 and dz=negligible....or:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow2.gif" alt="compressible_flow2" width="129" height="51" /></td><td class="equationnumber" align="right">Eq. (2)</td></tr></tbody></table><p>Enthalpy per unit mass of an <strong>ideal</strong> gas is defined H = C<sub>p</sub> T</p><p>The gas, at rest, has no kinetic energy and is at its stagnation temperature (Tst), while the moving gas has kinetic energy and is at another temperature (T). The energies are therefore:<br />energy at rest, per unit mass = 0 + C<sub>p</sub> T<sub>st<br /></sub>energy in motion, per unit mass = v<sup>2</sup>/2 + C<sub>p</sub> T</p><p>Equating the energy at rest and in motion:</p><table class="equationtable" border="0" align="center"><tbody><tr><td>hst= h+v<sup>2</sup>/2</td><td class="equationnumber" align="right">Eq. (3)</td></tr></tbody></table><p>or</p><table class="equationtable" border="0" align="center"><tbody><tr><td>h= hst-v<sup>2</sup>/2</td><td class="equationnumber" align="right">Eq. (4)</td></tr></tbody></table><p>or</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow3.gif" alt="compressible_flow3" width="121" height="53" /></td><td class="equationnumber" align="right">Eq. (5)</td></tr></tbody></table><p>This implies:</p><ol><li>Stagnation enthalpy of the fluid during adiabatic flow is constant. For an ideal gas, this implies the stagnation temperature is constant.</li><li>Enthalpy of the gas drops and kinetic energy increases in the direction of flow.</li><li><span style="text-decoration: underline;">For as given mass flux the enthalpy and density are related to each other.</span></li></ol><p>A useful way of looking at this relationship is by fanno lines. The fanno lines are lines of constant mass flux plotted on an enthalpy/entropy diagram:</p><table class="imagecaption" border="0" align="center"><tbody><tr><td><a class='resized_img' rel='lightbox[2]' title="Sub-sonic Flanno Flow" href="../../../../invision/uploads/images/articles/compressible_flow4.gif" target="_blank"><img src="../../../../invision/uploads/images/articles/thumbnails/thumb_compressible_flow4.gif" alt="compressible-flow" width="250" height="170" /></a></td></tr><tr><td>Figure 1: Sub-sonic Flanno Flow</td></tr></tbody></table><table class="equationtable" border="0" align="center"><tbody><tr><td>C<sub>p</sub> T<sub>st</sub> = v<sup>2</sup>/2 + C<sub>p</sub> T</td><td class="equationnumber" align="right">Eq. (6)</td></tr></tbody></table><p>To make this equation useful, we must replace C<sub>p </sub>and v by terms containing only constants and the Mach number.</p><p>Also for an <strong>ideal</strong> gas:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow5.gif" alt="compressible_flow5" width="125" height="66" /></td><td class="equationnumber" align="right">Eq. (7)</td></tr></tbody></table><p>and</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow6.gif" alt="compressible_flow6" width="119" height="79" /></td><td class="equationnumber" align="right">Eq. (8)</td></tr></tbody></table><p>Substituting yields:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow7.gif" alt="compressible_flow7" width="317" height="68" /></td><td class="equationnumber" align="right">Eq. (9)</td></tr></tbody></table><p>or</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow8.gif" alt="compressible_flow8" width="197" height="65" /></td><td class="equationnumber" align="right">Eq. (10)</td></tr></tbody></table><p><em>Thus we see that for an ideal gas the temperature decreases as velocity increases.</em><br /><br />If the gas is flowing adiabatically, then no energy has been added or subtracted from it and Tst is constant along the length of the pipe. Knowing Tst, then the above equation can be used to find the flowing temperature from the Mach number, (or vice versa) at any position along the pipe.</p><p class="h2header">Analysis Two</p><p>This analysis uses the principles of conservation of energy and mass to derive a relationship between pressure and Mach number at up and downstream conditions, for adiabatic flow in a pipe of constant cross-sectional area.</p><p>The conservation of mass requires the mass flux to be the same at any position along a pipe. Mass flux at any of these positions can be expressed in terms of density and velocity :</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow9.gif" alt="compressible_flow9" width="242" height="28" /></td><td class="equationnumber" align="right">Eq. (11)</td></tr></tbody></table><p>For an ideal gas:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow10.gif" alt="compressible_flow10" width="90" height="52" /></td><td class="equationnumber" align="right">Eq. (12)</td></tr></tbody></table><p>and</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow11.gif" alt="compressible_flow11" width="115" height="76" /></td><td class="equationnumber" align="right">Eq. (13)</td></tr></tbody></table><p>Substituting for density and velocity, we obtain Equation14 which relates Mach number, mass flow rate and flowing pressure and temperature:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow12.gif" alt="compressible_flow12" width="168" height="60" /></td><td class="equationnumber" align="right">Eq. (14)</td></tr></tbody></table><p>or</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow13.gif" alt="compressible_flow13" width="148" height="67" /></td><td class="equationnumber" align="right">Eq. (15)</td></tr></tbody></table><p>Substituting for T from Equation 10:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow14.gif" alt="compressible_flow14" width="284" height="107" /></td><td class="equationnumber" align="right">Eq. (16)</td></tr></tbody></table><p>G is same at inlet (1) and outlet(2), so:</p><p>Â </p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow15.gif" alt="compressible_flow15" width="565" height="99" /></td><td class="equationnumber" align="right">Eq. (17)</td></tr></tbody></table><p>which leads to:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow16.gif" alt="compressible_flow16" width="236" height="120" /></td><td class="equationnumber" align="right">Eq. (18)</td></tr></tbody></table><p><em>This implies that pressure decreases as the Mach number increases</em>. A similar analysis for temperature gives:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow17.gif" alt="compressible_flow17" width="183" height="118" /></td><td class="equationnumber" align="right">Eq. (19)</td></tr></tbody></table><p><em>This implies that temperature decreases as the Mach number increases. However, this is true for ideal gases only. For real gases temperature may increase!</em></p><hr class="system-pagebreak" title="Analysis Three" /><p class="h2header">Analysis Three</p><p>Now the momentum equation is introduced to incorporates the losses due to friction. The derivation is available in any standard textbook for compressible flow In summary the final result is:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow18.gif" alt="compressible_flow18" width="471" height="137" /></td><td class="equationnumber" align="right">Eq. (20)</td></tr></tbody></table><p>where</p><p>f= Average Darcy friction factor<br />L= Equivalent length of line<br />d= I.D. of the line</p><p>Thus this equation relates losses due to friction to inlet and outlet velocities. Solving for the unknown parameter requires a trial and error approach and is suitable for an Excel spreadsheet using the "Goal Seek" or "Solver" tools. Depending on the number of unknowns one or all three of the following equations need to be solved simultaneously:</p><p>Mass balance Equation 11<br />Energy balance Equation18 or 19<br />Momentum balance Equation 20.</p><p>In cases where the outlet velocity is defined as Mach 1, then the equation can be solved for the maximum length, which can be used to flow a certain amount of fluid through a line of known diameter. <em>Beyond this length choked flow condition occurs and, as explained above, any further increase in pipe length will cause the flow to decrease in such a manner that velocity at the end of the pipe is still sonic ( Mach=1).</em> This particular application is of considerable practical use in sizing blowdown lines or relief valve outlet lines relieving to the atmosphere.</p><p>Recall that the above equations have assumed that the gas is ideal. One can compensate for non-ideality to an extent by incorporating the Z factor. A rigorous approach implies solving simultaneously the momentum, energy, and mass balance equation numerically. An analytical approach, as given above for ideal gases, is useful most of the time and the results are valid for engineering purpose.</p><hr class="system-pagebreak" title="Isothermal Flow" /><p><span class="h1header">Isothermal Flow</span></p><p>In isothermal flow, the temperature of the gas remains constant. This simplifies matters considerably. Starting with the mechanical energy equation:</p><table class="equationtable" border="0" align="center"><tbody><tr><td valign="middle"><img src="../../../../invision/uploads/images/articles/compressible_flow19.gif" alt="compressible_flow19" width="203" height="76" /></td><td class="equationnumber" align="right">Eq. (21)</td></tr></tbody></table><p>Multiplying both sides by ?<sup>2</sup>:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow20.gif" alt="compressible_flow20" width="253" height="60" /></td><td class="equationnumber" align="right">Eq. (22)</td></tr></tbody></table><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow21.gif" alt="compressible_flow21" width="453" height="133" /></td><td class="equationnumber" align="right" valign="bottom"><br /><br /><br />Eq. (23)</td></tr></tbody></table><p align="left">Rearranging and integrating gives:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow22.gif" alt="compressible_flow22" width="346" height="66" /></td><td class="equationnumber" align="right">Eq. (24)</td></tr></tbody></table><p align="left"><em>When the temperature change over the conduit is small EquationÂ 24 can be used instead of the adiabatic Equation 20.Â  Adibatic flow below Mach 0.3 follows EquationÂ 24 closely.</em></p><p align="left">If EquationÂ 24 is differentiated with respect to ?<sub>bÂ Â  </sub>to obtain a maximum G then:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow23.gif" alt="compressible_flow23" width="140" height="68" /></td><td class="equationnumber" align="right">Eq. (25)</td></tr></tbody></table><p align="left">and the exit Mach number is:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/compressible_flow24.gif" alt="compressible_flow24" width="97" height="54" /></td><td class="equationnumber" align="right">Eq. (26)</td></tr></tbody></table><p align="left"><em>This apparent choking condition for isothermal flow is not physically meaningful, as at these high speeds, and rates of expansion, isothermal conditions are not possible.</em></p><p align="left"><span class="h1header">References</span></p><ol><li><div>Unit operations of Chemical Engineering- Mccabe, Smith and Hariott; McGraw-Hill</div></li><li><div>Perry's Chemical Engineers' Handbook' McGraw-Hill.</div></li></ol>]]></description>
		<pubDate>Mon, 08 Nov 2010 18:50:19 +0000</pubDate>
		<guid isPermaLink="false">6cdd60ea0045eb7a6ec44c54d29ed402</guid>
	</item>
	<item>
		<title>Using Equivalent Lengths of Valves and Fittings</title>
		<link>http://www.cheresources.com/content/articles/fluid-flow/using-equivalent-lengths-of-valves-and-fittings</link>
		<description><![CDATA[<p>One of the most basic calculations performed by any process engineer, whether in design or in the plant, is line sizing and pipeline pressure loss. Typically known are the flow rate, temperature and corresponding viscosity and specific gravity of the fluid that will flow through the pipe.</p><p> These properties are entered into a computer program or spreadsheet along with some pipe physical data (pipe schedule and roughness factor) {parse block="google_articles"}and out pops a series of line sizes with associated Reynolds Number, velocity, friction factor and pressure drop per linear dimension. The pipe size is then selected based on a compromise between the velocity and the pressure drop. With the line now sized and the pressure drop per linear dimension determined, the pressure loss from the inlet to the outlet of the pipe can be calculated.</p><p class="h1header">Calculating Pressure Drop</p><p>The most commonly used equation for determining pressure drop in a straight pipe is the Darcy Weisbach equation. One common form of the equation which gives pressure drop in terms of feet of head is given below:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/eqlength1.gif" alt="eqlength1" width="102" height="46" /></td><td class="equationnumber" align="right">Eq. (1)</td></tr></tbody></table><p>The term <img style="margin-left: 3px; vertical-align: middle; margin-right: 3px;" src="../../../../invision/uploads/images/articles/eqlength2.gif" alt="eqlength2" width="41" height="57" />is commonly referred to as the Velocity Head.</p><p>Another common form of the Darcy Weisbach equation that is most often used by engineers because it gives pressure drop in units of pounds per square inch (psi) is:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/eqlength3.gif" alt="eqlength3" width="164" height="49" /></td><td class="equationnumber" align="right">Eq. (2)</td></tr></tbody></table><p>To obtain pressure drop in units of psi/100 ft, the value of 100 replaces L in Equation 2.</p><p>The total pressure drop in the pipe is typically calculated using these five steps.</p><ol><li>Determine the total length of all horizontal and vertical straight pipe runs. </li><li>Determine the number of valves and fittings in the pipe. For example, there may be two gate valves, a 90<sup>o</sup> elbow and a flow thru tee. </li><li>Determine the means of incorporating the valves and fittings into the Darcy equation. To accomplish this, most engineers use a table of equivalent lengths. This table lists the valve and fitting and an associated length of straight pipe of the same diameter, which will incur the same pressure loss as that valve or fitting. For example, if a 2" 90<sup>o</sup> elbow were to produce a pressure drop of 1 psi, the equivalent length would be a length of 2" straight pipe that would also give a pressure drop of 1 psi. The engineer then multiplies the quantity of each type of valve and fitting by its respective equivalent length and adds them together. </li><li>The total equivalent length is usually added to the total straight pipe length obtained in step one to give a total pipe equivalent length. </li><li>This total pipe equivalent length is then substituted for L in Equation 2 to obtain the pressure drop in the pipe.</li></ol><p>See any problems with this method?</p><p class="h1header">Relationship Between K, Friction Factor, and Equivalent Length</p><p>The following discussion is based on concepts found in reference 1, the CRANE Technical Paper No. 410. It is the author's opinion that this manual is the closest thing the industry has to a standard on performing various piping calculations. If the reader currently does not own this manual, it is highly recommended that it be obtained.</p><p>As in straight pipe, velocity increases through valves and fittings at the expense of head loss. This can be expressed by another form of the Darcy equation similar to Equation 1:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/eqlength4.gif" alt="eqlength4" width="83" height="45" /></td><td class="equationnumber" align="right">Eq. (3)</td></tr></tbody></table><p>When comparing Equations 1 and 3, it becomes apparent that:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/eqlength5.gif" alt="eqlength5" width="70" height="47" /></td><td class="equationnumber" align="right">Eq. (4)</td></tr></tbody></table><p>K is called the resistance coefficient and is defined as the number of velocity heads lost due to the valve or fitting. It is a measure of the following pressure losses in a valve or fitting:{parse block="google_articles"}</p><ul type="disc"><li>Pipe friction in the inlet and outlet straight portions of the valve or fitting </li><li>Changes in direction of flow path </li><li>Obstructions in the flow path </li><li>Sudden or gradual changes in the cross-section and shape of the flow path </li></ul><p>Pipe friction in the inlet and outlet straight portions of the valve or fitting is very small when compared to the other three. Since friction factor and Reynolds Number are mainly related to pipe friction, K can be considered to be independent of both friction factor and Reynolds Number.<sup> </sup>Therefore, K is treated as a constant for any given valve or fitting under all flow conditions, including laminar flow. Indeed, experiments showed<sup>1</sup> that for a given valve or fitting type, the tendency is for K to vary only with valve or fitting size. Note that this is also true for the friction factor in straight clean commercial steel pipe <em>as long as flow conditions are in the fully developed turbulent zone</em>. It was also found that the ratio L/D tends towards a constant <em>for all sizes </em>of a given valve or fitting type<em> </em>at the same flow conditions. The ratio L/D is defined as the equivalent length of the valve or fitting <em>in pipe diameters </em>and<em> </em>L is the equivalent length itself.<em> </em></p><p>In Equation 4, <em>f</em> therefore varies only with valve and fitting size and is independent of Reynolds Number. This only occurs if the fluid flow is in the zone of <em>complete turbulence</em> (see the Moody Chart in reference 1 or in any textbook on fluid flow). Consequently, <em>f</em> in Equation 4 is <em>not</em> the same <em>f</em> as in the Darcy equation for straight pipe, which <em>is</em> a function of Reynolds Number. For valves and fittings, <em>f</em> is the friction factor in the zone of <em>complete turbulence</em> and is designated <em>f</em><sub>t</sub>, and the equivalent length of the valve or fitting is designated L<sub>eq</sub>. Equation 4 should now read (with D being the diameter of the valve or fitting):</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/eqlength6.gif" alt="eqlength6" width="92" height="40" /></td><td class="equationnumber" align="right">Eq. (5)</td></tr></tbody></table><p>The equivalent length, L<sub>eq,</sub> is related to <em>f</em><sub>t</sub>, not<sub> </sub><em>f</em>, the friction factor of the flowing fluid in the pipe. Going back to step four in our five step procedure for calculating the total pressure drop in the pipe, adding the equivalent length to the straight pipe length for use in Equation 1 is fundamentally wrong.</p><p class="h1header">Calculating Pressure Drop, The Correct Way</p><p>So how should we use equivalent lengths to get the pressure drop contribution of the valve or fitting? A form of Equation 1 can be used if we substitute <em>f</em><sub>t</sub> for <em>f</em> and L<sub>eq</sub> for L (with d being the diameter of the valve or fitting):</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/eqlength7.gif" alt="eqlength7" width="181" height="54" /></td><td class="equationnumber" align="right">Eq. (6)</td></tr></tbody></table><p>The pressure drop for the valves and fittings is then added to the pressure drop for the straight pipe to give the total pipe pressure drop.</p><p>Another approach would be to use the K values of the individual valves and fittings. The quantity of each type of valve and fitting is multiplied by its respective K value and added together to obtain a total K. This total K is then substituted into the following equation:</p><table class="equationtable" border="0" align="center"><tbody><tr><td><img src="../../../../invision/uploads/images/articles/eqlength8.gif" alt="eqlength8" width="164" height="44" /></td><td class="equationnumber" align="right">Eq. (7)</td></tr></tbody></table><p>Notice that use of equivalent length and friction factor in the pressure drop equation is eliminated, although both are still required to calculate the values of K<sup>1</sup>. As a matter of fact, there is nothing stopping the engineer from converting the straight pipe length into a K value and adding this to the K values for the valves and fittings before using Equation 7. This is accomplished by using Equation 4, where D is the pipe diameter and <em>f</em> is the pipeline friction factor.</p><p>How significant is the error caused by mismatching friction factors? The answer is, it depends. Below is a real world example showing the difference between the Equivalent Length method (as applied by most engineers) and the K value method to calculate pressure drop.</p><p class="h1header">An Example</p><p>The fluid being pumped is 94% Sulfuric Acid through a 3", Schedule 40, Carbon Steel pipe:</p><table class="datatable" border="0" align="center"><caption>Table 1: Process Data for Example Calculation</caption><tbody><tr><td>Mass Flow Rate, lb/hr</td><td>63,143</td></tr><tr><td>Volumetric Flow Rate, gpm</td><td>70</td></tr><tr><td>Density, lb/ft<sup>3</sup></td><td>112.47</td></tr><tr><td>S.G.</td><td>1.802</td></tr><tr><td>Viscosity, cp</td><td>10</td></tr><tr><td>Temperature, <sup>o</sup>F</td><td>127</td></tr><tr><td>Pipe ID, in</td><td>3.068</td></tr><tr><td>Velocity, ft/s</td><td>3.04</td></tr><tr><td>Reynold's No</td><td>12,998</td></tr><tr><td>Darcy Friction Factor, (f) Pipe</td><td>0.02985</td></tr><tr><td>Pipe Line ?P/100 ft</td><td>1.308</td></tr><tr><td>Friction Factor at Full Turbulence (<em>f</em><sub>t</sub>)</td><td>0.018</td></tr><tr><td>Straight Pipe, ft</td><td>31.5</td></tr></tbody></table><p>Â </p><table class="datatable" border="0" align="center"><caption>Table 2: Fitting Date for Example Calculation</caption><tbody><tr><td align="right" valign="middle" scope="colgroup"><strong>Fittings</strong></td><td align="right" valign="middle" scope="colgroup">L<sub>eq</sub>/D<sup>1</sup></td><td align="right" valign="middle" scope="colgroup">L<sub>eq</sub><sup>2, 3</sup></td><td align="right" valign="middle" scope="colgroup"><p align="center">K<sup>1, 2</sup> =<br /><em>f</em><sub>t</sub> (L/D)</p></td><td align="right" valign="middle" scope="colgroup">Quantity</td><td align="right" valign="middle" scope="colgroup">Total L<sub>eq</sub></td><td align="right" valign="middle" scope="colgroup">Total K</td></tr><tr><td align="left" valign="middle" scope="col">90<sup>o</sup> Long Radius Elbow</td><td align="right" valign="middle" scope="colgroup">20</td><td align="right" valign="middle" scope="colgroup">5.1</td><td align="right" valign="middle" scope="colgroup">0.36</td><td align="right" valign="middle" scope="colgroup">2</td><td align="right" valign="middle" scope="colgroup">10.23</td><td align="right" valign="middle" scope="colgroup">0.72</td></tr><tr><td align="left" valign="middle" scope="col">Branch Tee</td><td align="right" valign="middle" scope="colgroup">60</td><td align="right" valign="middle" scope="colgroup">15.3</td><td align="right" valign="middle" scope="colgroup">1.08</td><td align="right" valign="middle" scope="colgroup">1</td><td align="right" valign="middle" scope="colgroup">15.34</td><td align="right" valign="middle" scope="colgroup">1.08</td></tr><tr><td align="left" valign="middle" scope="col">Swing Check Valve</td><td align="right" valign="middle" scope="colgroup">50</td><td align="right" valign="middle" scope="colgroup">12.8</td><td align="right" valign="middle" scope="colgroup">0.90</td><td align="right" valign="middle" scope="colgroup">1</td><td align="right" valign="middle" scope="colgroup">12.78</td><td align="right" valign="middle" scope="colgroup">0.90</td></tr><tr><td align="left" valign="middle" scope="col">Plug Valve</td><td align="right" valign="middle" scope="colgroup">18</td><td align="right" valign="middle" scope="colgroup">4.6</td><td align="right" valign="middle" scope="colgroup">0.324</td><td align="right" valign="middle" scope="colgroup">1</td><td align="right" valign="middle" scope="colgroup">4.60</td><td align="right" valign="middle" scope="colgroup">0.324</td></tr><tr><td align="left" valign="middle" scope="col">3" x 1" Reducer<sup>4</sup></td><td align="right" valign="middle" scope="colgroup">None<sup>5</sup></td><td align="right" valign="middle" scope="colgroup">822.68<sup>5</sup></td><td align="right" valign="middle" scope="colgroup">57.92</td><td align="right" valign="middle" scope="colgroup">1</td><td align="right" valign="middle" scope="colgroup">822.68</td><td align="right" valign="middle" scope="colgroup">57.92</td></tr><tr><td align="right" valign="middle" scope="colgroup"><em>Total</em></td><td align="right" valign="middle" scope="colgroup">Â </td><td align="right" valign="middle" scope="colgroup">Â </td><td align="right" valign="middle" scope="colgroup">Â </td><td align="right" valign="middle" scope="colgroup">Â </td><td align="right" valign="middle" scope="colgroup">865.63</td><td align="right" valign="middle" scope="colgroup">60.94</td></tr></tbody></table><p><em>Notes:</em></p><ol type="1"><li><em>K values and L<sub>eq</sub>/D are obtained from Reference 1. </em></li><li><em>K values and L<sub>eq </sub>are given in terms of the larger sized pipe. </em></li><li><em>L<sub>eq</sub> is calculated using Equation 5 above. </em></li><li><em>The reducer is really an expansion; the pump discharge nozzle is 1" (Schedule 80) but the connecting pipe is 3". In piping terms, there are no expanders, just reducers. It is standard to specify the reducer with the larger size shown first. The K value for the expansion is calculated as a gradual enlargement with a 30<sup>o</sup> angle. </em></li><li><em>There is no L/D associated with an expansion or contraction. The equivalent length must be back calculated from the K value using Equation 5 above. </em></li></ol><table class="datatable" border="0" align="center"><caption>Table 3: Pressure Drop Results for Example Calculation</caption><tbody><tr><td>Â </td><td>Typical Equivalent <br />Length Method</td><td>K Value Method</td></tr><tr><td>Straight Pipe ?P, psi</td><td align="right" scope="rowgroup">Not Applicable</td><td align="right">0.412</td></tr><tr><td>Total Pipe Equivalent Length ?P, psi</td><td align="right">11.734</td><td align="right">Not Applicable</td></tr><tr><td>Valves and Fittings ?P, psi</td><td align="right">Not Applicable</td><td align="right">6.828</td></tr><tr><td>Total Pipe ?P, psi</td><td align="right">11.734</td><td align="right">7.240</td></tr></tbody></table><p>The line pressure drop is greater by about 4.5 psi (about 62%) using the typical equivalent length method (adding straight pipe length to the equivalent length of the fittings and valves and using the pipe line fiction factor in Equation 1).</p><p>One can argue that if the fluid is water or a hydrocarbon, the pipeline friction factor would be closer to the friction factor at full turbulence and the error would not be so great, if at all significant; and they would be correct. However hydraulic calculations, like all calculations, should be done in a correct and consistent manner. If the engineer gets into the habit of performing hydraulic calculations using fundamentally incorrect equations, he takes the risk of falling into the trap when confronted by a pumping situation as shown above.</p><p>Another point to consider is how the engineer treats a reducer when using the typical equivalent length method. As we saw above, the equivalent length of the reducer had to be back-calculated using equation 5. To do this, we had to use <em>f<sub>t </sub><em>and K</em>. </em></p><p><span class="info"><strong>Why not use these for the rest of the fittings and apply the calculation correctly in the first place?</strong></span><em> </em></p><p class="h1header"> <span class="h1header">Final Thoughts on K Values</span></p><p>The 1976 edition of the Crane Technical Paper No. 410 first discussed and used the two-friction factor method for calculating the total pressure drop in a piping system (<em>f</em> for straight pipe and <em>f</em><sub>t</sub> for valves and fittings). Since then, Hooper<sup>2 </sup>suggested a 2-K method for calculating the pressure loss contribution for valves and fittings. His argument was that the equivalent length in pipe diameters (L/D) and K was indeed a function of Reynolds Number (at flow rates less than that obtained at fully developed turbulent flow) and the exact geometries of smaller valves and fittings. K for a given valve or fitting is a {parse block="google_articles"}combination of two Ks, one being the K found in CRANE Technical Paper No. 410, designated K<sub>Y</sub>, and the other being defined as the K of the valve or fitting at a Reynolds Number equal to 1, designated K<sub>1</sub>. The two are related by the following equation:</p><p>K = K<sub>1 </sub>/ N<sub>RE </sub>+ K<sub>?</sub> (1 + 1/D)</p><p>The term (1+1/D) takes into account scaling between different sizes within a given valve or fitting group. Values for K<sub>1</sub> can be found in the reference article<sup>2</sup> and pressure drop is then calculated using Equation 7. For flow in the fully turbulent zone and larger size valves and fittings, K becomes consistent with that given in CRANE.</p><p>Darby<sup>3</sup> expanded on the 2-K method. He suggests adding a third K term to the mix. Darby states that the 2-K method does not accurately represent the effect of scaling the sizes of valves and fittings. The reader is encouraged to get a copy of this article.</p><p>The use of the 2-K method has been around since 1981 and does not appear to have "caught" on as of yet. Some newer commercial computer programs allow for the use of the 2-K method, but most engineers inclined to use the K method instead of the Equivalent Length method still use the procedures given in CRANE. The latest 3-K method comes from data reported in the recent CCPS Guidlines<sup>4</sup> and appears to be destined to become the new standard; we shall see.</p><p class="h1header">Conclusion</p><p>Consistency, accuracy and correctness should be what the Process Design Engineer strives for. We all add our "fat" or safety factors to theoretical calculations to account for real-world situations. It would be comforting to know that the "fat" was added to a basis using sound and fundamentally correct methods for calculations.</p><p class="h1header">Questions and Answers</p><p class="h2header">Question #1</p><p class="blockquote_j"><p>Could you please give me in layman terms a better definition for K values. I know that K is defined as "the number of velocity heads lost"...But what exactly does that mean???</p><p>Mr. Leckner's reply to this question:</p><table class="datatable_inset" border="0"><tbody><tr><td><p>Well, I'll try to give you the Chemical Engineer's version of the layman answer. Velocity of any fluid increases through pipes, valves and fittings at the expense of pressure. This pressure loss is referred to as head loss. The greater the head loss, the higher the velocity of the fluid. So, saying a velocity head loss is just another way of saying we loose pressure due to and increase in velocity and this pressure loss is measured in terms of feet of head. Now, each component in the system contributes to the amount of pressure loss in different amounts depending upon what it is. Pipes contribute fL/D where L is the pipe length, D is the pipe diameter and f is the friction factor. A fitting or valve contributes K. Each fitting and valve has an associated K.</p></td></tr></tbody></table><p>Â </p><p class="h2header">Question #2</p><p class="blockquote_j"><p>It appears that the K values in CRANE TP-410 were established using a liquid (water) flow loop. Is this K value also valid for compressible media systems? (Can a K value be used for both compressible and incompressible service?)</p><p>Mr. Leckner's reply to this question:</p><table class="datatable_inset" border="0"><tbody><tr><td><p>Crane also tested their system on steam and air. Now, this is where things get sticky. As per CRANE TP-410, K values are a function of the size and type of valve or fitting only and is independent of fluid and Reynolds number. So yes, you can use it in ALL services, including two-phase flow.Â  However, as I point out towards the end of my article, there is now evidence that shows using a single K value for the valve and fitting is not correct and that K is indeed a function of both Reynolds number and fitting/valve<br />geometry. I reference an article by Dr. Ron Darby of Texas A&M University which can be found in Chemical Engineering Magazine, July 1999. Dr. Darby just published a second article on the subject which can be found in Chemical Engineering Magazine, April 2001.<br /><br />I don't believe there is any question as to the proper way to use K values in pressure drop calculations. The only question is whether industry will accept the new data.</p></td></tr></tbody></table><p>Â </p><p class="h2header">Question #3</p><p class="blockquote_j"><p>When answering my first question, you stated:Â  'Velocity of any fluid increases through pipes, valves and fittings at the expense of pressure.'Â  When you say this, you are talking about compressible (gas) flow right?Â  For example, in a pipe of constant area, the velocity of a gas would increase as the fluid traveled down the pipe (due to the decreasing pressure). Â  However, the velocity of a liquid would remain constant as it traveled down the same pipe (even with the decreasing pressure).Â  Is this a correct statement?</p><p>Mr. Leckner's reply to this question:</p><table class="datatable_inset" border="0"><tbody><tr><td><p>Sorry for the confusion. Yes to both of your questions. If you look at the Bernoulli equation, you will see that velocity cancels out for a liquid as long as there is no change in pipe size along the way and pressure drop is only a function of frictional losses and a change in elevation.<br /><br />However, the K value of a fitting is still a quantifier of the head loss (frictional loss) in that fitting and this head loss is still calculated as the velocity head of the liquid (V^2/2g). So in essence, you still achieve a <br />liquid velocity at the expense of pressure loss; the velocity head just happens to be constant. Read section 2-8 in CRANE TP-410. They define the velocity head as a decrease in static head due to velocity.<br /><br />The big thing is not to get too hung up on the definitions and just remember you can't have flow unless you have a driving force and that force is differential pressure. Also, in a piping system there is frictional losses which comes from the pipe and all fittings and valves. The use of K is just a way of quantifying the frictional component of the fittings and valves. You can even put the piping friction in terms of K by using fL/D for the pipe and multiplying that by V^2/2g.<br /><br />I hope this helps. If you are still confused, let me know and I'll just explain it again but I'll try to do it in a different way. Sometimes, a concept just needs to be re-worded and I'm willing to spend as much time on this as you need.</p></td></tr></tbody></table><p>Â </p><p class="h2header">Question #4</p><p class="blockquote_j"><p>I'm reading the Crane Technical Paper #410 and I have the following<br />questions/comments:<br /><br />Page 2-8 of TP 410 states that:<br />"Velocity in a pipe is obtained at the expense of static head".Â  This makes sense and Equation 2-1 shows this relationship where the static head is converted to velocity head.Â  However, there is no diameter associated with this.Â  So is it correct to say based on equation 2-1 that if you had a barrel of water with a short length of pipe attached to the bottom that discharged to atmosphere, and in this barrel you had 5 feet of water (5' of static head), the resulting water velocity would be 17.94 ft/sec (regardless<br />of the pipe diameter).<br /><br />Maybe the real question is how do you use equation 2-1.Â  Do you have to know the velocity and then you can calculate the headloss?Â  And why does equation 2-1 and equation 2-3 seem to show headloss equaling two different things?<br /><br />Also, why does it say that a diameter is always associtated with the K value, when as I mentioned above there is no diameter associated with equation 2-1?<br /><br />Maybe I'm trying to read into all of this too deeply, but I still do not feel that I fully grasp what page 2-8 is trying to reveal.</p><p>Mr. Leckner's reply to this question:</p><table class="datatable_inset" border="0"><tbody><tr><td><p>You need a diameter to get velocity. Velocity is lenght/time (for example, feet/sec). Flow is usually given in either mass units (weight/time or lb/hr for example) or in volumetric units (cubic feet per minute for example). To get velocity, you need to divide the volumetric flow by a cross sectional area (square feet). To get an area, you need a diameter. So the velocity is always based on some diameter.<br /><br />As I show in my paper, equation 2-1 is just the basis of the velocity head. To get the frictional loss, you need to know the contribution of each component in the system; pipe, fitting and valve. To get that contribution, you use 'K' (equation 2-2). Each component has an associated 'K' value. You multiply the velocity head by the appropriate 'K' value. Equation 2-3 is just another way of expressing the same thing. As you can see, this means you can calculate a 'K' for a component such as a pipe using the formula fL/D as shown in Equation 2-3. Again, I explain this in my paper so I would suggest you re-read it.<br /><br />I would also suggest you look at the examples in CRANE. There are many of them in Chapter 4.<br /><br />'K' is associated with the velocity and therefore the diameter. Look at the values for 'K' in CRANE (starting on page A-26). You will see that for the most part, K is a function of a constant times the friction factor at fully turbulent flow. This friction factor changes with pipe diameter as shown on page A-26. Again, re-read my paper and look at the examples in Chapter 4.</p></td></tr></tbody></table><p></p><p class="h1header">Nomenclature</p><table border="0" cellspacing="1" cellpadding="2"><tbody><tr><td width="40">D</td><td width="23">=</td><td width="376">Diameter, ft</td></tr><tr><td width="40">d</td><td width="23">=</td><td width="376">Diameter, inches</td></tr><tr><td width="40"><em>f</em></td><td width="23">=</td><td width="376">Darcy friction factor</td></tr><tr><td width="40"><em>f</em><sub>t</sub></td><td width="23">=</td><td width="376">Darcy friction factor in the zone of complete turbulence</td></tr><tr><td width="40">g</td><td width="23">=</td><td width="376">Acceleration of gravity, ft/sec<sup>2</sup></td></tr><tr><td width="40">h<sub>L</sub></td><td width="23">=</td><td width="376">Head loss in feet</td></tr><tr><td width="40">K</td><td width="23">=</td><td width="376">Resistance coefficient or velocity head loss</td></tr><tr><td width="40">K<sub>1</sub></td><td width="23">=</td><td width="376">K for the fitting at N<sub>RE</sub> = 1</td></tr><tr><td width="40">K<sub>?</sub></td><td width="23">=</td><td width="376">K value from CRANE</td></tr><tr><td width="40">L</td><td width="23">=</td><td width="376">Straight pipe length, ft</td></tr><tr><td width="40">L<sub>eq</sub></td><td width="23">=</td><td width="376">Equivalent length of valve or fitting, ft</td></tr><tr><td width="40">N<sub>RE</sub></td><td width="23">=</td><td width="376">Reynolds Number</td></tr><tr><td width="40">?P</td><td width="23">=</td><td width="376">Pressure drop, psi</td></tr><tr><td width="40">n</td><td width="23">=</td><td width="376">Velocity, ft/sec</td></tr><tr><td width="40">W</td><td width="23">=</td><td width="376">Flow Rate, lb/hr</td></tr><tr><td width="40">?</td><td width="23">=</td><td width="376">Density, lb/ft<sup>3</sup></td></tr></tbody></table><p class="h1header">References</p><ol><li>Crane Co., "Flow of Fluids through Valves, Fittings and Pipe", Crane Technical Paper No. 410, New York, 1991.</li><li>Hooper, W. B., The Two-K Method Predicts Head Losses in Pipe Fittings, Chem. Eng., p. 97-100, August 24, 1981. </li><li>Darby, R., Correlate Pressure Drops through Fittings, Chem. Eng., p. 101-104, July, 1999. </li><li>AIChE Center for Chemical Process Safety, "Guidelines for Pressure Relief and Effluent Handling systems", pp. 265-268, New York, 1998. </li></ol>]]></description>
		<pubDate>Mon, 08 Nov 2010 18:50:19 +0000</pubDate>
		<guid isPermaLink="false">e19347e1c3ca0c0b97de5fb3b690855a</guid>
	</item>
</channel>
</rss>