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#1 XBOX999

XBOX999

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Posted 16 March 2010 - 08:29 PM

Hello, I am first year student.This is my first course in Chemical engineering.I have midtearm after tommorow.Can you tell me the way how to solve this problem please.

The production of butadiene (C4H6) by the oxy-dehydrogenation of butenes (C4H8) in the presence of a catalyst occurs according to the following gas phase reactions:
C4H8+0.5 O2 ----> C4H6 +H2O
C4H8 + 6O2------> 4 CO2+4H2O
The feed, consisting of a mixture of butenes, water vapour, air and a small quantity of butadiene, is added to the recycle stream and fed to the reactor. The gases exiting from the reactor are cooled in heat exchangers and condensed water is removed using a decanter. One can assume that all of the water is condensed. The carbon dioxide and nitrogen in the air are then completely eliminated in an oil wash tower.
The butadiene is separated from the butenes using a furfuryl alcohol extraction tower. A small proportion of unreacted butadiene and butenes are recycled.
Below is some additional information about the process:
1. The fresh feed is composed of 10 000 kmol/h water, 3 500 kmol/h air, 645 kmol/h butenes and 58 kmol/h butadiene.
2. The production of butadiene is 628 kmol/h.
3. The mean value of the butadiene/butenes molar ratio obtained by chemical analysis in the recycle stream is 0.027586 and after the mixing point (at the reactor entrance) is 0.064814.
4. The oxygen in the air is completely consumed by the reactions.
48246248222CH + 0.5 O CH + HOCH + 6 O 4 CO + 4 HO→→
Calculate the overall flowrate and the flowrates for each species (see the figure below) using the extent of reaction.
Complete the following table.
the table and the graph is in the attachment.Attached File  the table and the graph.pdf   100.14KB   13 downloads

#2 breizh

breizh

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Posted 17 March 2010 - 01:34 AM

Show us what you did and then we will help you .
Hope you understand .
Breizh




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