Jump to content



Featured Articles

Check out the latest featured articles.

File Library

Check out the latest downloads available in the File Library.

New Article

Product Viscosity vs. Shear

Featured File

Vertical Tank Selection

New Blog Entry

Low Flow in Pipes- posted in Ankur's blog

Nfpa 30 Emergecny Vent


This topic has been archived. This means that you cannot reply to this topic.
2 replies to this topic
Share this topic:
| More

#1 Leinster

Leinster

    Junior Member

  • Inactive Member
  • PipPip
  • 16 posts

Posted 15 March 2011 - 11:32 PM

I was recently given the calculation for emergency venting as per NFPA 30 using a "manhole with long bolts" as per the below.

CFH = 1,667*Cf*A*√(Pt-Pa)

Where;
Cf = Flow coefficient of valve (set at 0.5)
A = Area of open manhole or area of manhole lift
Pt = Absolute pressure inside the tank (inH2O)
Pa = Absolute pressure outside of the tank (inH2O)

My questions which nobody has been able to answer (hopefully until now) are as per below.

1) Is the absolute pressure the pressure at which the manhole cover begins to lift or is it the design pressure of the tank or the maximum design pressure as set by Appendix F of API 650?

2) The orifice are of the manhole. Are these units meant to be in "inches" or "feet"?

Thanks in advance.

#2 Zauberberg

Zauberberg

    Gold Member

  • ChE Plus Subscriber
  • 2,727 posts

Posted 19 March 2011 - 03:14 PM

Orifice area is expressed in square inches, as per NFPA 30.

As per my understanding of the paragraph (a), Pt should be the opening pressure i.e. the pressure at which the flow area is fully open.

#3 Leinster

Leinster

    Junior Member

  • Inactive Member
  • PipPip
  • 16 posts

Posted 07 June 2011 - 09:05 AM

Many thanks for the response Zauberberg.

How would you calculate the pressure at which the manhole is fully open? The opening pressure is simple to calculate however I am not really sure where to go once the manhole has begun to lift.




Similar Topics