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Fluid Statics
Started by Dudesons123, May 28 2017 03:05 PM
2 replies to this topic
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#1
Posted 28 May 2017 - 03:05 PM
Dear Engineers/Scientists,
I am facing a problem regarding a rectangular tank 5 m long by 2 m wide containing water to a depth of 2 m. How do I determine the total pressure on the end? I got an answer of 9,810Nm^-2 but the answer on the book says 39kNm^-2. I just want to know where I went wrong?
Here is my working:
Area =1/2*AB*BC
=1/2*H*rho*g*H
=1/2*rho*g*H^2
Resultant force per unit width
R=1/2*rho*g*H^2
Total resultant force
R=1/2*rho*g*H^3
=1/2(1000)(9.81)(2)^2
=39240N
P=R/A=39240N/(2m*2m)=9,810Pascals
Thanks.
I am facing a problem regarding a rectangular tank 5 m long by 2 m wide containing water to a depth of 2 m. How do I determine the total pressure on the end? I got an answer of 9,810Nm^-2 but the answer on the book says 39kNm^-2. I just want to know where I went wrong?
Here is my working:
Area =1/2*AB*BC
=1/2*H*rho*g*H
=1/2*rho*g*H^2
Resultant force per unit width
R=1/2*rho*g*H^2
Total resultant force
R=1/2*rho*g*H^3
=1/2(1000)(9.81)(2)^2
=39240N
P=R/A=39240N/(2m*2m)=9,810Pascals
Thanks.
#2
Posted 28 May 2017 - 04:01 PM
It seems that the answer is the total force on the end, not the average pressure.
#3
Posted 29 May 2017 - 03:39 PM
I agree with Sam. Are you sure that =39240N isn't the answer you are looking for? "Total pressure" doesn't seem to have a clear meaning, on the other hand if you integrate pressure you obtain force. Another result that you can calculate is can be "average pressure".
Best regards.
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