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Fluidised Bed Cooling Loop


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#1 Guest_CEng d3wd_*

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Posted 21 April 2003 - 11:12 AM

Hello

As part of a design project I have to design a cooling loop to remove 100000Mj/h of heat from
a fluidised bed reactor (acrylic acid from propylene). I have had a good attempt at the heat
exchanger, pump and piping design but the removal of heat from the reactor is proving difficult
to achieve. The only other data I have been supplied with is the reactor is operated isothermally
at 310°C and is cooled by 'an arrangement of heat transfer tubes in the reactor' with HiTec
solution running through them (enters at 200°C, leaves at 250°C).

The main problem seems to be the huge surface area of piping which would be required to
remove the heat (>500 m2 even with a high assumed overall heat transfer coefficient).
Im not given any data on the reactor size but was under the impression that Fluidised bed
reactors are not huge vessels so dont want to make the reactor unreasonably large.


Any ideas/suggest on how I should proceed would be appreciated.

#2 mbeychok

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Posted 21 April 2003 - 02:31 PM

I would just like to point out that 100,000 Mj/hour is equivalent to 94,000,000 Btu/hour (I visualize much better in Btu's) ... and that is a very, very high cooling load. Are you sure of your 100,000 Mj/hour ??

#3 mbeychok

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Posted 21 April 2003 - 03:36 PM

I did some searching with Google and found this web site:

www.che.cemr.wvu.edu/publications/projects/acrylic/acrylic12.PDF

That PDF document includes a process flow diagram of a plant that produces acrylic acid from propylene and uses a fludized bed reactor. If you will look at Appendix 4 in that document, you will find that the reactor cooling tubes required 1420 m2 for a cooling load of 84,000 MJ/hour which is in the same ball park as your cooling load.

Hope this helps.




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