2 replies to this topic

[atiq124]

I want to separate suspended solids particles of polymer from solvent by using centrifuge. Lab test have shown positive results and encouraged to proceed towards pilot scale trial. From the information given below, how do I calculate the particle size (micro meter) that will remain in the bowl ?

 

Total Solids = 10% on dry basis

Viscosity of solvent (IsoparM)  0.002 Pa*s

Density of Solids 1100 kg/m3

Density of IsoparM 750 kg/m3

 

Centrifuge basket diameter = 630 mm

Centrifuge basket height = 500 mm

Filtering surface area = 1 m2

Centrifugal speed = 3000 rpm

Feed rate = 700 l/h

 

The machine is model is V630 III BK and further details are at link:

 

http://www.heinkel.c...assifying.aspx 

 

 

 

 

[Bobby Strain]

Have you asked this of the equipment supplier?

 

Bobby

[atiq124]

Hi Bobby, The supplier provided me one of the results below but didn't explain the calculations as they got calculations done by a third party. I want to understand how did they calculate that 1.4 μm particles will remain in the bowl and smaller will be decanted out. Once I understand it, I'll change the feed rates, bowl speed and total solids to find the best operating conditions.  Thanks

 

Proposed average feed rate 700 l/hr * 0.775 kg/l = 542.5 kg/hr

Solids rate 54.2 kg/hr @10% solids by weight

Capacity of 1 x 630 BK = 700 l * 5 hrs = 3500 litres suspension

Result: Particles larger than 1.4 μm remain in the bowl

 

 

(Background: IsoparM solvent is used in cleaning the reactors after every batch which gets contaminated with polymer product. The solids particles from product takes too long (days) for sedimentation and we want to speed up the process by using centrifugal separation. Currently, the IBCs of contaminated solvent are kept aside for few days until the solvent from top can be skimmed off using a pump. Isopar M is one of the raw materials of product and therefore used to avoid any issue of contamination.)

Edited by atiq124, 25 August 2015 - 03:37 AM.