Download Minimum Safe Flow for a Centrifugal Pump

Sir,

Please reply with answers to above queries

Sir,

 

Please reply with answers to above queries

Ayush,

I had already answered your question in the main blog entry. I will repeat my answer here:

Your statement is incorrect. The pump efficiency will be low but it cannot be zero. The pump is still running against a blocked discharge and the mechanical energy from the driver of the pump is being lost by generating heat in the pump casing instead of overcoming the head as change in the potential energy of the liquid being pumped

This can be proven through the power equation for any pump:

P = Q*H*ρ*g / 3600*η*1000

where:

P = power, kW
Q = volumetric flow rate, m3/h
H = head, m
ρ = density, kg/m3
g = 9.81 m/s2 (grav. constant)
η = efficiency, %

If η becomes zero the power required at shut-off would be infinity which is not correct. Hope it is clear now that efficiency is not zero at shut-off.

Regards,
Ankur.

DEAR SIR,

                 THANKS A LOT FOR WRITE THIS BLOG & ATTACHED THE DATA SHEET.

Thanks alot sir for clarifying the doubt.

Sir, its a great blog, thanks for the reference also.

Please recheck the temperature unit conversion.

Sorry @ the last query sir I got the temp. conversion.

However going through the formula, t = (1-e)*Hs/778e

here what is significance of 778, I am asking this because I am confused wether this equation is valid for any liquid or only water?

You can not generalise the equation it is for water only, one needs to use it w.r.t pumping fluid specific heat.