1 reply to this topic

[matinbhagat]

Hi,

I am trying to humidify dry sulfur dioxide gas with water. I want to saturate the gas with water to the maximum, so that I can hold a lot of water. However, I am unable to calculate how much water my gas stream will have when saturated at my experimental conditions. I heard HYSYS and other process simulators can do that, but I do not have access to process simulators currently. If I have dry sulfur dioxide at 80 degrees celsius and volume flow rate is 15 cm^3/minute, how much water(volumetric flowrate of water in moles or ml or cm^3 per minute) can it hold when it is completely saturated with water vapor? I saw a link (given below) describing how to do this with HYSYS, but I do not have HYSYS. I hope someone can either help me with this simple calculation or refer me to a website or something that can help me do this computation. Without knowing how much water I can have, at 100% saturation, I do not know if my reaction can proceed at all. Thank you so much, and please feel free to ask any questions or discuss this. Thank you once again.Also, I am using a dew point humidification process to humidify the sulfur dioxide and would like any advice in relation to this setup. Thanks!

http://webwormcpt.bl...r-in-hysys.html

[MrShorty]

Pressure in the saturator would be important to know.

Perry's has some VLE data for SO2/H2O (taken from JCED vol 8 pp 333-336) that might be worth looking up.

Here's a line of reasoning that might help. If I assume you are operating at "low" pressures, then I can assume the solubility of SO2 in the saturated liquid phase is low [x(H2O) is close to 100 mol%]. If x(H2O) is close to 1, then the activity coefficient of water will also be close to 1, at which point I can just use Raoult's law to calculate the partial pressure of water in the saturated vapor.