hello
I am currently working on inerting pipeline transporting LPG.
I need to know the amount of nitrogen for inerting a distance of 20km pipe diameter of 28 inches.
thank you
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Inerting An Lpg Pipeline
#1
Posted 17 November 2013 - 03:38 PM
#2
Posted 21 November 2013 - 07:14 PM
If you are inerting then does that mean that the pipeline has no LPG in it? I mean if it is full of gas, why would you inert?
If it is empty, then you need to supply a volume based upon the volume of the pipe, corrected for the pressure and temperature. You would likely want to purge it to a multiple of that to insure that there was no flammable mixture. Also, to insure safety, I would instrument the pipe to confirm the mixture.
But none of what I have said may not apply to your application. I think that you need to explain more of what you are trying to accomplish.
Paul
#3
Posted 30 November 2013 - 10:04 PM
1. I believe what you are saying is that the line is now empty (no more LPG). Is that correct?
2. If that is true that the quantity of LPG required depends on the pressure of inert that you want to maintained in the pipeline, which is normally slightly above atmospheric. Then use the gas law PV=nRT. You know P,V,R and T so you can compute the n which is the number of moles of inert.
Edited by S.AHMAD, 30 November 2013 - 10:06 PM.
#4
Posted 30 December 2013 - 01:00 PM
Ahmad:
I agree with you but think that you mean to state: "If that is true, than the quantity of the inert gas required depends on the pressure of the inert gas that you want to maintain in the pipeline."
Am I correct or have I misread your post?
#5
Posted 01 January 2014 - 12:21 AM
Dear Art
Yes... you are correct.. Thanks
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