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Edited by atiq124, 11 March 2015 - 11:03 AM.
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Posted 10 March 2015 - 05:42 AM
Edited by atiq124, 11 March 2015 - 11:03 AM.
Posted 12 March 2015 - 10:34 AM
The circled area on your graph represents the phenomenon called "choked flow" where there is no increase in flow rate even when the downstream pressure is reduced further. As a rule of thumb, this point is generally reached when the downstream pressure is about half of the upstream pressure.
Posted 13 March 2015 - 12:55 AM
atiq124,
No need the flow curve intersects the constant pressure line of 1.4 barg to obtain the flow rate of N2 in your case...
Actually as the critical pressure ratio of N2 is 0.55, then the downstream pressure at or below which there are chocked flow condition is 7.4 (bara)*0.55=4.07 (bara or 3.07 barg); then in your case because the pressure is below the critical pressure, chocked flow would ocuur and based on the graph you provided the flow rate of N2 would be around 212 dm3/s...
Posted 15 March 2015 - 06:21 PM
Thanks a lot for your guidance.
What happens if the pressure is above the critical pressure, will the flow still chock and how would it look on the graph ?
Posted 15 March 2015 - 10:28 PM
atiq124.
If downstream pressure is above the critical pressure, flow will not be choked and the corresponding flow of the pressure will be readable on the graph...
Posted 16 March 2015 - 12:51 AM
Posted 16 March 2015 - 05:24 AM
Hi Fallah, you have already given me the answer but trying to understand a bit more. We know that the critical pressure of Nitrogen is 34 bar and below we have calculated critical pressure of Nitrogen as 3.52 bar, what is the difference between these two critical pressure ?
Pc / Pi = ( 2 / (k + 1))^(k/(k-1))
where
Pc = critical pressure
Pi = inlet pressure = 6.4 barg
k = specific heat capacity ratio
k = Cp/Cv (Cp= heat capacity at constant pressure, Cv= heat capacity at constant volume)
Cp= 0.873 kJ/kg K (www.apithailand.com)
Cv= 0.684 kJ/kg K (www.apithailand.com)
k = 1.2763
Pc/Pi = (2/2.2763) ^ (1.2763/0.2763)
Pc/Pi = 0.55 (Critical Pressure Ratio)
Pc = 0.55 x 6.4 = 3.52 bara
Pc = 3.52 +1.01 = 4.53 barg
Posted 16 March 2015 - 06:49 AM Best Answer
atiq124,
First i have to correct the value of Pc you calculated in barg. In fact it would be 2.53 barg rather than 4.53 barg....
The critical pressure of N2 of 34 bar you mentioned is a thermodynamic properties of N2 and indicates the end point of phase equilibrium (critical point) for N2 under which liquid N2 and its vapor can coexist. The critical flow pressure, on the other hand, indicates the absolute pressure at nozzle exit at critical flow rate passing through that nozzle which corresponds to the nozzle inlet pressure ..
Edited by fallah, 16 March 2015 - 06:51 AM.
Posted 16 March 2015 - 02:22 PM
atiq124,
Please follow exactly what has been clearly explained by Mr. Fallah. The critical pressure downstream of a hole is what has been clearly clarified above.
In the case of a control valve, the ratio of the critical pressure to the upstream pressure also depends on the type of the valve which defines the pressure profile in the vena contracta. In the method recently used to size control valves, AKA "Standardization Method", which has replaced the traditional ones, it is specified that for compressible fluids such as nitrogen in your case, the flow chokes across the control valve if:
X > (Fp) * (XT) , where X = (Pupstream - Pdownstream) / (Absolute Pupstream), Fp = (Cp/Cv)/1.4, and XT is the based on the type of the valve
For more information, refer to ISA-750101.
Best,
Milad
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