3 replies to this topic

[huleswapnil]

Hello,

 

I am working on one of the Oil Processing Complex. In this project, in Separator datasheet, in performance guarantee section it is mentioned that "Separator Pressure loss shall be less than Downcomer static head".

The Separator is Vertical two phase with Vane pack packing.

 

What will happened if Separator Pressure loss shall become more than or equal to Downcomer static head?

 

Kindly explain.

 

Thanks in advance.

[VeryProfessionalEngineer]

I could be wrong because I'm not familiar with your exact situation, but wouldn't the gas just take the path of least resistance? If the dP of the vane pack is higher than the static head in the downcomer, I assume the gas would flow upwards through the downcomer instead of fighting the higher dP in the separator, and in the process blow out (upwards) all the liquid that the vessel is attempting to drain.

[Bobby Strain]

Huleswapnil,

 

The statement makes no sense.

 

Bobby

Edited by Bobby Strain, 06 September 2017 - 02:25 PM.

[VeryProfessionalEngineer]

The statement makes no sense.

 

Bobby

I'm imagining something like the vane pack device on the bottom of page 7 of this Sulzer brochure: https://www.sulzer.c..._Technology.pdf

 

Even then though, I would expect the dP to be through the vane, not through the chimney. For what I said to make sense you would have to have the dP for the gas to escape the chimneys be higher than the static head in that downcomer, but that would seem like a stretch. If we had a drawing of the internal arrangement perhaps the statement would make more sense.