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Desalter Mass Balance

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#1 iOM


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Posted 21 September 2020 - 05:05 PM

Greetings dears,

i have went through on below link and read all valuable replies there in addition to Oilfieled processing Vol. 2

However i still didn’t get why the salt content after dilution and mixing is the same as the content leaving the oil stream (Kb = Kc) while we still do have the salt in the reject brine?
overall MB, B = C + V
Salt MB, B Kb = C Kc + V Kv

I know that we are diluting with fresh water increasing water droplets population within the stream thus with electrostatic grids aid to decrease the BS&W and salt content in the oil stream to the desired spec. and Z (lb salt/1000 bbl) = B (bbl brine / bbl crude) * Kb (lb salt/bbl brine)

I’m still confused with Kb = Kc.. I appreciate explaining this equality.

#2 breizh


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Posted 21 September 2020 - 08:34 PM


Consider the resource attached with examples, extract from Oilfield processing -volume 2 crude oil by Francis S  Manning and Richard E Thompson .

You should also consider your favorite search engine for more information.


Good luck.


#3 bikashmallick


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Posted 05 October 2021 - 04:43 AM

As pointed out by iOM, I could not make out why Kb = Kc and this is very much important to understand because all material balance equation for salt is based on this. 


So It will be extremely helpful, if this equality is explained. 

#4 breizh


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Posted 07 October 2021 - 10:44 PM


The attachment with BM .


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