Jump to content



Featured Articles

Check out the latest featured articles.

File Library

Check out the latest downloads available in the File Library.

New Article

Product Viscosity vs. Shear

Featured File

Vertical Tank Selection

New Blog Entry

Low Flow in Pipes- posted in Ankur's blog

0

Multithreading App With Python And Prode Properties

python prode fluid properties multithreading parallel

3 replies to this topic
Share this topic:
| More

#1 Alpe

Alpe

    Junior Member

  • Members
  • 11 posts

Posted 13 June 2021 - 02:01 AM

I read that both Python and Prode Properties library support multithreading,

I wrote a Python procedure which adopts heuristic optimization methods and takes much time to complete,

how can I run multiple threads in parallel with Python and Prode ?

Can you provide an example ?



#2 PaoloPemi

PaoloPemi

    Gold Member

  • Members
  • 549 posts

Posted 13 June 2021 - 02:43 AM

Hi Alpe,

I confirm (see below the examples) that you can run multiple tasks in parallel with Prode and Python ,

for multithreading in Python you can import threading library while Prode doesn't require any specific settings,

you would need a multicore cpu , my cpu has four cores and I can execute my apps about four times faster with multithreading.

Another possibility is to execute on a cloud, some providers offer multicore cpus at reasonable prices, you can install Prode on a Linux server, see these examples

 

https://www.prode.co...gramcompare.php

https://www.prode.co...ies/hydrate.php

 

herebelow the examples of Python and Prode Properties running in single and multiple threads,  reported results are for a Intel i7 3740QM cpu (four cores)

 

results in Python 3.8 (64-bit) console

>>> exec(open("hydrateST.py").read())
Total time (seconds) -> 0.16275644302368164
245.0   K   214036.75   Pa.a
250.0   K   297396.875   Pa.a
255.0   K   402031.21875   Pa.a
260.0   K   533987.5   Pa.a
265.0   K   653298.9375   Pa.a
270.0   K   760583.0   Pa.a
275.0   K   1075351.875   Pa.a
280.0   K   1814863.25   Pa.a
285.0   K   3070172.75   Pa.a
290.0   K   5376445.5   Pa.a
>>> exec(open("hydrateMT.py").read())
Total time (seconds) -> 0.04987978935241699
245.0   K   214036.75   Pa.a
250.0   K   297396.875   Pa.a
255.0   K   402031.21875   Pa.a
260.0   K   533987.5   Pa.a
265.0   K   653298.9375   Pa.a
270.0   K   760583.0   Pa.a
275.0   K   1075351.875   Pa.a
280.0   K   1814863.25   Pa.a
285.0   K   3070172.75   Pa.a
290.0   K   5376445.5   Pa.a

 

first example, single thread

 

# single thread example
# hydrate formation conditions
# calculated with Prode Properties

import time
import prode
from array import array

# global vars
pt = array('f',[0,0,0,0,0,0,0,0,0,0,0])
pp = array('f',[0,0,0,0,0,0,0,0,0,0,0])
stream = 1

# define a function to calculate hydrate formation conditions
def hydform(i1,t):
    # convert t (unit K) to user unit    
    tt = prode.umcr(t,17,1)
    pt[i1] = tt
    # call Prode Properties to calculate hydrate pressure
    # mode 2 instructs Prode to evaluate only structures I (as in original work)
    pp[i1] = prode.hydp(stream,tt,2)

# for a few formers, obtain internal codes from CAS numbers (or chemical formula, names etc.)
C1 = prode.idc(74828)
C2 = prode.idc(74840)
C3 = prode.idc(74986)
IC4= prode.idc(75285)
NC4= prode.idc(106978)  
H2S= prode.idc(7783064)
N2 = prode.idc(7727379)  
CO2= prode.idc(124389)
H2O= prode.idc(7732185)

# define a stream with hydrate formers plus water
prode.inits(stream)
prode.putsm(stream,1,0,115) # fugacity, vapor phase, PRCPANHV model
prode.putsm(stream,1,1,115) # fugacity, liquid phase, PRCPANHV model
prode.putsm(stream,1,2,151) # fugacity, solid phase, SPRCPANHV model
prode.putsm(stream,1,3,170) # fugacity, hydrate phase, HPRCPANHV model
prode.putscc(stream,1,C1)   # mixture evaluated by Robinson, 1966
prode.putsz(stream,1,0.808)
prode.putscc(stream,2,CO2)
prode.putsz(stream,2,0.13)
prode.putscc(stream,3,H2S)
prode.putsz(stream,3,0.06)
prode.putscc(stream,4,H2O)
prode.putsz(stream,4,0.06)
prode.sets(stream)
prode.loadsb(stream,3) # load BIPs for hydrate models

# call hydform ten times in range 245 K to 290 K
start = time.time()
hydform(1,245.0)
hydform(2,250.0)
hydform(3,255.0)
hydform(4,260.0)
hydform(5,265.0)
hydform(6,270.0)
hydform(7,275.0)
hydform(8,280.0)
hydform(9,285.0)
hydform(10,290.0)
end = time.time()

print('Total time (seconds) ->',end-start,'\r')
for i in range(1,11):
    print(pt[i],' ',prode.sums(17),' ',pp[i],' ',prode.sums(15),'\r')

 

second example multithreading

 

# multi threaded example
# hydrate formation conditions
# calculated with Prode Properties

import time
import prode
import threading
from array import array

# global vars
pt = array('f',[0,0,0,0,0,0,0,0,0,0,0])
pp = array('f',[0,0,0,0,0,0,0,0,0,0,0])
stream = 1

# define a function to calculate hydrate formation conditions
def hydform(i1,t):
    # convert t (unit K) to user unit    
    tt = prode.umcr(t,17,1)
    # call Prode Properties to calculate hydrate pressure
    # mode 2 instructs Prode to evaluate only structures I (as in original work)
    p = prode.hydp(stream,tt,2)
    llock = threading.Lock()
    llock.acquire()
    pt[i1] = tt
    pp[i1] = p
    llock.release()

# for a few formers, obtain internal codes from CAS numbers (or chemical formula, names etc.)
C1 = prode.idc(74828)
C2 = prode.idc(74840)
C3 = prode.idc(74986)
IC4= prode.idc(75285)
NC4= prode.idc(106978)  
H2S= prode.idc(7783064)
N2 = prode.idc(7727379)  
CO2= prode.idc(124389)
H2O= prode.idc(7732185)

# define a stream with hydrate formers plus water
prode.inits(stream)
prode.putsm(stream,1,0,115) # fugacity, vapor phase, PRCPANHV model
prode.putsm(stream,1,1,115) # fugacity, liquid phase, PRCPANHV model
prode.putsm(stream,1,2,151) # fugacity, solid phase, SPRCPANHV model
prode.putsm(stream,1,3,170) # fugacity, hydrate phase, HPRCPANHV model
prode.putscc(stream,1,C1)   # mixture evaluated by Robinson, 1966
prode.putsz(stream,1,0.808)
prode.putscc(stream,2,CO2)
prode.putsz(stream,2,0.13)
prode.putscc(stream,3,H2S)
prode.putsz(stream,3,0.06)
prode.putscc(stream,4,H2O)
prode.putsz(stream,4,0.06)
prode.sets(stream)
prode.loadsb(stream,3) # load BIPs for hydrate models

# run 10 indipendent threads to calculate 10 points
# ranging from 245 K to 290 K
t1 = threading.Thread(target=hydform, args=(1,245.0))
t2 = threading.Thread(target=hydform, args=(2,250.0))
t3 = threading.Thread(target=hydform, args=(3,255.0))
t4 = threading.Thread(target=hydform, args=(4,260.0))
t5 = threading.Thread(target=hydform, args=(5,265.0))
t6 = threading.Thread(target=hydform, args=(6,270.0))
t7 = threading.Thread(target=hydform, args=(7,275.0))
t8 = threading.Thread(target=hydform, args=(8,280.0))
t9 = threading.Thread(target=hydform, args=(9,285.0))
t10= threading.Thread(target=hydform, args=(10,290.0))

start = time.time()
t1.start()
t2.start()
t3.start()
t4.start()
t5.start()
t6.start()
t7.start()
t8.start()
t9.start()
t10.start()

t1.join()
t2.join()
t3.join()
t4.join()
t5.join()
t6.join()
t7.join()
t8.join()
t9.join()
t10.join()

end = time.time()

print('Total time (seconds) ->',end-start,'\r')
for i in range(1,11):
    print(pt[i],' ',prode.sums(17),' ',pp[i],' ',prode.sums(15),'\r')



 



#3 Alpe

Alpe

    Junior Member

  • Members
  • 11 posts

Posted 13 June 2021 - 02:46 AM

thanks, I'll test your code



#4 mgerian

mgerian

    Brand New Member

  • Members
  • 6 posts

Posted 14 June 2021 - 12:11 AM

thanks for the links to free online calc's Paolo !

I have found these pages very useful !






Similar Topics