Does anyone knows the heat of solution of methanol in water or where i can get the info. It is not in the PERRY.
I'm working on a waste gas scrubber for methanol vapours so i need to know the amount of heat evolved/absorbed when methanol goes into solution.
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Methanol In Water
Started by anilde2010, Mar 30 2008 09:21 AM
3 replies to this topic
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#1
Posted 30 March 2008 - 09:21 AM
#2
Posted 10 April 2008 - 08:16 PM
QUOTE (anilde2010 @ Mar 30 2008, 10:21 PM) <{POST_SNAPBACK}>
Does anyone knows the heat of solution of methanol in water or where i can get the info. It is not in the PERRY.
I'm working on a waste gas scrubber for methanol vapours so i need to know the amount of heat evolved/absorbed when methanol goes into solution.
I'm working on a waste gas scrubber for methanol vapours so i need to know the amount of heat evolved/absorbed when methanol goes into solution.
I think it is hard to find table or graphy that can direct check on the "heat of solution" by simply of concentration and temperature.
But i think you can roughly calculated it by sum up the ethalphy of water (Perry's steam table) and methonal (perry or Yaw's) and then minus the heat of mixing (Perry or Yaw's , i cannot remember).
#3
Posted 18 April 2008 - 07:20 AM
But i think you can roughly calculated it by sum up the ethalphy of water (Perry's steam table) and methonal (perry or Yaw's) and then minus the heat of mixing (Perry or Yaw's , i cannot remember).
I do not know the answer for the question stated in this thread, but I am fully convinced that the above formula proposed by Drow is not correct. The process is the absorption of vapour (gas) and not mixing of two liquids...
It can probably be: heat of adsorption = heat of mixing - heat of vaporization (= condensation in this case), but I am not quite sure of this...
I do not know the answer for the question stated in this thread, but I am fully convinced that the above formula proposed by Drow is not correct. The process is the absorption of vapour (gas) and not mixing of two liquids...
It can probably be: heat of adsorption = heat of mixing - heat of vaporization (= condensation in this case), but I am not quite sure of this...
#4
Posted 18 April 2008 - 07:30 AM
I meant absorption not adsorption - sorry for this awful mistake...
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