Dear colleague:
1-Due to limited capacity of flare system we have to sequentially depressurize gas trains and also some other units through flare system.
Max capacity of each gas train/other units and flare tip capacity is available.
Could U advise me regarding procedure for this calculation?
2- if there is a vessel with specified V, p1&T1 which contain compressible gas fluid, if it starts depressurizing to p2. Is it possible to calculate outlet flow rate during depressurizing? How?
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Depressurizing
Started by mohammadhosseinzadeh, Sep 09 2008 04:26 AM
6 replies to this topic
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#1
Posted 09 September 2008 - 04:26 AM
#2
Posted 10 September 2008 - 08:22 AM
There is a nice article that contains all info you need and more, "How to predict temperatures during gas depressuring", by G. Montgomery, Hydrocarbon Processing, April 1995, p. 85-88.
It is all pretty straightforward, using gas law, heat transfer equations, mass balance considerations, and valve flow equations. I am sure you could even figure it out by yourself.
It is all pretty straightforward, using gas law, heat transfer equations, mass balance considerations, and valve flow equations. I am sure you could even figure it out by yourself.
#3
Posted 11 September 2008 - 03:37 AM
It is quit possible with fundamental equations:
But you have to give on more variable that is crossetional area (A)of piping to depressurisation.
Loss in pressure energy during depressurusation = Kinetic energy of gas releiving with certain velocity.
Allowable Velocity can be calculated by limiting mach no 0.3 to 0.4.
Q (m3/h) X (p1-p2) =1/2 m v2
substitute value Q = v x A
=> m =2*(p1-p2)*A/v (kg/hr)
Calculatiom of v.
V sonic =(KT/Mw)^.5
V allovable = 0.4*v sonic
Formulae to be checked from any text for unit consistancy
Regards
Shahnawaz
But you have to give on more variable that is crossetional area (A)of piping to depressurisation.
Loss in pressure energy during depressurusation = Kinetic energy of gas releiving with certain velocity.
Allowable Velocity can be calculated by limiting mach no 0.3 to 0.4.
Q (m3/h) X (p1-p2) =1/2 m v2
substitute value Q = v x A
=> m =2*(p1-p2)*A/v (kg/hr)
Calculatiom of v.
V sonic =(KT/Mw)^.5
V allovable = 0.4*v sonic
Formulae to be checked from any text for unit consistancy
Regards
Shahnawaz
#4
Posted 11 September 2008 - 12:58 PM
Mohammad:
I suggest that you read this article:
http://en.citizendium.org/wiki/Accidental_release_source_terms
It provides the the correct equations for use in the choked flow and the non-choked flow of gases for use in accidental gas releases or in routine depressurization of gas-filled vessels or pipes.
Milt Beychok
I suggest that you read this article:
http://en.citizendium.org/wiki/Accidental_release_source_terms
It provides the the correct equations for use in the choked flow and the non-choked flow of gases for use in accidental gas releases or in routine depressurization of gas-filled vessels or pipes.
Milt Beychok
#5
Posted 14 September 2008 - 01:29 AM
thanks all for useful information
joerd:
could you please send me this article:
How to predict temperatures during gas depressuring", by G. Montgomery, Hydrocarbon Processing, April 1995, p. 85-88.
Email:m.hosseinzadeh.78@gmail.com
joerd:
could you please send me this article:
How to predict temperatures during gas depressuring", by G. Montgomery, Hydrocarbon Processing, April 1995, p. 85-88.
Email:m.hosseinzadeh.78@gmail.com
#6
Posted 15 September 2008 - 08:41 AM
Sorry, it is copyrighted. You can request it at http://www.hydrocarb.../hp-photos.html
or give it a try at your local university library. Good luck,
or give it a try at your local university library. Good luck,
#7
Posted 07 December 2008 - 04:35 AM
QUOTE (MAKROO @ Sep 11 2008, 03:37 AM) <{POST_SNAPBACK}>
It is quit possible with fundamental equations:
But you have to give on more variable that is crossetional area (A)of piping to depressurisation.
Loss in pressure energy during depressurusation = Kinetic energy of gas releiving with certain velocity.
Allowable Velocity can be calculated by limiting mach no 0.3 to 0.4.
Q (m3/h) X (p1-p2) =1/2 m v2
substitute value Q = v x A
=> m =2*(p1-p2)*A/v (kg/hr)
Calculatiom of v.
V sonic =(KT/Mw)^.5
V allovable = 0.4*v sonic
Dear mr shahnawaz ,plz explain teh meaing of KT you used in above equation for Vsonic..,r they soem contants ..if yes then plz give there vaules.
Formulae to be checked from any text for unit consistancy
Regards
Shahnawaz
But you have to give on more variable that is crossetional area (A)of piping to depressurisation.
Loss in pressure energy during depressurusation = Kinetic energy of gas releiving with certain velocity.
Allowable Velocity can be calculated by limiting mach no 0.3 to 0.4.
Q (m3/h) X (p1-p2) =1/2 m v2
substitute value Q = v x A
=> m =2*(p1-p2)*A/v (kg/hr)
Calculatiom of v.
V sonic =(KT/Mw)^.5
V allovable = 0.4*v sonic
Dear mr shahnawaz ,plz explain teh meaing of KT you used in above equation for Vsonic..,r they soem contants ..if yes then plz give there vaules.
Formulae to be checked from any text for unit consistancy
Regards
Shahnawaz
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