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Steam Conversion
#1
Guest_RicardoT_*
Posted 24 September 2009 - 05:16 AM
I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)
1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr
Using gas law: P1*V1/T1=P2*V2/T2
V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions
Thank you
#2
Posted 24 September 2009 - 07:30 AM
There is no steam at 1 atm and 0 C. It is icy water! P1*V1/T1=P2*V2/T2 is applicable to ideal gas not to water or steam. If you want have a better score than “Fail”, please don’t hand in your homework yet.Can someone help me to check if my calculations are correct?
I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)
1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr
Using gas law: P1*V1/T1=P2*V2/T2
V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions
Thank you
#3
Guest_RicardoT_*
Posted 24 September 2009 - 08:17 AM
So how can i corvert steam or when they say 3 UK Ton/hr is already in process conditions?There is no steam at 1 atm and 0 C. It is icy water! P1*V1/T1=P2*V2/T2 is applicable to ideal gas not to water or steam. If you want have a better score than “Fail”, please don’t hand in your homework yet.
Can someone help me to check if my calculations are correct?
I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)
1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr
Using gas law: P1*V1/T1=P2*V2/T2
V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions
Thank you
#4
Posted 24 September 2009 - 08:44 AM
First, you should find the Steam Density at 16.5 atm and 275 C from a steam table or a steam chart. Then, (3 UK Ton/hr) / Steam Density (UK Ton/M3) = ?? M3/Hr.So how can i corvert steam or when they say 3 UK Ton/hr is already in process conditions?
There is no steam at 1 atm and 0 C. It is icy water! P1*V1/T1=P2*V2/T2 is applicable to ideal gas not to water or steam. If you want have a better score than “Fail”, please don’t hand in your homework yet.
Can someone help me to check if my calculations are correct?
I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)
1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr
Using gas law: P1*V1/T1=P2*V2/T2
V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions
Thank you
Now, if you get 100 score from the question, you shall, at least, share me 90.
#5
Guest_RicardoT_*
Posted 24 September 2009 - 11:52 AM
OK. Thank you for helping me.First, you should find the Steam Density at 16.5 atm and 275 C from a steam table or a steam chart. Then, (3 UK Ton/hr) / Steam Density (UK Ton/M3) = ?? M3/Hr.
So how can i corvert steam or when they say 3 UK Ton/hr is already in process conditions?
There is no steam at 1 atm and 0 C. It is icy water! P1*V1/T1=P2*V2/T2 is applicable to ideal gas not to water or steam. If you want have a better score than “Fail”, please don’t hand in your homework yet.
Can someone help me to check if my calculations are correct?
I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)
1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr
Using gas law: P1*V1/T1=P2*V2/T2
V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions
Thank you
Now, if you get 100 score from the question, you shall, at least, share me 90.
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