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Steam Conversion


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#1 Guest_RicardoT_*

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Posted 24 September 2009 - 05:16 AM

Can someone help me to check if my calculations are correct?

I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)

1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr

Using gas law: P1*V1/T1=P2*V2/T2

V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions

Thank you

#2 shan

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Posted 24 September 2009 - 07:30 AM

Can someone help me to check if my calculations are correct?

I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)

1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr

Using gas law: P1*V1/T1=P2*V2/T2

V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions

Thank you

There is no steam at 1 atm and 0 C. It is icy water! P1*V1/T1=P2*V2/T2 is applicable to ideal gas not to water or steam. If you want have a better score than “Fail”, please don’t hand in your homework yet.

#3 Guest_RicardoT_*

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Posted 24 September 2009 - 08:17 AM


Can someone help me to check if my calculations are correct?

I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)

1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr

Using gas law: P1*V1/T1=P2*V2/T2

V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions

Thank you

There is no steam at 1 atm and 0 C. It is icy water! P1*V1/T1=P2*V2/T2 is applicable to ideal gas not to water or steam. If you want have a better score than “Fail”, please don’t hand in your homework yet.

So how can i corvert steam or when they say 3 UK Ton/hr is already in process conditions?

#4 shan

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  • 692 posts

Posted 24 September 2009 - 08:44 AM



Can someone help me to check if my calculations are correct?

I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)

1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr

Using gas law: P1*V1/T1=P2*V2/T2

V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions

Thank you

There is no steam at 1 atm and 0 C. It is icy water! P1*V1/T1=P2*V2/T2 is applicable to ideal gas not to water or steam. If you want have a better score than “Fail”, please don’t hand in your homework yet.

So how can i corvert steam or when they say 3 UK Ton/hr is already in process conditions?

First, you should find the Steam Density at 16.5 atm and 275 C from a steam table or a steam chart. Then, (3 UK Ton/hr) / Steam Density (UK Ton/M3) = ?? M3/Hr.

Now, if you get 100 score from the question, you shall, at least, share me 90.

#5 Guest_RicardoT_*

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Posted 24 September 2009 - 11:52 AM




Can someone help me to check if my calculations are correct?

I have a flow of steam 3 UK Ton/hr in (1 atm and 0°C) and i whant in m3/h (16,5 atm and 275 ºC)

1 UK Ton/hr of water is 1,02 m3/hr so 3 UK Ton/hr is 3,06 m3/hr

Using gas law: P1*V1/T1=P2*V2/T2

V2= (V1*P1*T2)/(P2*T1)
V2= (3,06*1*(275+273))/(16,5*273)
V2= 0,365474525 m3/hr in process conditions

Thank you

There is no steam at 1 atm and 0 C. It is icy water! P1*V1/T1=P2*V2/T2 is applicable to ideal gas not to water or steam. If you want have a better score than “Fail”, please don’t hand in your homework yet.

So how can i corvert steam or when they say 3 UK Ton/hr is already in process conditions?

First, you should find the Steam Density at 16.5 atm and 275 C from a steam table or a steam chart. Then, (3 UK Ton/hr) / Steam Density (UK Ton/M3) = ?? M3/Hr.

Now, if you get 100 score from the question, you shall, at least, share me 90.

OK. Thank you for helping me.




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