7 replies to this topic

[breizh]

Good day ,
I would appreciate direction to calculate the volume of liquid inside a "vertical" tank slightly tilted due to soil sinking .( Known are the geometry of the tank: L, D ; the slope ; the reference point (nozzle) to measure the height of liquid).

Breizh

[katmar]

Breizh, there was a time in the dim and distant past when my mathematical skills were sharp enough that I would have tried to solve that problem analytically. Now, I would rent a calibrated flow meter and generate a calibration chart by filling the tank slowly while taking readings from the level gauge.

[riven]

A college sent me this see if it makes sense. Mathematically it is quite complex.

http://www.lmnoeng.c...InclinedCyl.htm

[breizh]

Thanks for your input .
Breizh

[kkala]

I would appreciate direction to calculate the volume of liquid inside a "vertical" tank slightly tilted due to soil sinking .( Known are the geometry of the tank: L, D ; the slope ; the reference point (nozzle) to measure the height of liquid).

Attached "tilted.pdf" may help, giving a simplified formula for the volumes above ground and below ground. It is noted that e.g. Lcosθ=Η for above ground cylinder (θ=angle of the axis to perpendicular).
In case that tank bottom is seriously distorted, another method has to be applied for the volume below ground (or any definite horizontal level), as the calibration proposed by Katmar.
Can you inform order of magnitude for angle θ or slope? Probably θ is very close to zero, otherwise tank would have to be dismantled.

Attached Files

•  tilted.PDF   25.53KB   34 downloads

Edited by kkala, 08 March 2010 - 09:32 AM.

[breizh]

I would appreciate direction to calculate the volume of liquid inside a "vertical" tank slightly tilted due to soil sinking .( Known are the geometry of the tank: L, D ; the slope ; the reference point (nozzle) to measure the height of liquid).

Attached "tilted.pdf" may help, giving a simplified formula for the volumes above ground and below ground. It is noted that e.g. Lcosθ=Η for above ground cylinder (θ=angle of the axis to perpendicular).
In case that tank bottom is seriously distorted, another method has to be applied for the volume below ground (or any definite horizontal level), as the calibration proposed by Katmar.
Can you inform order of magnitude for angle θ or slope? Probably θ is very close to zero, otherwise tank would have to be dismantled.

Thanks Kostas ,
For your question : the slope : 7 centimeters for 7 meters height
Breizh

[kkala]

the slope : 7 centimeters for 7 meters height

Thus tanθ=0.01, θ=0.573 degrees, H=l*cosθ=0.99995l. Even if l=30 m, H=29.9985 m; so difference between l and H can be hardly distinguished; neglecting such slope may affect volumetry precision quite marginally.
Distortions may play a greater role.

Edited by kkala, 09 March 2010 - 11:36 AM.

[breizh]

the slope : 7 centimeters for 7 meters height

Thus tanθ=0.01, θ=0.573 degrees, H=l*cosθ=0.99995l. Even if l=30 m, H=29.9985 m; so difference between l and H can be hardly distinguished; neglecting such slope may affect volumetry precision quite marginally.
Distortions may play a greater role.

Kostas ,
The quantity of material is strictly monitored by "authorities"!
Thanks again .
Breizh