chemeng2016
As you may know , in such piping network , according to the energy (Bernoulli) equation, we have below pressure drop terms :
- Pressure drop (Delta P)
- Pressure drop due to elevation change(Delta Z)
- Pressure drop due to acceleration of fluid
Now , you should note that what your Press Indicator/Gauge shows is the Hydraulic or Static Pressure (i.e. P+Z) which is sum of the Pressure term and gravity term.
Moreover , in compliance with any Fluid Mechanic book, total head loss or hf equals to this Hydraulic Pressure drop (Z+P).
Now the question is whether or not, you have a parallel pipeline network. I mean, whether your three lines will be eventually connected together again (to the same header , for instance in a cooling water network , wherein there are many parallel piping system). If so ,for each pipe junction or ‘‘node’’ in the parallel pipelines, continuity tells us that the sum of all the flow rates into the node must equal the sum of all the flow rates out of the node. So ,
Q=Q1+Q2+Q3
Also, the total head loss (pressure drop plus Elevation head loss or P+Z) between the two nodes , equals to the total head loss of either individual pipe in parallel lines.
I think that your case might not be a parallel piping network and so for this case , if I were you , I would do the following:
-first measure in practice the static pressure drop for either pipe (P2-Pjunction) and then calculate the hf. Next , you can calculate hf , theoretically by Darcy equation as said by Mahdi1980 , for either pipe but remember that if there is any fitting head losses , you have to incorporate them into Darcy equation (hf=(fl/d+SIGMA K) *v2/2/g). Then the calculated hf is expected to be equal to the measured hf.
Edited by Araboni, 19 April 2016 - 05:35 AM.