Hi there newsgroup,
I have a simple problem that involves converting an HHV value that I have of a wet solid fuel into LHV.
My fuel has moisture in it to begin with and has a dry HHV of 8376 Btu/lb (oven dry) and a wet HHV of 4607.017449 (55% moisture).
I did a bit of reading and I learned I could convert HHV to LHV using this equation:
LHV = HHV - (mH2O/mfuel) * latent heat of vap for H2O at 25C
The first problem is that I don't know if mH2O is only the moisture generated during the combustion, or is it both the generated water and the moisture in the fuel to begin with?
The second is that mfuel in the equation was just defined as "mass of fuel", should this be mass of wet fuel (the entire fuel), or mass of the fuel excluding water?
The third is that I don't know if this equation works if I use the wet HHV as opposed to the dry one, although intuition tells me it will.
Thanks guys.
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Simple Hhv/lhv Conversion
Started by Guest_Shen_*, May 31 2010 09:16 PM
1 reply to this topic
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#1
Guest_Shen_*
Posted 31 May 2010 - 09:16 PM
#2
Posted 31 May 2010 - 11:26 PM
Hi Shen,
This link should support your query:
http://hydrogen.pnl....?canprint=false
Hope these helps
Breizh
This link should support your query:
http://hydrogen.pnl....?canprint=false
Hope these helps
Breizh
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