1 reply to this topic

[JunCheng]

Hi,

Anyone familiar with Fischer Tropsch synthesis (FTS)? In usual case, we would remove CO2 before entering FT reactor. Read an article regarding mixing large amount of CO2 into regular FT feed (CO+H2) would maximize FTS hydrocarbon product, but more selectivity towards methane and shorter carbon chain. Yet, the conversion of CO2 is very low (around 13% or lower), implies that there will be remaining CO2 in the hydrocarbon product stream.

Question is:
1) Will this remaining CO2 affect the fractionation process later?
2) If not, how should it be removed or settled? Seems illogical to remove it after hydrocarbon forms using conventional methanol.

Appreciate your advice.
Thanks.

[sundutt]

for FT reaction only H2:CO ratio is important based on which process you have low temperature FT ot high temperature FT, the unreacted co2 is again recycled back to autothermal reforming section as recycle gas there it will take part with reforming & water shift reaction.
FTproducts are straight chain paraffin hydrocarbons like wax & hydrocarbon condensate, these are feed to fractionator, so no ned to worry about this CO2 to fractionator.
OFF GAS( unconverted gas from reactor can be further treated for C3-C4 recovery( mostly LPG, dry condensate, wet condensate) and lean gas can be used as fuel gas.

further any info you want you can mail me santosh_khopade@rediff.com

Hi,

Anyone familiar with Fischer Tropsch synthesis (FTS)? In usual case, we would remove CO2 before entering FT reactor. Read an article regarding mixing large amount of CO2 into regular FT feed (CO+H2) would maximize FTS hydrocarbon product, but more selectivity towards methane and shorter carbon chain. Yet, the conversion of CO2 is very low (around 13% or lower), implies that there will be remaining CO2 in the hydrocarbon product stream.

Question is:
1) Will this remaining CO2 affect the fractionation process later?
2) If not, how should it be removed or settled? Seems illogical to remove it after hydrocarbon forms using conventional methanol.

Appreciate your advice.
Thanks.