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#1 Humongousfungus


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Posted 14 May 2013 - 07:26 AM

Hi guys, I'm revising for exams and I have this tutourial question where the answer is (1m) I cant seem to get that answer by quite a large margin.

Q) For the arrangement shown in figure 2 determine the difference in fluid levels, Y,
in the two tanks. The oil has a specific gravity of 0.87. (1.0 m)




Thanks for the help.

#2 breizh


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Posted 16 May 2013 - 02:16 AM

Static problem : 


Pressure both legs are equal /reference interface oil/ mercury .


Pair reservoir +Ro water *g*Hwater +Ro hg*g*Hhg = Patm +Ro oil*g*( Hwater +Hhg-Y)

H water :6m

H hg :0.15m 

g= 9.81 SI unit

1 KN/m2 =1000 Pa 

Pat =1e5 Pa


Do the math and it should work .


Edited by breizh, 16 May 2013 - 02:50 AM.

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