Hello.
I am working on Thermal design of Liquid to Liquid heater for Intermediate Fuel Oil (IFO 380). Below is the data:
1. Hex type: Shell and tube
2. Heat Load : 6200 kW
3. Shellside fluid: Heat transfer oil @ 600 m3/h(Density@105 deg. C=834.47 kg/m3, Cp=1992 J/kg.k, Th. Cond.=0.148 W/m.k, Kine. viscosity@105 deg. C=11.04 mm2/s)
4. Tubeside fluid: IFO 380 @ 750 m3/h (Density@15 deg. C=991 kg/m3, Cp=2000 J/kg.k, Th. Cond.=0.150 W/m.k, Kine. viscosity@50 deg. C=380 mm2/s)
My assumptions:
1. Tube: 31.75 OD x 2 thk x 4800 mm Long
2. Tubeside passes: 4
3. Tube layout: Square type with 39.69 pitch
4. Tube material: CS SA 178 ERW
5. Baffles: Segmental, transeverse
6. Overall U assumed : 300 W/m2.C
7. Calculated U : 308 W/m2.C
8. Area calculated: ~387 m2
But the problem is Pressure drops through shell and tubes:
Shellside Pressure drop with above configuration: 1.51 bar (This is too high, which should be below 0.7 bar)
Tubeside Pressure drop with above configuration: 2.4 bar (This is too high, which should be below 0.5 bar)
I have tried many combinations to deal with/ to olwer the pressure drops, But could not succeed.
I am a Mechanical Engineer with exp. of Pressure vessel and Heat exchanger design,
Since I am not an experienced process designer/Chemical engineer, I expect help on this forum.
an advice or suggestion to minimize the pressure drops are much appreciated.
Have attached excel sheet for thermal calculations.
I have referred: Chemical Engineering. Vol. 6, Chemical Engineering Design, 4th Ed by Coulson & Richardson
-Suresh Bhad

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