I've been working on this all week and asked around some other forums but I keep getting different answers and mixed results. I have three reactions occurring simultaneously.
CH4 + H2O --> CO + 3H2
CO + H20 <--> CO2 + H2
CH4 + 2H2O <--> CO2 + 4H2
My lecturer and I have assumed the first reaction has a CH4 conversion of 95% with the flow rate of both the CH4 and H2O being 134.4753 mol/s. If I have the 95% conversion, I am wondering how much H2O would be provided to each of the other two steps; that is assuming the other 5% of the CH4 is going to the other steps.
I basically have conducted calculations to find the reaction rate of each step for varying CH4 conversions from 0.99 to 1*10^-10 (assumed to be 0). I have then fixed the conversion of the third step to a set value and then used the left over H2O from the third in the second assuming it is fully used up. I then used Euler's approach to find the Weight Catalyst according to the equations in the literature. This allowed me to find the weight of catalyst for the CH4 conversion and then the CO2 conversion. I then had to make the weight of catalyst equal for the XCH4 at 0.95 conversion and then for XCO2 conversion at 0.05 assuming that the rest of the CH4 is converted to CO2 in the 2nd and 3rd steps. Are my assumptions correct and is the correct methodology as I have been working on this for at least three weeks now and have felt that I have regressed? I have attached my excel spreadsheet below (labelled under Calculation of Catalyst Weight)
Also how would I calculate the reactor diameter as for the mean voidage calculations I need to determine the tube diameter.
Edited by JArchy123, 26 December 2021 - 06:17 PM.