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Batch And Cstr Reactor Problems


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#1 mahdi1988

mahdi1988

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Posted 24 May 2009 - 03:03 AM

Hello ,


I'm new one here in this forums .. And I hope that you can help me ... !

Now I'm Studying Reaction Kintecs And Reactors Course ... !

Me Dr Gave me two problems to solve ... each problem = 10 points

so I need help to increase my grade by solving them ... !

I Will write the problems here ... and anyone can help me ... that will be vert nice ... !

I should submit the solution in 26 of may ... !

-----

Problem -1-

Batch Reactor *

A constant volume batch reactor was operated at 10 ˚C. The following data were found at different intervals of time for the gas with reaction :-







Using the above data , determine

-a- the rate constant .
-b- the rate expression for this reaction

Hint , promgo's law

PV=nRT

Concentration Ca = PV/RT = n/V

(-Ra)=KPa^n = -dPa/dt


---------------

Problem -2-

CSTR Reactor

A Reaction with stoichiometry



is be carried out in a single CSTR .

What size of reactor is needed for 75% conversion of a feed stream of 1200 mole A / hr

At 1.2 moles/liter . Take K=15 hr^-1

----


Please help me ... I need those 20 points ... !

Anyone can help .. I Can do him a faivor ... !

Thanks all

I'm Waiting ... !

Mahdi










#2 clarenceyue

clarenceyue

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Posted 24 May 2009 - 09:11 AM

I'm sorry, but no one will help you here. You need to sit down read and understand your notes to do these homework problems yourself.

Don't for one minute, think you can step in here and expect people to do your homework for you, because that isn't going to happen.

#3 mahdi1988

mahdi1988

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Posted 24 May 2009 - 09:28 PM

QUOTE (clarenceyue @ May 24 2009, 09:11 AM) <{POST_SNAPBACK}>
I'm sorry, but no one will help you here. You need to sit down read and understand your notes to do these homework problems yourself.

Don't for one minute, think you can step in here and expect people to do your homework for you, because that isn't going to happen.


Hi , thanks for replaying here ... I Know no one will wolve my homework for me .. but we never take partial pressure ... !

but thanks all





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