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#1 Ebrahim

Ebrahim

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Posted 12 February 2006 - 11:15 AM

Dear all

As we know, liquid and vapor mixtures at equilibrium are at same temperature and pressure throughout. we know that in T-X-Y diagrams (at constant pressure), in horizontal tie lines (constant temperature) a point that is not saturated liquid (point A) or vapor (point B) is a two phase-mixture, consisting of a liquid and vapor of A and B composition.

1. At this situation we have infinite pointes with same T, P, X , Y and same equilibrium conditions. What is the difference between these points?
2. Can anyone define a process that begins at A and at constant T, P, X, Y and without changing equilibrium condition receives B ?

Best Regards

Ebrahim

#2 abhi_agrawa

abhi_agrawa

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Posted 12 February 2006 - 10:17 PM

QUOTE
1. At this situation we have infinite pointes with same T, P, X , Y and same equilibrium conditions. What is the difference between these points?
For a binary mixture, the degree of freedom at a given Temperature and Pressure is 0. Therefore when you specify the T & P, the compositions of the two phases is fixed. Therefore, the feed may have any composition, it will split in two phases and the compositions of the two phases will be same. However, between two feeds of the different compositions but at the same T & P, the amount of the two phases will be different.

QUOTE
2. Can anyone define a process that begins at A and at constant T, P, X, Y and without changing equilibrium condition receives B ?


I don't think so.




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