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Ammonium Nitrate Stoichiometry


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#1 geo123

geo123

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Posted 12 July 2016 - 01:28 AM

I want to ask about Q3 part (a). I'm not sure if my answer is correct or not.

Working

Basis: 100 moles of aqueous nitric acid.

 

 

Ammonia and 22 mol% aqueous nitric acid have reacted completely.

 

NH3 + HNO3 ---> NH4NO3

1       :   1         :       1

22mol   22mol     22mol

 

(NH4NO3)in = (NH4NO3)out

(NH4NO3)out = 22 moles

 

My system boundary is around the evaporator and the crystallizer.

 

In the stream between the crystallizer and the dryer.

0.9y+0.1y*0.302=22 moles

0.9302y= 22 moles

y=23.65 moles

 

0.1*23.65 moles*(1-0.302)

=1.65 moles in the stream

 

Answer

[1.65/(1.65+22)]*100%=6.98mol% H2O

[22/(1.65+22)]*100%=93.02mol%NH4NO3

 

I want to know if my answer is right as I have not been given an answer for this part of the question.

 

 



#2 geo123

geo123

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Posted 12 July 2016 - 03:25 PM

Hi, I need your help. Is my answer correct or not? Your help will be greatly appreciated.


Edited by geo123, 12 July 2016 - 03:25 PM.





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