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[dwsv]

Hi,

I have to design a heat exchanger that evaporates Propane and condensates propylene but I tried using a kettle rebiller but the area required is so immense I'm very unsure it's correct.

 

m_propane = 25 kg/s

latent heat propane = h_propane_liquid - h_propane_vapour = 279.81 kJ/kg

U_ass = 200 W/m2C

T_m = | T_propane-T_propylene | = 7.7

 

A = (latent heat propane*m_propane)/(U_ass*T_m) = 4534 m2

 

Is this anywhere near correct?

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Edited by dwsv, 06 March 2017 - 05:42 PM.

[cea]

Dear dwsv,

 

As I understand, you are talking about reboiler on heat pump circuit, wherein both sides of exchanger are exchanging only latent heat. Primefacie, it appears that the U_ass is very less. This value is expected to be significantly high.