Hello,
I try to calculate and to understand the emergency venting according to NFPA 30.
First of all I am familiar with the calculation according to API 2000.
The NFPA 30 has this exceptions for tanks > 12000 gallons / 45m³. Unfortunately I don't find this exception in the API 2000. (Or did I miss it?)
That's why I intend to use the NFPA 30.
In chapter 22.7.3.3. of the NFPA it says: "The total emergency relief venting capacity for tanks and storage vessels designed to operate at pressures above a gauge pressure of 1.0 psi (6.9 kPa) shall be as follows:"
So what if I have a tank that is operated below the 6.9 kPa/ 69 mbar (or even with open vent)? I am not allowed to use the rest of this calculation?
Nevertheless I took the value from the table 22.7.3.2 and compared it to the API 2000. With the equation of 3.3.3.3.2 for required flow capacity q, in normal cubic meter per hour of air I calculate a similar value.
But...please explain me the equation 22.7.3.4 from the NFPA.
I use the value from the table (which is free air per hour) and divide by latent heat of vap (of any fluid) and the sqrt of it's molecular weight and at the end I have again free air per hour volume flow? I do not get the logic behind this equation and do not understand what is calculated by this.
Any help is appreciated
Thanks
Jon
Edited by Jon K, 10 February 2021 - 10:55 AM.