I'm having a hard time finding a data-source for acetaldehyde solubility in MEK (Methyl Ethyl Ketone). Anyone know? Any places I should look up?
Even an estimate will do. The pressure is 1 atm(abs) and Temp. is ~60 C.
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Posted 24 July 2013 - 05:27 AM
I'm having a hard time finding a data-source for acetaldehyde solubility in MEK (Methyl Ethyl Ketone). Anyone know? Any places I should look up?
Even an estimate will do. The pressure is 1 atm(abs) and Temp. is ~60 C.
Posted 27 July 2013 - 03:15 PM
You can go to NIST webbook & look up the Antoine coefficients for acetaldehyde & for MEK or use the plot feature to find the pure component vapor pressures (VP) at 60 deg C. Reading off plot, we have 273+60 = 333 K, 3.6 Bar VP for acetaldehyde (click + hold on plot to zoom in), and VP MEK = 0.515 bar. Atm pressure = 1.01325 bar (call it 1 Bar). So then you just solve the equation VP = Xa * VPa + (1-Xa)*VPMEK = 1 Bar, solving for X sub a, where Xa = mole fraction acetaldehyde & VPa = Vapor Pressure of Pure Acetaldehyde @ 60 deg C and VPMEK = vapor pressure of pure MEK at 60 deg C. You'll come up with mole fraction of 0.163 Acetaldehyde & 0.837 MEK. ChemCAD gives 0.166 & I wouldn't expect much deviation from non-ideality. This is typically described as the 'equilibrium' concentration instead of 'solubility'. The term solubility is typically used in describing aqueous streams or two phase mixtures, e.g. how much of a solid organic can dissolve in a liquid or how much salt water can hold at a given temperature. When you have more than two components I tend to prefer to use the simulators if available to you.
Posted 27 July 2013 - 11:28 PM
You can go to NIST webbook & look up the Antoine coefficients for acetaldehyde & for MEK or use the plot feature to find the pure component vapor pressures (VP) at 60 deg C. Reading off plot, we have 273+60 = 333 K, 3.6 Bar VP for acetaldehyde (click + hold on plot to zoom in), and VP MEK = 0.515 bar. Atm pressure = 1.01325 bar (call it 1 Bar). So then you just solve the equation VP = Xa * VPa + (1-Xa)*VPMEK = 1 Bar, solving for X sub a, where Xa = mole fraction acetaldehyde & VPa = Vapor Pressure of Pure Acetaldehyde @ 60 deg C and VPMEK = vapor pressure of pure MEK at 60 deg C. You'll come up with mole fraction of 0.163 Acetaldehyde & 0.837 MEK. ChemCAD gives 0.166 & I wouldn't expect much deviation from non-ideality. This is typically described as the 'equilibrium' concentration instead of 'solubility'. The term solubility is typically used in describing aqueous streams or two phase mixtures, e.g. how much of a solid organic can dissolve in a liquid or how much salt water can hold at a given temperature. When you have more than two components I tend to prefer to use the simulators if available to you.
Thanks a lot. Somehow this approach escaped me.
I was lost looking for solubility as something distinct from essentially a VLE calculation. Makes perfect sense.
Posted 27 July 2013 - 11:35 PM
Out of curiosity: Was there a reason you seemed confident non-ideality won't be an issue here?
The pressure being low fugacity is no worry. But what about non-unity activity coefficients?
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