We are designing a continuous fermenter which would grow bacteria with growth rate of 0.5 g/l/h . The maximum concentration we can have in the tank is 60 g/l of the bacteria in media. we need to produce at least 1100 kg/h of these bacteria. how can we calculate the volume of the bubble column reactor ?
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Fermenter Volume
#1
Posted 12 March 2018 - 11:56 PM
#2
Posted 13 March 2018 - 10:43 AM
you need to solve a differential equation based on bacteria mass balance and retention time. Media flow is constant.
bacteria concentration changes with time.
#3
Posted 13 March 2018 - 07:33 PM
Any sources that I can study about that ?
#4
Posted 13 March 2018 - 09:06 PM
60 g/l ---> means you are removing 18333 l/h (1100 kg/h divided by 0.06 kg/l)
Growth Rate: 0.5 g/l/h ----> For steady state you need to produce the same as you remove.
So you need: 1100 kg/h / 0.0005 kg/l/h. That is: 2200000 lts or 2200 m3
And 2200/18.333 gives you a retention time of 120 hours.
For a "bubble column" it looks big.
#5
Posted 13 March 2018 - 11:21 PM
yeah that's how we calculated it too and yes that's what we concluded that the reactor will be too big. Just wanted to make sure we are calculating it right. I don't know why our client keep saying we are wrong and the reactor should be much smaller :/
thanks for your help
#6
Posted 15 March 2018 - 07:05 AM
It is a accumulation not simply linear increasing.
Edited by rikakose, 15 March 2018 - 07:15 AM.
#7
Posted 15 March 2018 - 07:29 AM
mt(dt)=integral(0-t)(C0+S*dt)*F*dt
C0 initial concentration
S growth rate
F flow
mt bacteria mass
retention time is around 16 hours.
Edited by rikakose, 15 March 2018 - 07:51 AM.
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