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[harindra]

I am looking for someone to help me calculate the distance upto which a 119 T/hour of ethane-propane liquid mixture(75:25 weight) after injection into a 30" nominal diameter of 600# pipline having natural gas flow of 431 T/hr (Mol weight 20.2) shall fully evaporate or mix with the gas stream. The injection takes place at 90 Kg/cm2g and natural gas and C2/C3 liquid temperatures are 55 C & -5 C respectively.

 

It is known that if we mix the two stream as mentioned above, the final mixture is a gas however practically it needs some time to reach to that condition.

[Bobby Strain]

You need mixing elements of some kind to assure a uniform mixture. Check with vendors who supply static mixers. And, you fail to note that the ethane-propane mix is liquid at the conditions given. So you need to vaporize the liquid. Unless, if it is true that the resultant mix is a vapor, then you need to inject small quantites through many points. Doesn't seem too practical.

 

Bobby